[Findit] Fix network timeout.

tools/findit/common/http_client_local.py

 # Copyright (c) 2014 The Chromium Authors. All rights reserved.
 # Use of this source code is governed by a BSD-style license that can be
 # found in the LICENSE file.
 
 """
 A http client with support for https connections with certificate verification.
 
 The verification is based on http://tools.ietf.org/html/rfc6125#section-6.4.3
 and the code is from Lib/ssl.py in python3:
   http://hg.python.org/cpython/file/4dac45f88d45/Lib/ssl.py
@@ skipping 200 matching lines @@
   content = None
 
   try:
     response = url_opener.open(url, timeout=timeout)
 
     status_code = response.code
     content = response.read()
   except urllib2.HTTPError as e:
     status_code = e.code
     content = None
+  except (ssl.SSLError, httplib.BadStatusLine, IOError):
+    status_code = -1
+    content = None
 
   return status_code, content
 
 
 class HttpClientLocal(http_client.HttpClient):
   """This http client is used locally in a workstation, GCE VMs, etc."""
 
   @staticmethod
-  def Get(url, params={}, timeout=60, retries=5, retry_interval=0.5,
+  def Get(url, params={}, timeout=120, retries=5, retry_interval=0.5,
           retry_if_not=None):
     if params:
       url = '%s?%s' % (url, urllib.urlencode(params))
 
     count = 0
     while True:
       count += 1
 
       status_code, content = _SendRequest(url, timeout=timeout)
       if status_code == 200:
         return status_code, content
       if retry_if_not and status_code == retry_if_not:
         return status_code, content
 
       if count < retries:
         time.sleep(retry_interval)
       else:
         return status_code, content
 
     # Should never be reached.
     return status_code, content