| Index: fusl/src/math/sqrt.c
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| diff --git a/fusl/src/math/sqrt.c b/fusl/src/math/sqrt.c
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| new file mode 100644
|
| index 0000000000000000000000000000000000000000..b27756738595dc29a8a7f35e7bffa8da64214826
|
| --- /dev/null
|
| +++ b/fusl/src/math/sqrt.c
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| @@ -0,0 +1,185 @@
|
| +/* origin: FreeBSD /usr/src/lib/msun/src/e_sqrt.c */
|
| +/*
|
| + * ====================================================
|
| + * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
|
| + *
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| + * Developed at SunSoft, a Sun Microsystems, Inc. business.
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| + * Permission to use, copy, modify, and distribute this
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| + * software is freely granted, provided that this notice
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| + * is preserved.
|
| + * ====================================================
|
| + */
|
| +/* sqrt(x)
|
| + * Return correctly rounded sqrt.
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| + * ------------------------------------------
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| + * | Use the hardware sqrt if you have one |
|
| + * ------------------------------------------
|
| + * Method:
|
| + * Bit by bit method using integer arithmetic. (Slow, but portable)
|
| + * 1. Normalization
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| + * Scale x to y in [1,4) with even powers of 2:
|
| + * find an integer k such that 1 <= (y=x*2^(2k)) < 4, then
|
| + * sqrt(x) = 2^k * sqrt(y)
|
| + * 2. Bit by bit computation
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| + * Let q = sqrt(y) truncated to i bit after binary point (q = 1),
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| + * i 0
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| + * i+1 2
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| + * s = 2*q , and y = 2 * ( y - q ). (1)
|
| + * i i i i
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| + *
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| + * To compute q from q , one checks whether
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| + * i+1 i
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| + *
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| + * -(i+1) 2
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| + * (q + 2 ) <= y. (2)
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| + * i
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| + * -(i+1)
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| + * If (2) is false, then q = q ; otherwise q = q + 2 .
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| + * i+1 i i+1 i
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| + *
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| + * With some algebric manipulation, it is not difficult to see
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| + * that (2) is equivalent to
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| + * -(i+1)
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| + * s + 2 <= y (3)
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| + * i i
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| + *
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| + * The advantage of (3) is that s and y can be computed by
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| + * i i
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| + * the following recurrence formula:
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| + * if (3) is false
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| + *
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| + * s = s , y = y ; (4)
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| + * i+1 i i+1 i
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| + *
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| + * otherwise,
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| + * -i -(i+1)
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| + * s = s + 2 , y = y - s - 2 (5)
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| + * i+1 i i+1 i i
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| + *
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| + * One may easily use induction to prove (4) and (5).
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| + * Note. Since the left hand side of (3) contain only i+2 bits,
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| + * it does not necessary to do a full (53-bit) comparison
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| + * in (3).
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| + * 3. Final rounding
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| + * After generating the 53 bits result, we compute one more bit.
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| + * Together with the remainder, we can decide whether the
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| + * result is exact, bigger than 1/2ulp, or less than 1/2ulp
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| + * (it will never equal to 1/2ulp).
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| + * The rounding mode can be detected by checking whether
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| + * huge + tiny is equal to huge, and whether huge - tiny is
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| + * equal to huge for some floating point number "huge" and "tiny".
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| + *
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| + * Special cases:
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| + * sqrt(+-0) = +-0 ... exact
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| + * sqrt(inf) = inf
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| + * sqrt(-ve) = NaN ... with invalid signal
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| + * sqrt(NaN) = NaN ... with invalid signal for signaling NaN
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| + */
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| +
|
| +#include "libm.h"
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| +
|
| +static const double tiny = 1.0e-300;
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| +
|
| +double sqrt(double x)
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| +{
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| + double z;
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| + int32_t sign = (int)0x80000000;
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| + int32_t ix0,s0,q,m,t,i;
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| + uint32_t r,t1,s1,ix1,q1;
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| +
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| + EXTRACT_WORDS(ix0, ix1, x);
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| +
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| + /* take care of Inf and NaN */
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| + if ((ix0&0x7ff00000) == 0x7ff00000) {
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| + return x*x + x; /* sqrt(NaN)=NaN, sqrt(+inf)=+inf, sqrt(-inf)=sNaN */
|
| + }
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| + /* take care of zero */
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| + if (ix0 <= 0) {
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| + if (((ix0&~sign)|ix1) == 0)
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| + return x; /* sqrt(+-0) = +-0 */
|
| + if (ix0 < 0)
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| + return (x-x)/(x-x); /* sqrt(-ve) = sNaN */
|
| + }
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| + /* normalize x */
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| + m = ix0>>20;
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| + if (m == 0) { /* subnormal x */
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| + while (ix0 == 0) {
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| + m -= 21;
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| + ix0 |= (ix1>>11);
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| + ix1 <<= 21;
|
| + }
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| + for (i=0; (ix0&0x00100000) == 0; i++)
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| + ix0<<=1;
|
| + m -= i - 1;
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| + ix0 |= ix1>>(32-i);
|
| + ix1 <<= i;
|
| + }
|
| + m -= 1023; /* unbias exponent */
|
| + ix0 = (ix0&0x000fffff)|0x00100000;
|
| + if (m & 1) { /* odd m, double x to make it even */
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| + ix0 += ix0 + ((ix1&sign)>>31);
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| + ix1 += ix1;
|
| + }
|
| + m >>= 1; /* m = [m/2] */
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| +
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| + /* generate sqrt(x) bit by bit */
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| + ix0 += ix0 + ((ix1&sign)>>31);
|
| + ix1 += ix1;
|
| + q = q1 = s0 = s1 = 0; /* [q,q1] = sqrt(x) */
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| + r = 0x00200000; /* r = moving bit from right to left */
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| +
|
| + while (r != 0) {
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| + t = s0 + r;
|
| + if (t <= ix0) {
|
| + s0 = t + r;
|
| + ix0 -= t;
|
| + q += r;
|
| + }
|
| + ix0 += ix0 + ((ix1&sign)>>31);
|
| + ix1 += ix1;
|
| + r >>= 1;
|
| + }
|
| +
|
| + r = sign;
|
| + while (r != 0) {
|
| + t1 = s1 + r;
|
| + t = s0;
|
| + if (t < ix0 || (t == ix0 && t1 <= ix1)) {
|
| + s1 = t1 + r;
|
| + if ((t1&sign) == sign && (s1&sign) == 0)
|
| + s0++;
|
| + ix0 -= t;
|
| + if (ix1 < t1)
|
| + ix0--;
|
| + ix1 -= t1;
|
| + q1 += r;
|
| + }
|
| + ix0 += ix0 + ((ix1&sign)>>31);
|
| + ix1 += ix1;
|
| + r >>= 1;
|
| + }
|
| +
|
| + /* use floating add to find out rounding direction */
|
| + if ((ix0|ix1) != 0) {
|
| + z = 1.0 - tiny; /* raise inexact flag */
|
| + if (z >= 1.0) {
|
| + z = 1.0 + tiny;
|
| + if (q1 == (uint32_t)0xffffffff) {
|
| + q1 = 0;
|
| + q++;
|
| + } else if (z > 1.0) {
|
| + if (q1 == (uint32_t)0xfffffffe)
|
| + q++;
|
| + q1 += 2;
|
| + } else
|
| + q1 += q1 & 1;
|
| + }
|
| + }
|
| + ix0 = (q>>1) + 0x3fe00000;
|
| + ix1 = q1>>1;
|
| + if (q&1)
|
| + ix1 |= sign;
|
| + ix0 += m << 20;
|
| + INSERT_WORDS(z, ix0, ix1);
|
| + return z;
|
| +}
|
|
|