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Issue 727673002: [turbofan] Optimize remainder of integer division by unknown power of two. (Closed) Base URL: https://chromium.googlesource.com/v8/v8.git@master
Patch Set: Fix broken Int32Mod on ARM Created 6 years, 1 month ago
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1 // Copyright 2014 the V8 project authors. All rights reserved. 1 // Copyright 2014 the V8 project authors. All rights reserved.
2 // Use of this source code is governed by a BSD-style license that can be 2 // Use of this source code is governed by a BSD-style license that can be
3 // found in the LICENSE file. 3 // found in the LICENSE file.
4 4
5 var stdlib = {}; 5 var stdlib = {};
6 var foreign = {}; 6 var foreign = {};
7 var heap = new ArrayBuffer(64 * 1024); 7 var heap = new ArrayBuffer(64 * 1024);
8 8
9 function Uint32Mod(divisor) { 9 function Uint32Mod(divisor) {
10 var name = "mod_"; 10 var name = "mod_";
11 name += divisor; 11 name += divisor;
12 var m = eval("function Module(stdlib, foreign, heap) {\n" 12 var m = eval("function Module(stdlib, foreign, heap) {\n"
13 + " \"use asm\";\n" 13 + " \"use asm\";\n"
14 + " function " + name + "(dividend) {\n" 14 + " function " + name + "(dividend) {\n"
15 + " return ((dividend >>> 0) % " + divisor + ") >>> 0;\n" 15 + " return ((dividend >>> 0) % " + divisor + ") >>> 0;\n"
16 + " }\n" 16 + " }\n"
17 + " return { f: " + name + "}\n" 17 + " return { f: " + name + "}\n"
18 + "}; Module"); 18 + "}; Module");
19 return m(stdlib, foreign, heap).f; 19 return m(stdlib, foreign, heap).f;
20 } 20 }
21 21
22 var divisors = [0, 1, 3, 4, 10, 42, 64, 100, 1024, 2147483647, 4294967295]; 22 var divisors = [0, 1, 3, 4, 10, 42, 64, 100, 1024, 2147483647, 4294967295];
23 for (var i in divisors) { 23 for (var i in divisors) {
24 var divisor = divisors[i]; 24 var divisor = divisors[i];
25 var mod = Uint32Mod(divisor); 25 var mod = Uint32Mod(divisor);
26 for (var dividend = 0; dividend < 4294967296; dividend += 3999773) { 26 for (var dividend = 0; dividend < 4294967296; dividend += 3999773) {
27 assertEquals((dividend % divisor) >>> 0, mod(dividend)); 27 assertEquals((dividend % divisor) >>> 0, mod(dividend));
28 } 28 }
29 } 29 }
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