Add switch to disable WebVR gesture requirement

third_party/WebKit/Source/platform/RuntimeEnabledFeatures.in

Index: third_party/WebKit/Source/platform/RuntimeEnabledFeatures.in
diff --git a/third_party/WebKit/Source/platform/RuntimeEnabledFeatures.in b/third_party/WebKit/Source/platform/RuntimeEnabledFeatures.in
index a1a27b1ca3a268e5cd8b0c9b2d53072913fbbc50..1bde7acfc955b1d029eaac06ddcf8c2b2f44b498 100644
--- a/third_party/WebKit/Source/platform/RuntimeEnabledFeatures.in
+++ b/third_party/WebKit/Source/platform/RuntimeEnabledFeatures.in
@@ -250,6 +250,7 @@ WebGLDraftExtensions status=experimental
 WebGLImageChromium
 WebUSB status=experimental, origin_trial_feature_name=WebUSB
 WebVR origin_trial_feature_name=WebVR
+WebVrWithoutUserGestures

[ddorwin, 2016/11/30 23:33:34]

This seems like the wrong place to control this. These are mostly features in
development and will eventually be removed from here.

Most for-test values are probably checked in Chromium. The problem for WebVR is
that the gesture requirement is checked in Blink. Still, maybe there is a better
way to do this.

I'd be curious what Blink people have to say.

[ddorwin, 2016/11/30 23:33:34]

"Without" is still a negative. These are feature names, so they can be
independent of the switch name. (In the past, we toggled between
enabled/disabled in the switch names, but this remained the same.)
It seems that Requires/Needs would be better. Then we need to set it true (maybe
=stable would cause that if we keep it here) by default.

[haraken, 2016/11/30 23:41:28]

If you need to control a runtime-enabled feature in Blink, this is a right place
to do that.

[bsheedy, 2016/11/30 23:59:12]

Done.

 WebVTTRegions status=experimental
 V8BasedStructuredClone status=stable
 V8IdleTasks
@@ -270,4 +271,4 @@ LazyParseCSS status=experimental
 ParseHTMLOnMainThread status=test
 SendBeaconThrowForBlobWithNonSimpleType status=experimental
 PerformanceNavigationTiming2 status=test
-BackgroundVideoTrackOptimization status=stable
+BackgroundVideoTrackOptimization status=stable