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Issue 736003002: Correctly escape RegExp source. (Closed) Base URL: https://chromium.googlesource.com/v8/v8.git@regexpref
Patch Set: Created 6 years, 1 month ago
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1 // Copyright 2014 the V8 project authors. All rights reserved.
2 // Use of this source code is governed by a BSD-style license that can be
3 // found in the LICENSE file.
4
5 // Escape '/'.
6 function testEscapes(expected, regexp) {
7 assertEquals(expected, regexp.source);
8 assertEquals("/" + expected + "/", regexp.toString());
9 }
10
11 testEscapes("\\/", /\//);
12 testEscapes("\\/\\/", /\/\//);
13 testEscapes("\\/", new RegExp("/"));
14 testEscapes("\\/", new RegExp("\\/"));
15 testEscapes("\\\\/", new RegExp("\\\\/"));
16 testEscapes("\\/\\/", new RegExp("\\/\\/"));
17 testEscapes("\\/\\/\\/\\/", new RegExp("////"));
18 testEscapes("\\/\\/\\/\\/", new RegExp("\\//\\//"));
19 testEscapes("(?:)", new RegExp(""));
20 testEscapes("(?:)", RegExp.prototype);
21
22 // Read-only property.
23 var r = /\/\//;
24 testEscapes("\\/\\/", r);
25 r.source = "garbage";
26 testEscapes("\\/\\/", r);
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