Index: runtime/third_party/double-conversion/src/bignum-dtoa.cc |
diff --git a/runtime/third_party/double-conversion/src/bignum-dtoa.cc b/runtime/third_party/double-conversion/src/bignum-dtoa.cc |
new file mode 100644 |
index 0000000000000000000000000000000000000000..00724e8b295f0da2ae05e4f600c98bc80a593848 |
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+++ b/runtime/third_party/double-conversion/src/bignum-dtoa.cc |
@@ -0,0 +1,653 @@ |
+// Copyright 2010 the V8 project authors. All rights reserved. |
+// Redistribution and use in source and binary forms, with or without |
+// modification, are permitted provided that the following conditions are |
+// met: |
+// |
+// * Redistributions of source code must retain the above copyright |
+// notice, this list of conditions and the following disclaimer. |
+// * Redistributions in binary form must reproduce the above |
+// copyright notice, this list of conditions and the following |
+// disclaimer in the documentation and/or other materials provided |
+// with the distribution. |
+// * Neither the name of Google Inc. nor the names of its |
+// contributors may be used to endorse or promote products derived |
+// from this software without specific prior written permission. |
+// |
+// THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS |
+// "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT |
+// LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR |
+// A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT |
+// OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, |
+// SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT |
+// LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, |
+// DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY |
+// THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT |
+// (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE |
+// OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. |
+ |
+#include <math.h> |
+ |
+#include "bignum-dtoa.h" |
+ |
+#include "bignum.h" |
+#include "double.h" |
+ |
+namespace double_conversion { |
+ |
+static int NormalizedExponent(uint64_t significand, int exponent) { |
+ ASSERT(significand != 0); |
+ while ((significand & Double::kHiddenBit) == 0) { |
+ significand = significand << 1; |
+ exponent = exponent - 1; |
+ } |
+ return exponent; |
+} |
+ |
+ |
+// Forward declarations: |
+// Returns an estimation of k such that 10^(k-1) <= v < 10^k. |
+static int EstimatePower(int exponent); |
+// Computes v / 10^estimated_power exactly, as a ratio of two bignums, numerator |
+// and denominator. |
+static void InitialScaledStartValues(double v, |
+ int estimated_power, |
+ bool need_boundary_deltas, |
+ Bignum* numerator, |
+ Bignum* denominator, |
+ Bignum* delta_minus, |
+ Bignum* delta_plus); |
+// Multiplies numerator/denominator so that its values lies in the range 1-10. |
+// Returns decimal_point s.t. |
+// v = numerator'/denominator' * 10^(decimal_point-1) |
+// where numerator' and denominator' are the values of numerator and |
+// denominator after the call to this function. |
+static void FixupMultiply10(int estimated_power, bool is_even, |
+ int* decimal_point, |
+ Bignum* numerator, Bignum* denominator, |
+ Bignum* delta_minus, Bignum* delta_plus); |
+// Generates digits from the left to the right and stops when the generated |
+// digits yield the shortest decimal representation of v. |
+static void GenerateShortestDigits(Bignum* numerator, Bignum* denominator, |
+ Bignum* delta_minus, Bignum* delta_plus, |
+ bool is_even, |
+ Vector<char> buffer, int* length); |
+// Generates 'requested_digits' after the decimal point. |
+static void BignumToFixed(int requested_digits, int* decimal_point, |
+ Bignum* numerator, Bignum* denominator, |
+ Vector<char>(buffer), int* length); |
+// Generates 'count' digits of numerator/denominator. |
+// Once 'count' digits have been produced rounds the result depending on the |
+// remainder (remainders of exactly .5 round upwards). Might update the |
+// decimal_point when rounding up (for example for 0.9999). |
+static void GenerateCountedDigits(int count, int* decimal_point, |
+ Bignum* numerator, Bignum* denominator, |
+ Vector<char>(buffer), int* length); |
+ |
+ |
+void BignumDtoa(double v, BignumDtoaMode mode, int requested_digits, |
+ Vector<char> buffer, int* length, int* decimal_point) { |
+ ASSERT(v > 0); |
+ ASSERT(!Double(v).IsSpecial()); |
+ uint64_t significand = Double(v).Significand(); |
+ bool is_even = (significand & 1) == 0; |
+ int exponent = Double(v).Exponent(); |
+ int normalized_exponent = NormalizedExponent(significand, exponent); |
+ // estimated_power might be too low by 1. |
+ int estimated_power = EstimatePower(normalized_exponent); |
+ |
+ // Shortcut for Fixed. |
+ // The requested digits correspond to the digits after the point. If the |
+ // number is much too small, then there is no need in trying to get any |
+ // digits. |
+ if (mode == BIGNUM_DTOA_FIXED && -estimated_power - 1 > requested_digits) { |
+ buffer[0] = '\0'; |
+ *length = 0; |
+ // Set decimal-point to -requested_digits. This is what Gay does. |
+ // Note that it should not have any effect anyways since the string is |
+ // empty. |
+ *decimal_point = -requested_digits; |
+ return; |
+ } |
+ |
+ Bignum numerator; |
+ Bignum denominator; |
+ Bignum delta_minus; |
+ Bignum delta_plus; |
+ // Make sure the bignum can grow large enough. The smallest double equals |
+ // 4e-324. In this case the denominator needs fewer than 324*4 binary digits. |
+ // The maximum double is 1.7976931348623157e308 which needs fewer than |
+ // 308*4 binary digits. |
+ ASSERT(Bignum::kMaxSignificantBits >= 324*4); |
+ bool need_boundary_deltas = (mode == BIGNUM_DTOA_SHORTEST); |
+ InitialScaledStartValues(v, estimated_power, need_boundary_deltas, |
+ &numerator, &denominator, |
+ &delta_minus, &delta_plus); |
+ // We now have v = (numerator / denominator) * 10^estimated_power. |
+ FixupMultiply10(estimated_power, is_even, decimal_point, |
+ &numerator, &denominator, |
+ &delta_minus, &delta_plus); |
+ // We now have v = (numerator / denominator) * 10^(decimal_point-1), and |
+ // 1 <= (numerator + delta_plus) / denominator < 10 |
+ switch (mode) { |
+ case BIGNUM_DTOA_SHORTEST: |
+ GenerateShortestDigits(&numerator, &denominator, |
+ &delta_minus, &delta_plus, |
+ is_even, buffer, length); |
+ break; |
+ case BIGNUM_DTOA_FIXED: |
+ BignumToFixed(requested_digits, decimal_point, |
+ &numerator, &denominator, |
+ buffer, length); |
+ break; |
+ case BIGNUM_DTOA_PRECISION: |
+ GenerateCountedDigits(requested_digits, decimal_point, |
+ &numerator, &denominator, |
+ buffer, length); |
+ break; |
+ default: |
+ UNREACHABLE(); |
+ } |
+ buffer[*length] = '\0'; |
+} |
+ |
+ |
+// The procedure starts generating digits from the left to the right and stops |
+// when the generated digits yield the shortest decimal representation of v. A |
+// decimal representation of v is a number lying closer to v than to any other |
+// double, so it converts to v when read. |
+// |
+// This is true if d, the decimal representation, is between m- and m+, the |
+// upper and lower boundaries. d must be strictly between them if !is_even. |
+// m- := (numerator - delta_minus) / denominator |
+// m+ := (numerator + delta_plus) / denominator |
+// |
+// Precondition: 0 <= (numerator+delta_plus) / denominator < 10. |
+// If 1 <= (numerator+delta_plus) / denominator < 10 then no leading 0 digit |
+// will be produced. This should be the standard precondition. |
+static void GenerateShortestDigits(Bignum* numerator, Bignum* denominator, |
+ Bignum* delta_minus, Bignum* delta_plus, |
+ bool is_even, |
+ Vector<char> buffer, int* length) { |
+ // Small optimization: if delta_minus and delta_plus are the same just reuse |
+ // one of the two bignums. |
+ if (Bignum::Equal(*delta_minus, *delta_plus)) { |
+ delta_plus = delta_minus; |
+ } |
+ *length = 0; |
+ while (true) { |
+ uint16_t digit; |
+ digit = numerator->DivideModuloIntBignum(*denominator); |
+ ASSERT(digit <= 9); // digit is a uint16_t and therefore always positive. |
+ // digit = numerator / denominator (integer division). |
+ // numerator = numerator % denominator. |
+ buffer[(*length)++] = digit + '0'; |
+ |
+ // Can we stop already? |
+ // If the remainder of the division is less than the distance to the lower |
+ // boundary we can stop. In this case we simply round down (discarding the |
+ // remainder). |
+ // Similarly we test if we can round up (using the upper boundary). |
+ bool in_delta_room_minus; |
+ bool in_delta_room_plus; |
+ if (is_even) { |
+ in_delta_room_minus = Bignum::LessEqual(*numerator, *delta_minus); |
+ } else { |
+ in_delta_room_minus = Bignum::Less(*numerator, *delta_minus); |
+ } |
+ if (is_even) { |
+ in_delta_room_plus = |
+ Bignum::PlusCompare(*numerator, *delta_plus, *denominator) >= 0; |
+ } else { |
+ in_delta_room_plus = |
+ Bignum::PlusCompare(*numerator, *delta_plus, *denominator) > 0; |
+ } |
+ if (!in_delta_room_minus && !in_delta_room_plus) { |
+ // Prepare for next iteration. |
+ numerator->Times10(); |
+ delta_minus->Times10(); |
+ // We optimized delta_plus to be equal to delta_minus (if they share the |
+ // same value). So don't multiply delta_plus if they point to the same |
+ // object. |
+ if (delta_minus != delta_plus) { |
+ delta_plus->Times10(); |
+ } |
+ } else if (in_delta_room_minus && in_delta_room_plus) { |
+ // Let's see if 2*numerator < denominator. |
+ // If yes, then the next digit would be < 5 and we can round down. |
+ int compare = Bignum::PlusCompare(*numerator, *numerator, *denominator); |
+ if (compare < 0) { |
+ // Remaining digits are less than .5. -> Round down (== do nothing). |
+ } else if (compare > 0) { |
+ // Remaining digits are more than .5 of denominator. -> Round up. |
+ // Note that the last digit could not be a '9' as otherwise the whole |
+ // loop would have stopped earlier. |
+ // We still have an assert here in case the preconditions were not |
+ // satisfied. |
+ ASSERT(buffer[(*length) - 1] != '9'); |
+ buffer[(*length) - 1]++; |
+ } else { |
+ // Halfway case. |
+ // TODO(floitsch): need a way to solve half-way cases. |
+ // For now let's round towards even (since this is what Gay seems to |
+ // do). |
+ |
+ if ((buffer[(*length) - 1] - '0') % 2 == 0) { |
+ // Round down => Do nothing. |
+ } else { |
+ ASSERT(buffer[(*length) - 1] != '9'); |
+ buffer[(*length) - 1]++; |
+ } |
+ } |
+ return; |
+ } else if (in_delta_room_minus) { |
+ // Round down (== do nothing). |
+ return; |
+ } else { // in_delta_room_plus |
+ // Round up. |
+ // Note again that the last digit could not be '9' since this would have |
+ // stopped the loop earlier. |
+ // We still have an ASSERT here, in case the preconditions were not |
+ // satisfied. |
+ ASSERT(buffer[(*length) -1] != '9'); |
+ buffer[(*length) - 1]++; |
+ return; |
+ } |
+ } |
+} |
+ |
+ |
+// Let v = numerator / denominator < 10. |
+// Then we generate 'count' digits of d = x.xxxxx... (without the decimal point) |
+// from left to right. Once 'count' digits have been produced we decide wether |
+// to round up or down. Remainders of exactly .5 round upwards. Numbers such |
+// as 9.999999 propagate a carry all the way, and change the |
+// exponent (decimal_point), when rounding upwards. |
+static void GenerateCountedDigits(int count, int* decimal_point, |
+ Bignum* numerator, Bignum* denominator, |
+ Vector<char>(buffer), int* length) { |
+ ASSERT(count >= 0); |
+ for (int i = 0; i < count - 1; ++i) { |
+ uint16_t digit; |
+ digit = numerator->DivideModuloIntBignum(*denominator); |
+ ASSERT(digit <= 9); // digit is a uint16_t and therefore always positive. |
+ // digit = numerator / denominator (integer division). |
+ // numerator = numerator % denominator. |
+ buffer[i] = digit + '0'; |
+ // Prepare for next iteration. |
+ numerator->Times10(); |
+ } |
+ // Generate the last digit. |
+ uint16_t digit; |
+ digit = numerator->DivideModuloIntBignum(*denominator); |
+ if (Bignum::PlusCompare(*numerator, *numerator, *denominator) >= 0) { |
+ digit++; |
+ } |
+ buffer[count - 1] = digit + '0'; |
+ // Correct bad digits (in case we had a sequence of '9's). Propagate the |
+ // carry until we hat a non-'9' or til we reach the first digit. |
+ for (int i = count - 1; i > 0; --i) { |
+ if (buffer[i] != '0' + 10) break; |
+ buffer[i] = '0'; |
+ buffer[i - 1]++; |
+ } |
+ if (buffer[0] == '0' + 10) { |
+ // Propagate a carry past the top place. |
+ buffer[0] = '1'; |
+ (*decimal_point)++; |
+ } |
+ *length = count; |
+} |
+ |
+ |
+// Generates 'requested_digits' after the decimal point. It might omit |
+// trailing '0's. If the input number is too small then no digits at all are |
+// generated (ex.: 2 fixed digits for 0.00001). |
+// |
+// Input verifies: 1 <= (numerator + delta) / denominator < 10. |
+static void BignumToFixed(int requested_digits, int* decimal_point, |
+ Bignum* numerator, Bignum* denominator, |
+ Vector<char>(buffer), int* length) { |
+ // Note that we have to look at more than just the requested_digits, since |
+ // a number could be rounded up. Example: v=0.5 with requested_digits=0. |
+ // Even though the power of v equals 0 we can't just stop here. |
+ if (-(*decimal_point) > requested_digits) { |
+ // The number is definitively too small. |
+ // Ex: 0.001 with requested_digits == 1. |
+ // Set decimal-point to -requested_digits. This is what Gay does. |
+ // Note that it should not have any effect anyways since the string is |
+ // empty. |
+ *decimal_point = -requested_digits; |
+ *length = 0; |
+ return; |
+ } else if (-(*decimal_point) == requested_digits) { |
+ // We only need to verify if the number rounds down or up. |
+ // Ex: 0.04 and 0.06 with requested_digits == 1. |
+ ASSERT(*decimal_point == -requested_digits); |
+ // Initially the fraction lies in range (1, 10]. Multiply the denominator |
+ // by 10 so that we can compare more easily. |
+ denominator->Times10(); |
+ if (Bignum::PlusCompare(*numerator, *numerator, *denominator) >= 0) { |
+ // If the fraction is >= 0.5 then we have to include the rounded |
+ // digit. |
+ buffer[0] = '1'; |
+ *length = 1; |
+ (*decimal_point)++; |
+ } else { |
+ // Note that we caught most of similar cases earlier. |
+ *length = 0; |
+ } |
+ return; |
+ } else { |
+ // The requested digits correspond to the digits after the point. |
+ // The variable 'needed_digits' includes the digits before the point. |
+ int needed_digits = (*decimal_point) + requested_digits; |
+ GenerateCountedDigits(needed_digits, decimal_point, |
+ numerator, denominator, |
+ buffer, length); |
+ } |
+} |
+ |
+ |
+// Returns an estimation of k such that 10^(k-1) <= v < 10^k where |
+// v = f * 2^exponent and 2^52 <= f < 2^53. |
+// v is hence a normalized double with the given exponent. The output is an |
+// approximation for the exponent of the decimal approimation .digits * 10^k. |
+// |
+// The result might undershoot by 1 in which case 10^k <= v < 10^k+1. |
+// Note: this property holds for v's upper boundary m+ too. |
+// 10^k <= m+ < 10^k+1. |
+// (see explanation below). |
+// |
+// Examples: |
+// EstimatePower(0) => 16 |
+// EstimatePower(-52) => 0 |
+// |
+// Note: e >= 0 => EstimatedPower(e) > 0. No similar claim can be made for e<0. |
+static int EstimatePower(int exponent) { |
+ // This function estimates log10 of v where v = f*2^e (with e == exponent). |
+ // Note that 10^floor(log10(v)) <= v, but v <= 10^ceil(log10(v)). |
+ // Note that f is bounded by its container size. Let p = 53 (the double's |
+ // significand size). Then 2^(p-1) <= f < 2^p. |
+ // |
+ // Given that log10(v) == log2(v)/log2(10) and e+(len(f)-1) is quite close |
+ // to log2(v) the function is simplified to (e+(len(f)-1)/log2(10)). |
+ // The computed number undershoots by less than 0.631 (when we compute log3 |
+ // and not log10). |
+ // |
+ // Optimization: since we only need an approximated result this computation |
+ // can be performed on 64 bit integers. On x86/x64 architecture the speedup is |
+ // not really measurable, though. |
+ // |
+ // Since we want to avoid overshooting we decrement by 1e10 so that |
+ // floating-point imprecisions don't affect us. |
+ // |
+ // Explanation for v's boundary m+: the computation takes advantage of |
+ // the fact that 2^(p-1) <= f < 2^p. Boundaries still satisfy this requirement |
+ // (even for denormals where the delta can be much more important). |
+ |
+ const double k1Log10 = 0.30102999566398114; // 1/lg(10) |
+ |
+ // For doubles len(f) == 53 (don't forget the hidden bit). |
+ const int kSignificandSize = 53; |
+ double estimate = ceil((exponent + kSignificandSize - 1) * k1Log10 - 1e-10); |
+ return static_cast<int>(estimate); |
+} |
+ |
+ |
+// See comments for InitialScaledStartValues. |
+static void InitialScaledStartValuesPositiveExponent( |
+ double v, int estimated_power, bool need_boundary_deltas, |
+ Bignum* numerator, Bignum* denominator, |
+ Bignum* delta_minus, Bignum* delta_plus) { |
+ // A positive exponent implies a positive power. |
+ ASSERT(estimated_power >= 0); |
+ // Since the estimated_power is positive we simply multiply the denominator |
+ // by 10^estimated_power. |
+ |
+ // numerator = v. |
+ numerator->AssignUInt64(Double(v).Significand()); |
+ numerator->ShiftLeft(Double(v).Exponent()); |
+ // denominator = 10^estimated_power. |
+ denominator->AssignPowerUInt16(10, estimated_power); |
+ |
+ if (need_boundary_deltas) { |
+ // Introduce a common denominator so that the deltas to the boundaries are |
+ // integers. |
+ denominator->ShiftLeft(1); |
+ numerator->ShiftLeft(1); |
+ // Let v = f * 2^e, then m+ - v = 1/2 * 2^e; With the common |
+ // denominator (of 2) delta_plus equals 2^e. |
+ delta_plus->AssignUInt16(1); |
+ delta_plus->ShiftLeft(Double(v).Exponent()); |
+ // Same for delta_minus (with adjustments below if f == 2^p-1). |
+ delta_minus->AssignUInt16(1); |
+ delta_minus->ShiftLeft(Double(v).Exponent()); |
+ |
+ // If the significand (without the hidden bit) is 0, then the lower |
+ // boundary is closer than just half a ulp (unit in the last place). |
+ // There is only one exception: if the next lower number is a denormal then |
+ // the distance is 1 ulp. This cannot be the case for exponent >= 0 (but we |
+ // have to test it in the other function where exponent < 0). |
+ uint64_t v_bits = Double(v).AsUint64(); |
+ if ((v_bits & Double::kSignificandMask) == 0) { |
+ // The lower boundary is closer at half the distance of "normal" numbers. |
+ // Increase the common denominator and adapt all but the delta_minus. |
+ denominator->ShiftLeft(1); // *2 |
+ numerator->ShiftLeft(1); // *2 |
+ delta_plus->ShiftLeft(1); // *2 |
+ } |
+ } |
+} |
+ |
+ |
+// See comments for InitialScaledStartValues |
+static void InitialScaledStartValuesNegativeExponentPositivePower( |
+ double v, int estimated_power, bool need_boundary_deltas, |
+ Bignum* numerator, Bignum* denominator, |
+ Bignum* delta_minus, Bignum* delta_plus) { |
+ uint64_t significand = Double(v).Significand(); |
+ int exponent = Double(v).Exponent(); |
+ // v = f * 2^e with e < 0, and with estimated_power >= 0. |
+ // This means that e is close to 0 (have a look at how estimated_power is |
+ // computed). |
+ |
+ // numerator = significand |
+ // since v = significand * 2^exponent this is equivalent to |
+ // numerator = v * / 2^-exponent |
+ numerator->AssignUInt64(significand); |
+ // denominator = 10^estimated_power * 2^-exponent (with exponent < 0) |
+ denominator->AssignPowerUInt16(10, estimated_power); |
+ denominator->ShiftLeft(-exponent); |
+ |
+ if (need_boundary_deltas) { |
+ // Introduce a common denominator so that the deltas to the boundaries are |
+ // integers. |
+ denominator->ShiftLeft(1); |
+ numerator->ShiftLeft(1); |
+ // Let v = f * 2^e, then m+ - v = 1/2 * 2^e; With the common |
+ // denominator (of 2) delta_plus equals 2^e. |
+ // Given that the denominator already includes v's exponent the distance |
+ // to the boundaries is simply 1. |
+ delta_plus->AssignUInt16(1); |
+ // Same for delta_minus (with adjustments below if f == 2^p-1). |
+ delta_minus->AssignUInt16(1); |
+ |
+ // If the significand (without the hidden bit) is 0, then the lower |
+ // boundary is closer than just one ulp (unit in the last place). |
+ // There is only one exception: if the next lower number is a denormal |
+ // then the distance is 1 ulp. Since the exponent is close to zero |
+ // (otherwise estimated_power would have been negative) this cannot happen |
+ // here either. |
+ uint64_t v_bits = Double(v).AsUint64(); |
+ if ((v_bits & Double::kSignificandMask) == 0) { |
+ // The lower boundary is closer at half the distance of "normal" numbers. |
+ // Increase the denominator and adapt all but the delta_minus. |
+ denominator->ShiftLeft(1); // *2 |
+ numerator->ShiftLeft(1); // *2 |
+ delta_plus->ShiftLeft(1); // *2 |
+ } |
+ } |
+} |
+ |
+ |
+// See comments for InitialScaledStartValues |
+static void InitialScaledStartValuesNegativeExponentNegativePower( |
+ double v, int estimated_power, bool need_boundary_deltas, |
+ Bignum* numerator, Bignum* denominator, |
+ Bignum* delta_minus, Bignum* delta_plus) { |
+ const uint64_t kMinimalNormalizedExponent = |
+ UINT64_2PART_C(0x00100000, 00000000); |
+ uint64_t significand = Double(v).Significand(); |
+ int exponent = Double(v).Exponent(); |
+ // Instead of multiplying the denominator with 10^estimated_power we |
+ // multiply all values (numerator and deltas) by 10^-estimated_power. |
+ |
+ // Use numerator as temporary container for power_ten. |
+ Bignum* power_ten = numerator; |
+ power_ten->AssignPowerUInt16(10, -estimated_power); |
+ |
+ if (need_boundary_deltas) { |
+ // Since power_ten == numerator we must make a copy of 10^estimated_power |
+ // before we complete the computation of the numerator. |
+ // delta_plus = delta_minus = 10^estimated_power |
+ delta_plus->AssignBignum(*power_ten); |
+ delta_minus->AssignBignum(*power_ten); |
+ } |
+ |
+ // numerator = significand * 2 * 10^-estimated_power |
+ // since v = significand * 2^exponent this is equivalent to |
+ // numerator = v * 10^-estimated_power * 2 * 2^-exponent. |
+ // Remember: numerator has been abused as power_ten. So no need to assign it |
+ // to itself. |
+ ASSERT(numerator == power_ten); |
+ numerator->MultiplyByUInt64(significand); |
+ |
+ // denominator = 2 * 2^-exponent with exponent < 0. |
+ denominator->AssignUInt16(1); |
+ denominator->ShiftLeft(-exponent); |
+ |
+ if (need_boundary_deltas) { |
+ // Introduce a common denominator so that the deltas to the boundaries are |
+ // integers. |
+ numerator->ShiftLeft(1); |
+ denominator->ShiftLeft(1); |
+ // With this shift the boundaries have their correct value, since |
+ // delta_plus = 10^-estimated_power, and |
+ // delta_minus = 10^-estimated_power. |
+ // These assignments have been done earlier. |
+ |
+ // The special case where the lower boundary is twice as close. |
+ // This time we have to look out for the exception too. |
+ uint64_t v_bits = Double(v).AsUint64(); |
+ if ((v_bits & Double::kSignificandMask) == 0 && |
+ // The only exception where a significand == 0 has its boundaries at |
+ // "normal" distances: |
+ (v_bits & Double::kExponentMask) != kMinimalNormalizedExponent) { |
+ numerator->ShiftLeft(1); // *2 |
+ denominator->ShiftLeft(1); // *2 |
+ delta_plus->ShiftLeft(1); // *2 |
+ } |
+ } |
+} |
+ |
+ |
+// Let v = significand * 2^exponent. |
+// Computes v / 10^estimated_power exactly, as a ratio of two bignums, numerator |
+// and denominator. The functions GenerateShortestDigits and |
+// GenerateCountedDigits will then convert this ratio to its decimal |
+// representation d, with the required accuracy. |
+// Then d * 10^estimated_power is the representation of v. |
+// (Note: the fraction and the estimated_power might get adjusted before |
+// generating the decimal representation.) |
+// |
+// The initial start values consist of: |
+// - a scaled numerator: s.t. numerator/denominator == v / 10^estimated_power. |
+// - a scaled (common) denominator. |
+// optionally (used by GenerateShortestDigits to decide if it has the shortest |
+// decimal converting back to v): |
+// - v - m-: the distance to the lower boundary. |
+// - m+ - v: the distance to the upper boundary. |
+// |
+// v, m+, m-, and therefore v - m- and m+ - v all share the same denominator. |
+// |
+// Let ep == estimated_power, then the returned values will satisfy: |
+// v / 10^ep = numerator / denominator. |
+// v's boundarys m- and m+: |
+// m- / 10^ep == v / 10^ep - delta_minus / denominator |
+// m+ / 10^ep == v / 10^ep + delta_plus / denominator |
+// Or in other words: |
+// m- == v - delta_minus * 10^ep / denominator; |
+// m+ == v + delta_plus * 10^ep / denominator; |
+// |
+// Since 10^(k-1) <= v < 10^k (with k == estimated_power) |
+// or 10^k <= v < 10^(k+1) |
+// we then have 0.1 <= numerator/denominator < 1 |
+// or 1 <= numerator/denominator < 10 |
+// |
+// It is then easy to kickstart the digit-generation routine. |
+// |
+// The boundary-deltas are only filled if need_boundary_deltas is set. |
+static void InitialScaledStartValues(double v, |
+ int estimated_power, |
+ bool need_boundary_deltas, |
+ Bignum* numerator, |
+ Bignum* denominator, |
+ Bignum* delta_minus, |
+ Bignum* delta_plus) { |
+ if (Double(v).Exponent() >= 0) { |
+ InitialScaledStartValuesPositiveExponent( |
+ v, estimated_power, need_boundary_deltas, |
+ numerator, denominator, delta_minus, delta_plus); |
+ } else if (estimated_power >= 0) { |
+ InitialScaledStartValuesNegativeExponentPositivePower( |
+ v, estimated_power, need_boundary_deltas, |
+ numerator, denominator, delta_minus, delta_plus); |
+ } else { |
+ InitialScaledStartValuesNegativeExponentNegativePower( |
+ v, estimated_power, need_boundary_deltas, |
+ numerator, denominator, delta_minus, delta_plus); |
+ } |
+} |
+ |
+ |
+// This routine multiplies numerator/denominator so that its values lies in the |
+// range 1-10. That is after a call to this function we have: |
+// 1 <= (numerator + delta_plus) /denominator < 10. |
+// Let numerator the input before modification and numerator' the argument |
+// after modification, then the output-parameter decimal_point is such that |
+// numerator / denominator * 10^estimated_power == |
+// numerator' / denominator' * 10^(decimal_point - 1) |
+// In some cases estimated_power was too low, and this is already the case. We |
+// then simply adjust the power so that 10^(k-1) <= v < 10^k (with k == |
+// estimated_power) but do not touch the numerator or denominator. |
+// Otherwise the routine multiplies the numerator and the deltas by 10. |
+static void FixupMultiply10(int estimated_power, bool is_even, |
+ int* decimal_point, |
+ Bignum* numerator, Bignum* denominator, |
+ Bignum* delta_minus, Bignum* delta_plus) { |
+ bool in_range; |
+ if (is_even) { |
+ // For IEEE doubles half-way cases (in decimal system numbers ending with 5) |
+ // are rounded to the closest floating-point number with even significand. |
+ in_range = Bignum::PlusCompare(*numerator, *delta_plus, *denominator) >= 0; |
+ } else { |
+ in_range = Bignum::PlusCompare(*numerator, *delta_plus, *denominator) > 0; |
+ } |
+ if (in_range) { |
+ // Since numerator + delta_plus >= denominator we already have |
+ // 1 <= numerator/denominator < 10. Simply update the estimated_power. |
+ *decimal_point = estimated_power + 1; |
+ } else { |
+ *decimal_point = estimated_power; |
+ numerator->Times10(); |
+ if (Bignum::Equal(*delta_minus, *delta_plus)) { |
+ delta_minus->Times10(); |
+ delta_plus->AssignBignum(*delta_minus); |
+ } else { |
+ delta_minus->Times10(); |
+ delta_plus->Times10(); |
+ } |
+ } |
+} |
+ |
+} // namespace double_conversion |