| Index: src/pathops/SkDCubicToQuads.cpp
|
| diff --git a/src/pathops/SkDCubicToQuads.cpp b/src/pathops/SkDCubicToQuads.cpp
|
| index a28564d4c2c8b3ff724540d70d0c52a3a00fee05..272b997d6c70429c8abfea462e7da31028d02af1 100644
|
| --- a/src/pathops/SkDCubicToQuads.cpp
|
| +++ b/src/pathops/SkDCubicToQuads.cpp
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| @@ -1,4 +1,11 @@
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| /*
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| + * Copyright 2015 Google Inc.
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| + *
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| + * Use of this source code is governed by a BSD-style license that can be
|
| + * found in the LICENSE file.
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| + */
|
| +
|
| +/*
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| http://stackoverflow.com/questions/2009160/how-do-i-convert-the-2-control-points-of-a-cubic-curve-to-the-single-control-poi
|
| */
|
|
|
| @@ -19,63 +26,12 @@ If this is a degree-elevated cubic, then both equations will give the same answe
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| it's likely not, your best bet is to average them. So,
|
|
|
| P1 = -1/4 Q0 + 3/4 Q1 + 3/4 Q2 - 1/4 Q3
|
| -
|
| -SkDCubic defined by: P1/2 - anchor points, C1/C2 control points
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| -|x| is the euclidean norm of x
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| -mid-point approx of cubic: a quad that shares the same anchors with the cubic and has the
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| - control point at C = (3·C2 - P2 + 3·C1 - P1)/4
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| -
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| -Algorithm
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| -
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| -pick an absolute precision (prec)
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| -Compute the Tdiv as the root of (cubic) equation
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| -sqrt(3)/18 · |P2 - 3·C2 + 3·C1 - P1|/2 · Tdiv ^ 3 = prec
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| -if Tdiv < 0.5 divide the cubic at Tdiv. First segment [0..Tdiv] can be approximated with by a
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| - quadratic, with a defect less than prec, by the mid-point approximation.
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| - Repeat from step 2 with the second resulted segment (corresponding to 1-Tdiv)
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| -0.5<=Tdiv<1 - simply divide the cubic in two. The two halves can be approximated by the mid-point
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| - approximation
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| -Tdiv>=1 - the entire cubic can be approximated by the mid-point approximation
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| -
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| -confirmed by (maybe stolen from)
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| -http://www.caffeineowl.com/graphics/2d/vectorial/cubic2quad01.html
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| -// maybe in turn derived from http://www.cccg.ca/proceedings/2004/36.pdf
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| -// also stored at http://www.cis.usouthal.edu/~hain/general/Publications/Bezier/bezier%20cccg04%20paper.pdf
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| -
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| */
|
|
|
| #include "SkPathOpsCubic.h"
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| -#include "SkPathOpsLine.h"
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| #include "SkPathOpsQuad.h"
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| -#include "SkReduceOrder.h"
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| -#include "SkTArray.h"
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| -#include "SkTSort.h"
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| -
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| -#define USE_CUBIC_END_POINTS 1
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| -
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| -static double calc_t_div(const SkDCubic& cubic, double precision, double start) {
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| - const double adjust = sqrt(3.) / 36;
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| - SkDCubic sub;
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| - const SkDCubic* cPtr;
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| - if (start == 0) {
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| - cPtr = &cubic;
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| - } else {
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| - // OPTIMIZE: special-case half-split ?
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| - sub = cubic.subDivide(start, 1);
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| - cPtr = ⊂
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| - }
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| - const SkDCubic& c = *cPtr;
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| - double dx = c[3].fX - 3 * (c[2].fX - c[1].fX) - c[0].fX;
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| - double dy = c[3].fY - 3 * (c[2].fY - c[1].fY) - c[0].fY;
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| - double dist = sqrt(dx * dx + dy * dy);
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| - double tDiv3 = precision / (adjust * dist);
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| - double t = SkDCubeRoot(tDiv3);
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| - if (start > 0) {
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| - t = start + (1 - start) * t;
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| - }
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| - return t;
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| -}
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|
|
| +// used for testing only
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| SkDQuad SkDCubic::toQuad() const {
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| SkDQuad quad;
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| quad[0] = fPts[0];
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| @@ -86,101 +42,3 @@ SkDQuad SkDCubic::toQuad() const {
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| quad[2] = fPts[3];
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| return quad;
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| }
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| -
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| -static bool add_simple_ts(const SkDCubic& cubic, double precision, SkTArray<double, true>* ts) {
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| - double tDiv = calc_t_div(cubic, precision, 0);
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| - if (tDiv >= 1) {
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| - return true;
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| - }
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| - if (tDiv >= 0.5) {
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| - ts->push_back(0.5);
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| - return true;
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| - }
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| - return false;
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| -}
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| -
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| -static void addTs(const SkDCubic& cubic, double precision, double start, double end,
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| - SkTArray<double, true>* ts) {
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| - double tDiv = calc_t_div(cubic, precision, 0);
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| - double parts = ceil(1.0 / tDiv);
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| - for (double index = 0; index < parts; ++index) {
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| - double newT = start + (index / parts) * (end - start);
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| - if (newT > 0 && newT < 1) {
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| - ts->push_back(newT);
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| - }
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| - }
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| -}
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| -
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| -// flavor that returns T values only, deferring computing the quads until they are needed
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| -// FIXME: when called from recursive intersect 2, this could take the original cubic
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| -// and do a more precise job when calling chop at and sub divide by computing the fractional ts.
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| -// it would still take the prechopped cubic for reduce order and find cubic inflections
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| -void SkDCubic::toQuadraticTs(double precision, SkTArray<double, true>* ts) const {
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| - SkReduceOrder reducer;
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| - int order = reducer.reduce(*this, SkReduceOrder::kAllow_Quadratics);
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| - if (order < 3) {
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| - return;
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| - }
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| - double inflectT[5];
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| - int inflections = findInflections(inflectT);
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| - SkASSERT(inflections <= 2);
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| - if (!endsAreExtremaInXOrY()) {
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| - inflections += findMaxCurvature(&inflectT[inflections]);
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| - SkASSERT(inflections <= 5);
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| - }
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| - SkTQSort<double>(inflectT, &inflectT[inflections - 1]);
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| - // OPTIMIZATION: is this filtering common enough that it needs to be pulled out into its
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| - // own subroutine?
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| - while (inflections && approximately_less_than_zero(inflectT[0])) {
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| - memmove(inflectT, &inflectT[1], sizeof(inflectT[0]) * --inflections);
|
| - }
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| - int start = 0;
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| - int next = 1;
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| - while (next < inflections) {
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| - if (!approximately_equal(inflectT[start], inflectT[next])) {
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| - ++start;
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| - ++next;
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| - continue;
|
| - }
|
| - memmove(&inflectT[start], &inflectT[next], sizeof(inflectT[0]) * (--inflections - start));
|
| - }
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| -
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| - while (inflections && approximately_greater_than_one(inflectT[inflections - 1])) {
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| - --inflections;
|
| - }
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| - SkDCubicPair pair;
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| - if (inflections == 1) {
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| - pair = chopAt(inflectT[0]);
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| - int orderP1 = reducer.reduce(pair.first(), SkReduceOrder::kNo_Quadratics);
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| - if (orderP1 < 2) {
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| - --inflections;
|
| - } else {
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| - int orderP2 = reducer.reduce(pair.second(), SkReduceOrder::kNo_Quadratics);
|
| - if (orderP2 < 2) {
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| - --inflections;
|
| - }
|
| - }
|
| - }
|
| - if (inflections == 0 && add_simple_ts(*this, precision, ts)) {
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| - return;
|
| - }
|
| - if (inflections == 1) {
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| - pair = chopAt(inflectT[0]);
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| - addTs(pair.first(), precision, 0, inflectT[0], ts);
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| - addTs(pair.second(), precision, inflectT[0], 1, ts);
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| - return;
|
| - }
|
| - if (inflections > 1) {
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| - SkDCubic part = subDivide(0, inflectT[0]);
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| - addTs(part, precision, 0, inflectT[0], ts);
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| - int last = inflections - 1;
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| - for (int idx = 0; idx < last; ++idx) {
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| - part = subDivide(inflectT[idx], inflectT[idx + 1]);
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| - addTs(part, precision, inflectT[idx], inflectT[idx + 1], ts);
|
| - }
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| - part = subDivide(inflectT[last], 1);
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| - addTs(part, precision, inflectT[last], 1, ts);
|
| - return;
|
| - }
|
| - addTs(*this, precision, 0, 1, ts);
|
| -}
|
|
|