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Issue 727673002: [turbofan] Optimize remainder of integer division by unknown power of two. (Closed) Base URL: https://chromium.googlesource.com/v8/v8.git@master
Patch Set: Fix broken Int32Mod on ARM Created 6 years, 1 month ago
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1 // Copyright 2014 the V8 project authors. All rights reserved. 1 // Copyright 2014 the V8 project authors. All rights reserved.
2 // Use of this source code is governed by a BSD-style license that can be 2 // Use of this source code is governed by a BSD-style license that can be
3 // found in the LICENSE file. 3 // found in the LICENSE file.
4 4
5 var stdlib = {}; 5 var stdlib = {};
6 var foreign = {}; 6 var foreign = {};
7 var heap = new ArrayBuffer(64 * 1024); 7 var heap = new ArrayBuffer(64 * 1024);
8 8
9 function Int32Mod(divisor) { 9 var mod = (function Module(stdlib, foreign, heap) {
10 var name = "mod_"; 10 "use asm";
11 if (divisor < 0) { 11 function mod(dividend, divisor) {
12 name += "minus_"; 12 dividend = dividend|0;
13 divisor = divisor|0;
14 return (dividend % divisor) | 0;
13 } 15 }
14 name += Math.abs(divisor); 16 return { mod: mod };
15 var m = eval("function Module(stdlib, foreign, heap) {\n" 17 })(stdlib, foreign, heap).mod;
16 + " \"use asm\";\n"
17 + " function " + name + "(dividend) {\n"
18 + " return ((dividend | 0) % " + divisor + ") | 0;\n"
19 + " }\n"
20 + " return { f: " + name + "}\n"
21 + "}; Module");
22 return m(stdlib, foreign, heap).f;
23 }
24 18
25 var divisors = [-2147483648, -32 * 1024, -1000, -16, -7, -2, -1, 19 var divisors = [-2147483648, -32 * 1024, -1000, -16, -7, -2, -1, 0,
26 1, 3, 4, 10, 64, 100, 1024, 2147483647]; 20 1, 3, 4, 10, 64, 100, 1024, 2147483647];
27 for (var i in divisors) { 21 for (var i in divisors) {
28 var divisor = divisors[i]; 22 var divisor = divisors[i];
29 var mod = Int32Mod(divisor);
30 for (var dividend = -2147483648; dividend < 2147483648; dividend += 3999773) { 23 for (var dividend = -2147483648; dividend < 2147483648; dividend += 3999773) {
31 assertEquals((dividend % divisor) | 0, mod(dividend)); 24 assertEquals((dividend % divisor) | 0, mod(dividend, divisor));
32 } 25 }
33 } 26 }
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