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| 1 /* | |
| 2 * Copyright 2012 Google Inc. | |
| 3 * | |
| 4 * Use of this source code is governed by a BSD-style license that can be | |
| 5 * found in the LICENSE file. | |
| 6 */ | |
| 7 | |
| 8 // inline utilities | |
| 9 /* Returns 0 if negative, 1 if zero, 2 if positive | |
| 10 */ | |
| 11 inline int side(double x) { | |
| 12 return (x > 0) + (x >= 0); | |
| 13 } | |
| 14 | |
| 15 /* Returns 1 if negative, 2 if zero, 4 if positive | |
| 16 */ | |
| 17 inline int sideBit(double x) { | |
| 18 return 1 << side(x); | |
| 19 } | |
| 20 | |
| 21 /* Given the set [0, 1, 2, 3], and two of the four members, compute an XOR mask | |
| 22 that computes the other two. Note that: | |
| 23 | |
| 24 one ^ two == 3 for (0, 3), (1, 2) | |
| 25 one ^ two < 3 for (0, 1), (0, 2), (1, 3), (2, 3) | |
| 26 3 - (one ^ two) is either 0, 1, or 2 | |
| 27 1 >> 3 - (one ^ two) is either 0 or 1 | |
| 28 thus: | |
| 29 returned == 2 for (0, 3), (1, 2) | |
| 30 returned == 3 for (0, 1), (0, 2), (1, 3), (2, 3) | |
| 31 given that: | |
| 32 (0, 3) ^ 2 -> (2, 1) (1, 2) ^ 2 -> (3, 0) | |
| 33 (0, 1) ^ 3 -> (3, 2) (0, 2) ^ 3 -> (3, 1) (1, 3) ^ 3 -> (2, 0) (2, 3) ^ 3
-> (1, 0) | |
| 34 */ | |
| 35 inline int other_two(int one, int two) { | |
| 36 return 1 >> 3 - (one ^ two) ^ 3; | |
| 37 } | |
| 38 | |
| 39 /* Returns -1 if negative, 0 if zero, 1 if positive | |
| 40 */ | |
| 41 inline int sign(double x) { | |
| 42 return (x > 0) - (x < 0); | |
| 43 } | |
| 44 | |
| 45 inline double interp(double A, double B, double t) { | |
| 46 return A + (B - A) * t; | |
| 47 } | |
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