Index: experimental/Intersection/LineCubicIntersection.cpp |
diff --git a/experimental/Intersection/LineCubicIntersection.cpp b/experimental/Intersection/LineCubicIntersection.cpp |
deleted file mode 100644 |
index c433fc2a29349e8ba8ab54a76c458b5fa917fb65..0000000000000000000000000000000000000000 |
--- a/experimental/Intersection/LineCubicIntersection.cpp |
+++ /dev/null |
@@ -1,296 +0,0 @@ |
-/* |
- * Copyright 2012 Google Inc. |
- * |
- * Use of this source code is governed by a BSD-style license that can be |
- * found in the LICENSE file. |
- */ |
-#include "CurveIntersection.h" |
-#include "CubicUtilities.h" |
-#include "Intersections.h" |
-#include "LineUtilities.h" |
- |
-/* |
-Find the interection of a line and cubic by solving for valid t values. |
- |
-Analogous to line-quadratic intersection, solve line-cubic intersection by |
-representing the cubic as: |
- x = a(1-t)^3 + 2b(1-t)^2t + c(1-t)t^2 + dt^3 |
- y = e(1-t)^3 + 2f(1-t)^2t + g(1-t)t^2 + ht^3 |
-and the line as: |
- y = i*x + j (if the line is more horizontal) |
-or: |
- x = i*y + j (if the line is more vertical) |
- |
-Then using Mathematica, solve for the values of t where the cubic intersects the |
-line: |
- |
- (in) Resultant[ |
- a*(1 - t)^3 + 3*b*(1 - t)^2*t + 3*c*(1 - t)*t^2 + d*t^3 - x, |
- e*(1 - t)^3 + 3*f*(1 - t)^2*t + 3*g*(1 - t)*t^2 + h*t^3 - i*x - j, x] |
- (out) -e + j + |
- 3 e t - 3 f t - |
- 3 e t^2 + 6 f t^2 - 3 g t^2 + |
- e t^3 - 3 f t^3 + 3 g t^3 - h t^3 + |
- i ( a - |
- 3 a t + 3 b t + |
- 3 a t^2 - 6 b t^2 + 3 c t^2 - |
- a t^3 + 3 b t^3 - 3 c t^3 + d t^3 ) |
- |
-if i goes to infinity, we can rewrite the line in terms of x. Mathematica: |
- |
- (in) Resultant[ |
- a*(1 - t)^3 + 3*b*(1 - t)^2*t + 3*c*(1 - t)*t^2 + d*t^3 - i*y - j, |
- e*(1 - t)^3 + 3*f*(1 - t)^2*t + 3*g*(1 - t)*t^2 + h*t^3 - y, y] |
- (out) a - j - |
- 3 a t + 3 b t + |
- 3 a t^2 - 6 b t^2 + 3 c t^2 - |
- a t^3 + 3 b t^3 - 3 c t^3 + d t^3 - |
- i ( e - |
- 3 e t + 3 f t + |
- 3 e t^2 - 6 f t^2 + 3 g t^2 - |
- e t^3 + 3 f t^3 - 3 g t^3 + h t^3 ) |
- |
-Solving this with Mathematica produces an expression with hundreds of terms; |
-instead, use Numeric Solutions recipe to solve the cubic. |
- |
-The near-horizontal case, in terms of: Ax^3 + Bx^2 + Cx + D == 0 |
- A = (-(-e + 3*f - 3*g + h) + i*(-a + 3*b - 3*c + d) ) |
- B = 3*(-( e - 2*f + g ) + i*( a - 2*b + c ) ) |
- C = 3*(-(-e + f ) + i*(-a + b ) ) |
- D = (-( e ) + i*( a ) + j ) |
- |
-The near-vertical case, in terms of: Ax^3 + Bx^2 + Cx + D == 0 |
- A = ( (-a + 3*b - 3*c + d) - i*(-e + 3*f - 3*g + h) ) |
- B = 3*( ( a - 2*b + c ) - i*( e - 2*f + g ) ) |
- C = 3*( (-a + b ) - i*(-e + f ) ) |
- D = ( ( a ) - i*( e ) - j ) |
- |
-For horizontal lines: |
-(in) Resultant[ |
- a*(1 - t)^3 + 3*b*(1 - t)^2*t + 3*c*(1 - t)*t^2 + d*t^3 - j, |
- e*(1 - t)^3 + 3*f*(1 - t)^2*t + 3*g*(1 - t)*t^2 + h*t^3 - y, y] |
-(out) e - j - |
- 3 e t + 3 f t + |
- 3 e t^2 - 6 f t^2 + 3 g t^2 - |
- e t^3 + 3 f t^3 - 3 g t^3 + h t^3 |
-So the cubic coefficients are: |
- |
- */ |
- |
-class LineCubicIntersections { |
-public: |
- |
-LineCubicIntersections(const Cubic& c, const _Line& l, Intersections& i) |
- : cubic(c) |
- , line(l) |
- , intersections(i) { |
-} |
- |
-// see parallel routine in line quadratic intersections |
-int intersectRay(double roots[3]) { |
- double adj = line[1].x - line[0].x; |
- double opp = line[1].y - line[0].y; |
- Cubic r; |
- for (int n = 0; n < 4; ++n) { |
- r[n].x = (cubic[n].y - line[0].y) * adj - (cubic[n].x - line[0].x) * opp; |
- } |
- double A, B, C, D; |
- coefficients(&r[0].x, A, B, C, D); |
- return cubicRootsValidT(A, B, C, D, roots); |
-} |
- |
-int intersect() { |
- addEndPoints(); |
- double rootVals[3]; |
- int roots = intersectRay(rootVals); |
- for (int index = 0; index < roots; ++index) { |
- double cubicT = rootVals[index]; |
- double lineT = findLineT(cubicT); |
- if (pinTs(cubicT, lineT)) { |
- _Point pt; |
- xy_at_t(line, lineT, pt.x, pt.y); |
- intersections.insert(cubicT, lineT, pt); |
- } |
- } |
- return intersections.fUsed; |
-} |
- |
-int horizontalIntersect(double axisIntercept, double roots[3]) { |
- double A, B, C, D; |
- coefficients(&cubic[0].y, A, B, C, D); |
- D -= axisIntercept; |
- return cubicRootsValidT(A, B, C, D, roots); |
-} |
- |
-int horizontalIntersect(double axisIntercept, double left, double right, bool flipped) { |
- addHorizontalEndPoints(left, right, axisIntercept); |
- double rootVals[3]; |
- int roots = horizontalIntersect(axisIntercept, rootVals); |
- for (int index = 0; index < roots; ++index) { |
- _Point pt; |
- double cubicT = rootVals[index]; |
- xy_at_t(cubic, cubicT, pt.x, pt.y); |
- double lineT = (pt.x - left) / (right - left); |
- if (pinTs(cubicT, lineT)) { |
- intersections.insert(cubicT, lineT, pt); |
- } |
- } |
- if (flipped) { |
- flip(); |
- } |
- return intersections.fUsed; |
-} |
- |
-int verticalIntersect(double axisIntercept, double roots[3]) { |
- double A, B, C, D; |
- coefficients(&cubic[0].x, A, B, C, D); |
- D -= axisIntercept; |
- return cubicRootsValidT(A, B, C, D, roots); |
-} |
- |
-int verticalIntersect(double axisIntercept, double top, double bottom, bool flipped) { |
- addVerticalEndPoints(top, bottom, axisIntercept); |
- double rootVals[3]; |
- int roots = verticalIntersect(axisIntercept, rootVals); |
- for (int index = 0; index < roots; ++index) { |
- _Point pt; |
- double cubicT = rootVals[index]; |
- xy_at_t(cubic, cubicT, pt.x, pt.y); |
- double lineT = (pt.y - top) / (bottom - top); |
- if (pinTs(cubicT, lineT)) { |
- intersections.insert(cubicT, lineT, pt); |
- } |
- } |
- if (flipped) { |
- flip(); |
- } |
- return intersections.fUsed; |
-} |
- |
-protected: |
- |
-void addEndPoints() |
-{ |
- for (int cIndex = 0; cIndex < 4; cIndex += 3) { |
- for (int lIndex = 0; lIndex < 2; lIndex++) { |
- if (cubic[cIndex] == line[lIndex]) { |
- intersections.insert(cIndex >> 1, lIndex, line[lIndex]); |
- } |
- } |
- } |
-} |
- |
-void addHorizontalEndPoints(double left, double right, double y) |
-{ |
- for (int cIndex = 0; cIndex < 4; cIndex += 3) { |
- if (cubic[cIndex].y != y) { |
- continue; |
- } |
- if (cubic[cIndex].x == left) { |
- intersections.insert(cIndex >> 1, 0, cubic[cIndex]); |
- } |
- if (cubic[cIndex].x == right) { |
- intersections.insert(cIndex >> 1, 1, cubic[cIndex]); |
- } |
- } |
-} |
- |
-void addVerticalEndPoints(double top, double bottom, double x) |
-{ |
- for (int cIndex = 0; cIndex < 4; cIndex += 3) { |
- if (cubic[cIndex].x != x) { |
- continue; |
- } |
- if (cubic[cIndex].y == top) { |
- intersections.insert(cIndex >> 1, 0, cubic[cIndex]); |
- } |
- if (cubic[cIndex].y == bottom) { |
- intersections.insert(cIndex >> 1, 1, cubic[cIndex]); |
- } |
- } |
-} |
- |
-double findLineT(double t) { |
- double x, y; |
- xy_at_t(cubic, t, x, y); |
- double dx = line[1].x - line[0].x; |
- double dy = line[1].y - line[0].y; |
- if (fabs(dx) > fabs(dy)) { |
- return (x - line[0].x) / dx; |
- } |
- return (y - line[0].y) / dy; |
-} |
- |
-void flip() { |
- // OPTIMIZATION: instead of swapping, pass original line, use [1].y - [0].y |
- int roots = intersections.fUsed; |
- for (int index = 0; index < roots; ++index) { |
- intersections.fT[1][index] = 1 - intersections.fT[1][index]; |
- } |
-} |
- |
-static bool pinTs(double& cubicT, double& lineT) { |
- if (!approximately_one_or_less(lineT)) { |
- return false; |
- } |
- if (!approximately_zero_or_more(lineT)) { |
- return false; |
- } |
- if (precisely_less_than_zero(cubicT)) { |
- cubicT = 0; |
- } else if (precisely_greater_than_one(cubicT)) { |
- cubicT = 1; |
- } |
- if (precisely_less_than_zero(lineT)) { |
- lineT = 0; |
- } else if (precisely_greater_than_one(lineT)) { |
- lineT = 1; |
- } |
- return true; |
-} |
- |
-private: |
- |
-const Cubic& cubic; |
-const _Line& line; |
-Intersections& intersections; |
-}; |
- |
-int horizontalIntersect(const Cubic& cubic, double left, double right, double y, |
- double tRange[3]) { |
- LineCubicIntersections c(cubic, *((_Line*) 0), *((Intersections*) 0)); |
- double rootVals[3]; |
- int result = c.horizontalIntersect(y, rootVals); |
- int tCount = 0; |
- for (int index = 0; index < result; ++index) { |
- double x, y; |
- xy_at_t(cubic, rootVals[index], x, y); |
- if (x < left || x > right) { |
- continue; |
- } |
- tRange[tCount++] = rootVals[index]; |
- } |
- return result; |
-} |
- |
-int horizontalIntersect(const Cubic& cubic, double left, double right, double y, |
- bool flipped, Intersections& intersections) { |
- LineCubicIntersections c(cubic, *((_Line*) 0), intersections); |
- return c.horizontalIntersect(y, left, right, flipped); |
-} |
- |
-int verticalIntersect(const Cubic& cubic, double top, double bottom, double x, |
- bool flipped, Intersections& intersections) { |
- LineCubicIntersections c(cubic, *((_Line*) 0), intersections); |
- return c.verticalIntersect(x, top, bottom, flipped); |
-} |
- |
-int intersect(const Cubic& cubic, const _Line& line, Intersections& i) { |
- LineCubicIntersections c(cubic, line, i); |
- return c.intersect(); |
-} |
- |
-int intersectRay(const Cubic& cubic, const _Line& line, Intersections& i) { |
- LineCubicIntersections c(cubic, line, i); |
- return c.intersectRay(i.fT[0]); |
-} |