Make super() a syntax error in base class constructor

test/mjsunit/harmony/classes-experimental.js

 // Copyright 2014 the V8 project authors. All rights reserved.
 // Use of this source code is governed by a BSD-style license that can be
 // found in the LICENSE file.
 //
 // Flags: --harmony-classes
 
 'use strict';
 (function TestArgumentsAccess() {
   class Base {
     constructor() {
@@ skipping 146 matching lines @@
       assertEquals(1, fCalled);
       assertEquals(1, baseCalled);
       assertSame(obj, this);
     }
   }
 
   new Subclass1();
 }());
 
 
-(function TestSuperInBaseConstructors() {
-  class Base {
-    constructor() {
-      let exn = null;
-      try {
-        super();
-      } catch (e) {
-        exn = e;
-      }
-      assertTrue(exn instanceof ReferenceError);
-    }
-  }
-
-  new Base();
-}());
-
-
 (function TestPrototypeWiring() {
   class Base {
     constructor(x) {
       this.foobar = x;
     }
   }
 
   class Subclass extends Base {
     constructor(x) {
       super(x);
@@ skipping 153 matching lines @@
   var eua = new ExtendedUint8Array(10);
   assertEquals(10, eua.length);
   assertEquals(10, eua.byteLength);
   eua[0] = 0xFF;
   eua[1] = 0xFFA;
   assertEquals(0xFF, eua[0]);
   assertEquals(0xFA, eua[1]);
   assertSame(ExtendedUint8Array.prototype, eua.__proto__);
   assertEquals("[object Uint8Array]", Object.prototype.toString.call(eua));
 }());