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Side by Side Diff: src/core/SkTileGrid.cpp

Issue 615853007: Stay in floats as much as possible in SkTileGrid, particularly in insert. (Closed) Base URL: https://skia.googlesource.com/skia.git@master
Patch Set: explain better Created 6 years, 2 months ago
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1 /* 1 /*
2 * Copyright 2012 Google Inc. 2 * Copyright 2012 Google Inc.
3 * 3 *
4 * Use of this source code is governed by a BSD-style license that can be 4 * Use of this source code is governed by a BSD-style license that can be
5 * found in the LICENSE file. 5 * found in the LICENSE file.
6 */ 6 */
7 7
8 #include "SkTileGrid.h" 8 #include "SkTileGrid.h"
9 9
10 SkTileGrid::SkTileGrid(int xTiles, int yTiles, const SkTileGridFactory::TileGrid Info& info) 10 SkTileGrid::SkTileGrid(int xTiles, int yTiles, const SkTileGridFactory::TileGrid Info& info)
11 : fXTiles(xTiles) 11 : fXTiles(xTiles)
12 , fYTiles(yTiles) 12 , fYTiles(yTiles)
13 , fInfo(info) 13 , fInvWidth( SkScalarInvert(info.fTileInterval.width()))
14 , fTiles(SkNEW_ARRAY(SkTDArray<unsigned>, xTiles * yTiles)) { 14 , fInvHeight(SkScalarInvert(info.fTileInterval.height()))
15 // Margin is offset by 1 as a provision for AA and 15 , fMarginWidth (info.fMargin.fWidth +1) // Margin is offset by 1 as a provi sion for AA and
16 // to cancel-out the outset applied by getClipDeviceBounds. 16 , fMarginHeight(info.fMargin.fHeight+1) // to cancel the outset applied by getClipDeviceBounds.
17 fInfo.fMargin.fHeight++; 17 , fOffset(SkPoint::Make(info.fOffset.fX, info.fOffset.fY))
18 fInfo.fMargin.fWidth++; 18 , fGridBounds(SkRect::MakeWH(xTiles * info.fTileInterval.width(),
19 } 19 yTiles * info.fTileInterval.height()))
20 , fTiles(SkNEW_ARRAY(SkTDArray<unsigned>, xTiles * yTiles)) {}
20 21
21 SkTileGrid::~SkTileGrid() { 22 SkTileGrid::~SkTileGrid() {
22 SkDELETE_ARRAY(fTiles); 23 SkDELETE_ARRAY(fTiles);
23 } 24 }
24 25
25 void SkTileGrid::insert(unsigned opIndex, const SkRect& fbounds, bool) { 26 // Adjustments to user-provided bounds common to both insert() and search().
26 SkASSERT(!fbounds.isEmpty()); 27 // Call this after making insert- or search- specific adjustments.
28 void SkTileGrid::commonAdjust(SkRect* rect) const {
29 // Apply our offset.
30 rect->offset(fOffset);
27 31
28 SkIRect dilatedBounds; 32 // Scrunch the bounds in just a little to make the right and bottom edges
29 fbounds.roundOut(&dilatedBounds); 33 // exclusive. We want bounds of exactly one tile to hit exactly one tile.
30 dilatedBounds.outset(fInfo.fMargin.width(), fInfo.fMargin.height()); 34 rect->fRight -= SK_ScalarNearlyZero;
31 dilatedBounds.offset(fInfo.fOffset); 35 rect->fBottom -= SK_ScalarNearlyZero;
36 }
32 37
33 const SkIRect gridBounds = 38 // Convert user-space bounds to grid tiles they cover (LT inclusive, RB exclusiv e).
34 { 0, 0, fInfo.fTileInterval.width() * fXTiles, fInfo.fTileInterval.heigh t() * fYTiles }; 39 void SkTileGrid::userToGrid(const SkRect& user, SkIRect* grid) const {
35 if (!SkIRect::Intersects(dilatedBounds, gridBounds)) { 40 grid->fLeft = SkPin32(user.left() * fInvWidth , 0, fXTiles - 1);
41 grid->fTop = SkPin32(user.top() * fInvHeight, 0, fYTiles - 1);
42 grid->fRight = SkPin32(user.right() * fInvWidth , 0, fXTiles - 1) + 1;
43 grid->fBottom = SkPin32(user.bottom() * fInvHeight, 0, fYTiles - 1) + 1;
44 }
45
46 void SkTileGrid::insert(unsigned opIndex, const SkRect& originalBounds, bool) {
47 SkRect bounds = originalBounds;
48 bounds.outset(fMarginWidth, fMarginHeight);
49 this->commonAdjust(&bounds);
50
51 // TODO(mtklein): can we assert this instead to save an intersection in Rele ase mode,
52 // or just allow out-of-bound insertions to insert anyway (clamped to neares t tile)?
53 if (!SkRect::Intersects(bounds, fGridBounds)) {
36 return; 54 return;
37 } 55 }
38 56
39 // Note: SkIRects are non-inclusive of the right() column and bottom() row, 57 SkIRect grid;
40 // hence the "-1"s in the computations of maxX and maxY. 58 this->userToGrid(bounds, &grid);
41 int minX = SkMax32(0, SkMin32(dilatedBounds.left() / fInfo.fTileInterval.wid th(), fXTiles - 1));
42 int minY = SkMax32(0, SkMin32(dilatedBounds.top() / fInfo.fTileInterval.heig ht(), fYTiles - 1));
43 int maxX = SkMax32(0, SkMin32((dilatedBounds.right() - 1) / fInfo.fTileInte rval.width(),
44 fXTiles - 1));
45 int maxY = SkMax32(0, SkMin32((dilatedBounds.bottom() - 1) / fInfo.fTileInte rval.height(),
46 fYTiles - 1));
47 59
48 for (int y = minY; y <= maxY; y++) { 60 for (int y = grid.fTop; y < grid.fBottom; y++) {
49 for (int x = minX; x <= maxX; x++) { 61 for (int x = grid.fLeft; x < grid.fRight; x++) {
50 fTiles[y * fXTiles + x].push(opIndex); 62 fTiles[y * fXTiles + x].push(opIndex);
51 } 63 }
52 } 64 }
53 } 65 }
54 66
55 static int divide_ceil(int x, int y) {
56 return (x + y - 1) / y;
57 }
58
59 // Number of tiles for which data is allocated on the stack in 67 // Number of tiles for which data is allocated on the stack in
60 // SkTileGrid::search. If malloc becomes a bottleneck, we may consider 68 // SkTileGrid::search. If malloc becomes a bottleneck, we may consider
61 // increasing this number. Typical large web page, say 2k x 16k, would 69 // increasing this number. Typical large web page, say 2k x 16k, would
62 // require 512 tiles of size 256 x 256 pixels. 70 // require 512 tiles of size 256 x 256 pixels.
63 static const int kStackAllocationTileCount = 1024; 71 static const int kStackAllocationTileCount = 1024;
64 72
65 void SkTileGrid::search(const SkRect& query, SkTDArray<unsigned>* results) const { 73 void SkTileGrid::search(const SkRect& originalQuery, SkTDArray<unsigned>* result s) const {
66 SkIRect adjusted; 74 // The inset counteracts the outset that applied in 'insert', which optimize s
67 query.roundOut(&adjusted); 75 // for lookups of size 'tileInterval + 2 * margin' (aligned with the tile gr id).
76 SkRect query = originalQuery;
77 query.inset(fMarginWidth, fMarginHeight);
78 this->commonAdjust(&query);
68 79
69 // The inset is to counteract the outset that was applied in 'insert' 80 // The inset may have inverted the rectangle, so sort().
70 // The outset/inset is to optimize for lookups of size 81 // TODO(mtklein): It looks like we only end up with inverted bounds in unit tests
71 // 'tileInterval + 2 * margin' that are aligned with the tile grid. 82 // that make explicitly inverted queries, not from insetting. If we can dro p support for
72 adjusted.inset(fInfo.fMargin.width(), fInfo.fMargin.height()); 83 // unsorted bounds (i.e. we don't see them outside unit tests), I think we c an drop this.
73 adjusted.offset(fInfo.fOffset); 84 query.sort();
74 adjusted.sort(); // in case the inset inverted the rectangle
75 85
76 // Convert the query rectangle from device coordinates to tile coordinates 86 // No intersection check. We optimize for queries that are in bounds.
77 // by rounding outwards to the nearest tile boundary so that the resulting t ile 87 // We're safe anyway: userToGrid() will clamp out-of-bounds queries to neare st tile.
78 // region includes the query rectangle. 88 SkIRect grid;
79 int startX = adjusted.left() / fInfo.fTileInterval.width(), 89 this->userToGrid(query, &grid);
80 startY = adjusted.top() / fInfo.fTileInterval.height();
81 int endX = divide_ceil(adjusted.right(), fInfo.fTileInterval.width()),
82 endY = divide_ceil(adjusted.bottom(), fInfo.fTileInterval.height());
83 90
84 // Logically, we could pin endX to [startX, fXTiles], but we force it 91 const int tilesHit = (grid.fRight - grid.fLeft) * (grid.fBottom - grid.fTop) ;
85 // up to (startX, fXTiles] to make sure we hit at least one tile.
86 // This snaps just-out-of-bounds queries to the neighboring border tile.
87 // I don't know if this is an important feature outside of unit tests.
88 startX = SkPin32(startX, 0, fXTiles - 1);
89 startY = SkPin32(startY, 0, fYTiles - 1);
90 endX = SkPin32(endX, startX + 1, fXTiles);
91 endY = SkPin32(endY, startY + 1, fYTiles);
92
93 const int tilesHit = (endX - startX) * (endY - startY);
94 SkASSERT(tilesHit > 0); 92 SkASSERT(tilesHit > 0);
95 93
96 if (tilesHit == 1) { 94 if (tilesHit == 1) {
97 // A performance shortcut. The merging code below would work fine here too. 95 // A performance shortcut. The merging code below would work fine here too.
98 *results = fTiles[startY * fXTiles + startX]; 96 *results = fTiles[grid.fTop * fXTiles + grid.fLeft];
99 return; 97 return;
100 } 98 }
101 99
102 // We've got to merge the data in many tiles into a single sorted and dedupl icated stream. 100 // We've got to merge the data in many tiles into a single sorted and dedupl icated stream.
103 // We do a simple k-way merge based on the value of opIndex. 101 // We do a simple k-way merge based on the value of opIndex.
104 102
105 // Gather pointers to the starts and ends of the tiles to merge. 103 // Gather pointers to the starts and ends of the tiles to merge.
106 SkAutoSTArray<kStackAllocationTileCount, const unsigned*> starts(tilesHit), ends(tilesHit); 104 SkAutoSTArray<kStackAllocationTileCount, const unsigned*> starts(tilesHit), ends(tilesHit);
107 int i = 0; 105 int i = 0;
108 for (int x = startX; x < endX; x++) { 106 for (int y = grid.fTop; y < grid.fBottom; y++) {
109 for (int y = startY; y < endY; y++) { 107 for (int x = grid.fLeft; x < grid.fRight; x++) {
110 starts[i] = fTiles[y * fXTiles + x].begin(); 108 starts[i] = fTiles[y * fXTiles + x].begin();
111 ends[i] = fTiles[y * fXTiles + x].end(); 109 ends[i] = fTiles[y * fXTiles + x].end();
112 i++; 110 i++;
113 } 111 }
114 } 112 }
115 113
116 // Merge tiles into results until they're fully consumed. 114 // Merge tiles into results until they're fully consumed.
117 results->reset(); 115 results->reset();
118 while (true) { 116 while (true) {
119 // The tiles themselves are already ordered, so the earliest op is at th e front of some 117 // The tiles themselves are already ordered, so the earliest op is at th e front of some
(...skipping 13 matching lines...) Expand all
133 // We did find an earliest op. Output it, and step forward every tile th at contains it. 131 // We did find an earliest op. Output it, and step forward every tile th at contains it.
134 results->push(earliest); 132 results->push(earliest);
135 for (int i = 0; i < starts.count(); i++) { 133 for (int i = 0; i < starts.count(); i++) {
136 if (starts[i] < ends[i] && *starts[i] == earliest) { 134 if (starts[i] < ends[i] && *starts[i] == earliest) {
137 starts[i]++; 135 starts[i]++;
138 } 136 }
139 } 137 }
140 } 138 }
141 } 139 }
142 140
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