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| 1 /* | |
| 2 * Copyright 2012 Google Inc. | |
| 3 * | |
| 4 * Use of this source code is governed by a BSD-style license that can be | |
| 5 * found in the LICENSE file. | |
| 6 */ | |
| 7 | |
| 8 #include "SkTileGrid.h" | |
| 9 | |
| 10 SkTileGrid::SkTileGrid(int xTiles, int yTiles, const SkTileGridFactory::TileGrid
Info& info) | |
| 11 : fXTiles(xTiles) | |
| 12 , fYTiles(yTiles) | |
| 13 , fInvWidth( SkScalarInvert(info.fTileInterval.width())) | |
| 14 , fInvHeight(SkScalarInvert(info.fTileInterval.height())) | |
| 15 , fMarginWidth (info.fMargin.fWidth +1) // Margin is offset by 1 as a provi
sion for AA and | |
| 16 , fMarginHeight(info.fMargin.fHeight+1) // to cancel the outset applied by
getClipDeviceBounds. | |
| 17 , fOffset(SkPoint::Make(info.fOffset.fX, info.fOffset.fY)) | |
| 18 , fGridBounds(SkRect::MakeWH(xTiles * info.fTileInterval.width(), | |
| 19 yTiles * info.fTileInterval.height())) | |
| 20 , fTiles(SkNEW_ARRAY(SkTDArray<unsigned>, xTiles * yTiles)) {} | |
| 21 | |
| 22 SkTileGrid::~SkTileGrid() { | |
| 23 SkDELETE_ARRAY(fTiles); | |
| 24 } | |
| 25 | |
| 26 void SkTileGrid::reserve(int opCount) { | |
| 27 if (fXTiles * fYTiles == 0) { | |
| 28 return; // A tileless tile grid is nonsensical, but happens in at least
cc_unittests. | |
| 29 } | |
| 30 | |
| 31 // If we assume every op we're about to try to insert() falls within our gri
d bounds, | |
| 32 // then every op has to hit at least one tile. In fact, a quick scan over o
ur small | |
| 33 // SKP set shows that in the average SKP, each op hits two 256x256 tiles. | |
| 34 | |
| 35 // If we take those observations and further assume the ops are distributed
evenly | |
| 36 // across the picture, we get this guess for number of ops per tile: | |
| 37 const int opsPerTileGuess = (2 * opCount) / (fXTiles * fYTiles); | |
| 38 | |
| 39 for (SkTDArray<unsigned>* tile = fTiles; tile != fTiles + (fXTiles * fYTiles
); tile++) { | |
| 40 tile->setReserve(opsPerTileGuess); | |
| 41 } | |
| 42 | |
| 43 // In practice, this heuristic means we'll temporarily allocate about 30% mo
re bytes | |
| 44 // than if we made no setReserve() calls, but time spent in insert() drops b
y about 50%. | |
| 45 } | |
| 46 | |
| 47 void SkTileGrid::shrinkToFit() { | |
| 48 for (SkTDArray<unsigned>* tile = fTiles; tile != fTiles + (fXTiles * fYTiles
); tile++) { | |
| 49 tile->shrinkToFit(); | |
| 50 } | |
| 51 } | |
| 52 | |
| 53 // Adjustments to user-provided bounds common to both insert() and search(). | |
| 54 // Call this after making insert- or search- specific adjustments. | |
| 55 void SkTileGrid::commonAdjust(SkRect* rect) const { | |
| 56 // Apply our offset. | |
| 57 rect->offset(fOffset); | |
| 58 | |
| 59 // Scrunch the bounds in just a little to make the right and bottom edges | |
| 60 // exclusive. We want bounds of exactly one tile to hit exactly one tile. | |
| 61 rect->fRight -= SK_ScalarNearlyZero; | |
| 62 rect->fBottom -= SK_ScalarNearlyZero; | |
| 63 } | |
| 64 | |
| 65 // Convert user-space bounds to grid tiles they cover (LT and RB both inclusive)
. | |
| 66 void SkTileGrid::userToGrid(const SkRect& user, SkIRect* grid) const { | |
| 67 grid->fLeft = SkPin32(user.left() * fInvWidth , 0, fXTiles - 1); | |
| 68 grid->fTop = SkPin32(user.top() * fInvHeight, 0, fYTiles - 1); | |
| 69 grid->fRight = SkPin32(user.right() * fInvWidth , 0, fXTiles - 1); | |
| 70 grid->fBottom = SkPin32(user.bottom() * fInvHeight, 0, fYTiles - 1); | |
| 71 } | |
| 72 | |
| 73 void SkTileGrid::insert(SkAutoTMalloc<SkRect>* boundsArray, int N) { | |
| 74 this->reserve(N); | |
| 75 | |
| 76 for (int i = 0; i < N; i++) { | |
| 77 SkRect bounds = (*boundsArray)[i]; | |
| 78 bounds.outset(fMarginWidth, fMarginHeight); | |
| 79 this->commonAdjust(&bounds); | |
| 80 | |
| 81 // TODO(mtklein): can we assert this instead to save an intersection in
Release mode, | |
| 82 // or just allow out-of-bound insertions to insert anyway (clamped to ne
arest tile)? | |
| 83 if (!SkRect::Intersects(bounds, fGridBounds)) { | |
| 84 continue; | |
| 85 } | |
| 86 | |
| 87 SkIRect grid; | |
| 88 this->userToGrid(bounds, &grid); | |
| 89 | |
| 90 // This is just a loop over y then x. This compiles to a slightly faste
r and | |
| 91 // more compact loop than if we just did fTiles[y * fXTiles + x].push(i)
. | |
| 92 SkTDArray<unsigned>* row = &fTiles[grid.fTop * fXTiles + grid.fLeft]; | |
| 93 for (int y = 0; y <= grid.fBottom - grid.fTop; y++) { | |
| 94 SkTDArray<unsigned>* tile = row; | |
| 95 for (int x = 0; x <= grid.fRight - grid.fLeft; x++) { | |
| 96 (tile++)->push(i); | |
| 97 } | |
| 98 row += fXTiles; | |
| 99 } | |
| 100 } | |
| 101 this->shrinkToFit(); | |
| 102 } | |
| 103 | |
| 104 // Number of tiles for which data is allocated on the stack in | |
| 105 // SkTileGrid::search. If malloc becomes a bottleneck, we may consider | |
| 106 // increasing this number. Typical large web page, say 2k x 16k, would | |
| 107 // require 512 tiles of size 256 x 256 pixels. | |
| 108 static const int kStackAllocationTileCount = 1024; | |
| 109 | |
| 110 void SkTileGrid::search(const SkRect& originalQuery, SkTDArray<unsigned>* result
s) const { | |
| 111 // The inset counteracts the outset that applied in 'insert', which optimize
s | |
| 112 // for lookups of size 'tileInterval + 2 * margin' (aligned with the tile gr
id). | |
| 113 SkRect query = originalQuery; | |
| 114 query.inset(fMarginWidth, fMarginHeight); | |
| 115 this->commonAdjust(&query); | |
| 116 | |
| 117 // The inset may have inverted the rectangle, so sort(). | |
| 118 // TODO(mtklein): It looks like we only end up with inverted bounds in unit
tests | |
| 119 // that make explicitly inverted queries, not from insetting. If we can dro
p support for | |
| 120 // unsorted bounds (i.e. we don't see them outside unit tests), I think we c
an drop this. | |
| 121 query.sort(); | |
| 122 | |
| 123 // No intersection check. We optimize for queries that are in bounds. | |
| 124 // We're safe anyway: userToGrid() will clamp out-of-bounds queries to neare
st tile. | |
| 125 SkIRect grid; | |
| 126 this->userToGrid(query, &grid); | |
| 127 | |
| 128 const int tilesHit = (grid.fRight - grid.fLeft + 1) * (grid.fBottom - grid.f
Top + 1); | |
| 129 SkASSERT(tilesHit > 0); | |
| 130 | |
| 131 if (tilesHit == 1) { | |
| 132 // A performance shortcut. The merging code below would work fine here
too. | |
| 133 *results = fTiles[grid.fTop * fXTiles + grid.fLeft]; | |
| 134 return; | |
| 135 } | |
| 136 | |
| 137 // We've got to merge the data in many tiles into a single sorted and dedupl
icated stream. | |
| 138 // We do a simple k-way merge based on the value of opIndex. | |
| 139 | |
| 140 // Gather pointers to the starts and ends of the tiles to merge. | |
| 141 SkAutoSTArray<kStackAllocationTileCount, const unsigned*> starts(tilesHit),
ends(tilesHit); | |
| 142 int i = 0; | |
| 143 for (int y = grid.fTop; y <= grid.fBottom; y++) { | |
| 144 for (int x = grid.fLeft; x <= grid.fRight; x++) { | |
| 145 starts[i] = fTiles[y * fXTiles + x].begin(); | |
| 146 ends[i] = fTiles[y * fXTiles + x].end(); | |
| 147 i++; | |
| 148 } | |
| 149 } | |
| 150 | |
| 151 // Merge tiles into results until they're fully consumed. | |
| 152 results->reset(); | |
| 153 while (true) { | |
| 154 // The tiles themselves are already ordered, so the earliest op is at th
e front of some | |
| 155 // tile. It may be at the front of several, even all, tiles. | |
| 156 unsigned earliest = SK_MaxU32; | |
| 157 for (int i = 0; i < starts.count(); i++) { | |
| 158 if (starts[i] < ends[i]) { | |
| 159 earliest = SkTMin(earliest, *starts[i]); | |
| 160 } | |
| 161 } | |
| 162 | |
| 163 // If we didn't find an earliest op, there isn't anything left to merge. | |
| 164 if (SK_MaxU32 == earliest) { | |
| 165 return; | |
| 166 } | |
| 167 | |
| 168 // We did find an earliest op. Output it, and step forward every tile th
at contains it. | |
| 169 results->push(earliest); | |
| 170 for (int i = 0; i < starts.count(); i++) { | |
| 171 if (starts[i] < ends[i] && *starts[i] == earliest) { | |
| 172 starts[i]++; | |
| 173 } | |
| 174 } | |
| 175 } | |
| 176 } | |
| 177 | |
| 178 size_t SkTileGrid::bytesUsed() const { | |
| 179 size_t byteCount = sizeof(SkTileGrid); | |
| 180 | |
| 181 size_t opCount = 0; | |
| 182 for (int i = 0; i < fXTiles * fYTiles; i++) { | |
| 183 opCount += fTiles[i].reserved(); | |
| 184 } | |
| 185 byteCount += opCount * sizeof(unsigned); | |
| 186 | |
| 187 return byteCount; | |
| 188 } | |
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