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Unified Diff: doc/definition/static-semantics.tex

Issue 1236443002: Core static semantics (Closed) Base URL: git@github.com:dart-lang/dev_compiler.git@master
Patch Set: Created 5 years, 5 months ago
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Index: doc/definition/static-semantics.tex
diff --git a/doc/definition/static-semantics.tex b/doc/definition/static-semantics.tex
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+\subsection*{Expression typing: $\yieldsOk{\Phi, \Delta, \Gamma}{e}{\opt{\tau}}{e'}{\tau'}$} \hrulefill
+
+Expression typing is a relation between typing contexts, a term ($e$), an
+optional type ($\opt{\tau}$), and a type ($\tau'$). The term $e$ represents the
+term being checked. The optional type $\opt{\tau}$ is the type against which
+the term is being checked (if present). The output type $\tau'$ is the most
+precise type synthesized for the term. It should always be the case that the
+synthesized (output) type is a subtype of the checked (input) type if the latter
+is present. The checking/synthesis pattern allows for the propogation of type
+information both downwards and upwards. It is often the case that downwards
+propogation is not useful. Consequently, to simplify the presentation the rules
+which do not use the checking type require that it be empty ($\_$). The first
+typing rule allows contextual type information to be dropped so that such rules
+apply in the cast that we have contextual type information, subject to the
+contextual type being a supertype of the synthesized type:
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\_}{e'}{\sigma} \quad\quad
+ \subtypeOf{\Phi, \Delta}{\sigma}{\tau}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}{e}{\tau}{e'}{\sigma}}
+
+The implicit downcast rule also allows this when the contextual type is a
+subtype of the synthesized type, corresponding to an implicit downcast.
vsm 2015/07/13 22:36:56 As with the optional typing, I wonder if it's bett
Leaf 2015/07/14 22:39:49 Yes, I have mental note to revisit this. We can h
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\_}{e'}{\sigma} \quad\quad
+ \subtypeOf{\Phi, \Delta}{\tau}{\sigma}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}{e}{\tau}{\echeck{e'}{\tau}}{\tau}}
+
+Variables are typed according to their declarations:
+
+\axiom{\yieldsOk{\Phi, \Delta, \extends{\Gamma}{x}{\tau}}{x}{\_}{x}{\tau}}
vsm 2015/07/13 22:36:56 There is type promotion - but perhaps that's ortho
Leaf 2015/07/14 22:39:49 Yes, I could formalize this, but it will take a fa
+
+Numbers, booleans, and null all have a fixed synthesized type.
+
+\axiom{\yieldsOk{\Phi, \Delta, \Gamma}{i}{\_}{i}{\Num}}
+
+\axiom{\yieldsOk{\Phi, \Delta, \Gamma}{\eff}{\_}{\eff}{\Bool}}
+
+\axiom{\yieldsOk{\Phi, \Delta, \Gamma}{\ett}{\_}{\ett}{\Bool}}
+
+\axiom{\yieldsOk{\Phi, \Delta, \Gamma}{\enull}{\_}{\enull}{\Bottom}}
+
+A $\ethis$ expression is well-typed if we are inside of a method, and $\sigma$
+is the type of the enclosing class.
+
+\infrule{\Gamma = \Gamma'_{\sigma}
+ }
+ {
+ \yieldsOk{\Phi, \Delta, \Gamma}{\ethis}{\_}{\ethis}{\sigma}
+ }
+
+A fully annotated function is well-typed if its body is well-typed at its
+declared return type, under the assumption that the variables have their
+declared types.
+
+\infrule{\Gamma' = \extends{\Gamma}{\many{x}}{\many{\tau}} \quad
+ \yieldsOk{\Phi, \Delta, \Gamma'}{e}{\sigma}{e'}{\sigma'}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\elambda{\many{x:\tau}}{\sigma}{e}}
+ {\_}
+ {\elambda{\many{x:\tau}}{\sigma}{e'}}
+ {\Arrow[-]{\many{\tau}}{\sigma}}
vsm 2015/07/13 22:36:56 Should this be \sigma_'_?
Leaf 2015/07/14 22:39:50 I think it *can* be, but not sure that it *should*
+ }
+
+A function with a missing argument type is well-typed if it is well-typed with
+the argument type replaced with $\Dynamic$.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {\elambda{x_0:\opt{\tau_0}, \ldots, x_i:\Dynamic, \ldots, x_n:\opt{\tau_n}}{\opt{\sigma}}{e}}
+ {\opt{\tau}}
+ {e_f}
+ {\tau_f}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\elambda{x_0:\opt{\tau_0}, \ldots, x_i:\_, \ldots, x_n:\opt{\tau_n}}{\opt{\sigma}}{e}}
+ {\opt{\tau}}
+ {e_f}
+ {\tau_f}
+ }
+
+A function with a missing argument type is well-typed if it is well-typed with
+the argument type replaced with the corresponding argument type from the context
+type. Note that this rule overlaps with the previous: the formal presentation
+leaves this as a non-deterministic choice.
vsm 2015/07/13 22:36:56 Is this a step toward downward inference?
Leaf 2015/07/14 22:39:49 This is downwards inference. It's specified in a
vsm 2015/07/15 18:25:34 So, if my expr is: (e) => e.foo and my contextua
Leaf 2015/07/15 22:27:25 As currently specified, it will type check, and wi
+
+\infrule{\tau_c = \Arrow[k]{\upsilon_0, \ldots, \upsilon_n}{\upsilon_r} \\
+ \yieldsOk{\Phi, \Delta, \Gamma}
+ {\elambda{x_0:\opt{\tau_0}, \ldots, x_i:\upsilon_i, \ldots, x_n:\opt{\tau_n}}{\opt{\sigma}}{e}}
+ {\tau_c}
+ {e_f}
+ {\tau_f}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\elambda{x_0:\opt{\tau_0}, \ldots, x_i:\_, \ldots, x_n:\opt{\tau_n}}{\opt{\sigma}}{e}}
+ {\tau_c}
+ {e_f}
+ {\tau_f}
+ }
+
+A function with a missing return type is well-typed if it is well-typed with
+the return type replaced with $\Dynamic$.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {\elambda{\many{x:\opt{\tau}}}{\Dynamic}{e}}
+ {\opt{\tau_c}}
+ {e_f}
+ {\tau_f}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\elambda{\many{x:\opt{\tau}}}{\_}{e}}
+ {\opt{\tau_c}}
+ {e_f}
+ {\tau_f}
+ }
+
+A function with a missing return type is well-typed if it is well-typed with
+the return type replaced with the corresponding return type from the context
+type. Note that this rule overlaps with the previous: the formal presentation
+leaves this as a non-deterministic choice.
+
+\infrule{\tau_c = \Arrow[k]{\upsilon_0, \ldots, \upsilon_n}{\upsilon_r} \\
+ \yieldsOk{\Phi, \Delta, \Gamma}
+ {\elambda{\many{x:\opt{\tau}}}{\upsilon_r}{e}}
+ {\tau_c}
+ {e_f}
+ {\tau_f}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\elambda{\many{x:\opt{\tau}}}{\_}{e}}
+ {\tau_c}
+ {e_f}
+ {\tau_f}
+ }
+
+
+Instance creation creates an instance of the appropriate type.
+
+% FIXME(leafp): inference
+% FIXME(leafp): deal with bounds
+\infrule{(C : \dclass{\TApp{C}{T_0,\ldots,T_n}}{\TApp{C'}{\upsilon_0, \ldots, \upsilon_k}}{\ldots}) \in \Phi \\
+ \mbox{len}(\many{\tau}) = n+1}
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\enew{C}{\many{\tau}}{}}
+ {\_}
+ {\enew{C}{\many{\tau}}{}}
+ {\TApp{C}{\many{\tau}}}
+ }
+
+
+Members of the set of primitive operations (left unspecified) can only be
+applied. Applications of primitives are well-typed if the arguments are
+well-typed at the types given by the signature of the primitive.
vsm 2015/07/13 22:36:56 In Dart, these are really just syntactic sugar for
Leaf 2015/07/14 22:39:49 These really model the underlying primitive operat
+
+\infrule{\phi\, :\, \Arrow[]{\many{\tau}}{\sigma} \quad
+ \yieldsOk{\Phi, \Delta, \Gamma}{e}{\tau}{e'}{\tau'}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\eprimapp{\phi}{\many{e}}}
+ {\_}
+ {\eprimapp{\phi}{\many{e'}}}
+ {\sigma}
+ }
+
+Function applications are well-typed if the applicand is well-typed and has
+function type, and the arguments are well-typed.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {e}
+ {\_}
+ {e'}
+ {\Arrow[k]{\many{\tau_a}}{\tau_r}} \quad\quad
+ \yieldsOk{\Phi, \Delta, \Gamma}
+ {e_a}
+ {\tau_a}
+ {e_a'}
+ {\tau_a'} \quad \mbox{for}\ e_a, \tau_a \in \many{e_a}, \many{\tau_a}
+\iftrans{\\ e_c = \begin{cases}
+ \ecall{e'}{\many{e_a'}} & \text{if $k = -$}\\
+ \edcall{e'}{\many{e_a'}} & \text{if $k = +$}
+ \end{cases}}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\ecall{e}{\many{e_a}}}
+ {\_}
+ {e_c}
+ {\tau_r}
+ }
+
+Application of an expression of type $\Dynamic$ is well-typed if the arguments
+are well-typed at any type.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {e}
+ {\_}
+ {e'}
+ {\Dynamic} \quad\quad
+ \yieldsOk{\Phi, \Delta, \Gamma}
+ {e_a}
+ {\_}
+ {e_a'}
+ {\tau_a'} \quad \mbox{for}\ e_a \in \many{e_a}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\ecall{e}{\many{e_a}}}
+ {\_}
+ {\edcall{e'}{\many{e_a'}}}
+ {\Dynamic}
+ }
+
+A dynamic call expression is well-typed so long as the applicand and the
+arguments are well-typed at any type.
vsm 2015/07/13 22:36:56 What does dcall add if you allow e to be dynamic a
Leaf 2015/07/14 22:39:49 Basically I'm anticipating the dynamic semantics (
Siggi Cherem (dart-lang) 2015/07/14 23:59:21 Makes sense - I think it might be worth splitting
vsm 2015/07/15 18:25:34 It's the same thing (I think), but it might be a l
Leaf 2015/07/15 22:27:25 Yes, this is reasonable. I need additional mechan
Leaf 2015/07/15 22:27:25 Done.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {e}
+ {\_}
+ {e'}
+ {\tau} \quad
+ \yieldsOk{\Phi, \Delta, \Gamma}
+ {e_a}
+ {\_}
+ {e_a'}
+ {\tau_a} \quad \mbox{for}\ e_a \in \many{e_a}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\edcall{e}{\many{e_a}}}
+ {\_}
+ {\edcall{e'}{\many{e_a'}}}
+ {\Dynamic}
+ }
+
+A field load is well-typed if the term is well-typed, and the field name is
+present in the type of the term.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {e}
+ {\_}
+ {e'}
+ {\sigma} \quad\quad
+ \fieldLookup{\Phi}{\sigma}{m}{\tau}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\eload{e}{m}}
+ {\_}
+ {\eload{e'}{m}}
+ {\tau}
+ }
+
+A field load from a term of type $\Dynamic$ is well-typed if the term is
+well-typed.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {e}
+ {\_}
+ {e'}
+ {\Dynamic}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\eload{e}{m}}
+ {\_}
+ {\edload{e'}{m}}
+ {\Dynamic}
+ }
+
+A dynamic load is well typed so long as the term is well-typed.
vsm 2015/07/13 22:36:56 Ditto?
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {e}
+ {\_}
+ {e'}
+ {\Dynamic}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\edload{e}{m}}
+ {\_}
+ {\edload{e'}{m}}
+ {\Dynamic}
+ }
+
+An assignment expression is well-typed so long as the term is well-typed at a
+type which is compatible with the type of the variable being assigned.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {e}
+ {\opt{\tau}}
+ {e'}
+ {\sigma} \quad
+ \yieldsOk{\Phi, \Delta, \Gamma}
+ {x}
+ {\sigma}
+ {x}
+ {\sigma'}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\eassign{x}{e}}
+ {\opt{\tau}}
+ {\eassign{x}{e'}}
+ {\sigma}
+ }
vsm 2015/07/13 22:36:56 This reads a little odd to me ... seems to suggest
Leaf 2015/07/14 22:39:49 The way it works here is a bit subtle, but I think
+
+A field assignment is well-typed if the term being assigned is well-typed, the
+field name is present in the type of $\ethis$, and the declared type of the
+field is compatible with the type of the expression being assigned.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}
+ {e}
+ {\opt{\tau}}
+ {e'}
+ {\sigma} \quad\quad
+ \Gamma = \Gamma_\tau & \fieldLookup{\Phi}{\tau}{m}{\sigma'} \quad
+ \subtypeOf{\Phi, \Delta}{\sigma}{\sigma'}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\eset{\ethis}{m}{e}}
+ {\opt{\tau}}
+ {\eset{\ethis}{m}{e}}
+ {\sigma}
+ }
+
+A throw expression is well-typed at any type.
+
+\axiom{\yieldsOk{\Phi, \Delta, \Gamma}
+ {\ethrow}
+ {\_}
+ {\ethrow}
+ {\sigma}
+ }
+
+A cast expression is well-typed so long as the term being cast is well-typed.
+The synthesized type is the cast-to type.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\_}{e'}{\sigma}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\eas{e}{\tau}}
+ {\_}
+ {\eas{e'}{\tau}}
+ {\tau}
+ }
+
+An instance check expression is well-typed if the term being checked is
+well-typed.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\_}{e'}{\sigma}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\eis{e}{\tau}}
+ {\_}
+ {\eis{e'}{\tau}}
+ {\Bool}
+ }
vsm 2015/07/13 22:36:56 Should \tau be required to be ground here and abov
Leaf 2015/07/14 22:39:49 Yes.
Leaf 2015/07/14 22:39:49 Done.
+
+A check expression is well-typed so long as the term being checked is
+well-typed. The synthesized type is the target type of the check.
+
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\_}{e'}{\sigma}
+ }
+ {\yieldsOk{\Phi, \Delta, \Gamma}
+ {\echeck{e}{\tau}}
+ {\_}
+ {\echeck{e'}{\tau}}
+ {\tau}
+ }
+
+\subsection*{Declaration typing: $\declOk[d]{\Phi, \Delta, \Gamma}{\mathit{vd}}{\mathit{vd'}}{\Gamma'}$}
+\hrulefill
+
+Variable declaration typing checks the well-formedness of the components, and
+produces an output context $\Gamma'$ which contains the binding introduced by
+the declaration.
+
+A simple variable declaration with a declared type is well-typed if the
+initializer for the declaration is well-typed at the declared type. The output
+context binds the variable at the declared type.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\tau}{e'}{\tau'} \quad
+ }
+ {\declOk[d]{\Phi, \Delta, \Gamma}
+ {\dvar{x:\tau}{e}}
+ {\dvar{x:\tau'}{e'}}
+ {\extends{\Gamma}{x}{\tau}}
+ }
+
+A simple variable declaration without a declared type is well-typed if the
+initializer for the declaration is well-typed at any type. The output context
+binds the variable at the synthesized type (a simple form of type inference).
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\_}{e'}{\tau'} \quad
+ }
+ {\declOk[d]{\Phi, \Delta, \Gamma}
+ {\dvar{x:\_}{e}}
+ {\dvar{x:\tau'}{e'}}
+ {\extends{\Gamma}{x}{\tau'}}
+ }
+
+A function declaration is well-typed if the body of the function is well-typed
+with the given return type, under the assumption that the function and its
+parameters have their declared types. The function is assumed to have a
+contravariant (precise) function type. The output context binds the function
+variable only.
+
+\infrule{\tau_f = \Arrow[-]{\many{\tau_a}}{\tau_r} \quad
+ \Gamma' = \extends{\Gamma}{f}{\tau_f} \quad
+ \Gamma'' = \extends{\Gamma'}{\many{x}}{\many{\tau_a}} \\
+ \stmtOk{\Phi, \Delta, \Gamma''}{s}{\tau_r}{s'}{\Gamma_0}
+ }
+ {\declOk[d]{\Phi, \Delta, \Gamma}
+ {\dfun{\tau_r}{f}{\many{x:\tau_a}}{s}}
+ {\dfun{\tau_r}{f}{\many{x:\tau_a}}{s'}}
+ {\Gamma'}
+ }
+
+\subsection*{Statement typing: $\stmtOk{\Phi, \Delta, \Gamma}{\mathit{s}}{\tau}{\mathit{s'}}{\Gamma'}$}
+\hrulefill
+
+The statement typing relation checks the well-formedness of statements and
+produces an output context which reflects any additional variable bindings
+introduced into scope by the statements.
+
+A variable declaration statement is well-typed if the variable declaration is
+well-typed per the previous relation, with the corresponding output context.
+
+\infrule{\declOk[d]{\Phi, \Delta, \Gamma}
+ {\mathit{vd}}
+ {\mathit{vd'}}
+ {\Gamma'}
+ }
+ {\stmtOk{\Phi, \Delta, \Gamma}
+ {\mathit{vd}}
+ {\tau}
+ {\mathit{vd'}}
+ {\Gamma'}
+ }
+
+An expression statement is well-typed if the expression is well-typed at any
+type per the expression typing relation.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\_}{e'}{\tau}
+ }
+ {\stmtOk{\Phi, \Delta, \Gamma}{e}{\tau}{e'}{\Gamma}
+ }
+
+A conditional statement is well-typed if the condition is well-typed as a
+boolean, and the statements making up the two arms are well-typed. The output
+context is unchanged.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\Bool}{e'}{\sigma} \quad
+ \stmtOk{\Phi, \Delta, \Gamma}{s_1}{\tau_r}{s_1'}{\Gamma_1} \quad
+ \stmtOk{\Phi, \Delta, \Gamma}{s_2}{\tau_r}{s_2'}{\Gamma_2}
+ }
+ {\stmtOk{\Phi, \Delta, \Gamma}
+ {\sifthenelse{e}{s_1}{s_2}}
+ {\tau_r}
+ {\sifthenelse{e'}{s_1'}{s_2'}}
+ {\Gamma}
+ }
+
+A return statement is well-typed if the expression being returned is well-typed
+at the given return type.
+
+\infrule{\yieldsOk{\Phi, \Delta, \Gamma}{e}{\tau_r}{e'}{\tau}
+ }
+ {\stmtOk{\Phi, \Delta, \Gamma}{\sreturn{e}}{\tau_r}{\sreturn{e'}}{\Gamma}
+ }
+
+A sequence statement is well-typed if the first component is well-typed, and the
+second component is well-typed with the output context of the first component as
+its input context. The final output context is the output context of the second
+component.
+
+\infrule{\stmtOk{\Phi, \Delta, \Gamma}{s_1}{\tau_r}{s_1'}{\Gamma'} \quad
+ \stmtOk{\Phi, \Delta, \Gamma'}{s_2}{\tau_r}{s_2'}{\Gamma''}
+ }
+ {\stmtOk{\Phi, \Delta, \Gamma}{s_1;s_2}{\tau_r}{s_1';s_2'}{\Gamma''}
+ }

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