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Side by Side Diff: src/pathops/SkQuarticRoot.cpp

Issue 52653002: pathops work in progress (Closed) Base URL: https://skia.googlecode.com/svn/trunk
Patch Set: add raster vs gpu test Created 7 years, 1 month ago
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1 // from http://tog.acm.org/resources/GraphicsGems/gems/Roots3And4.c 1 // from http://tog.acm.org/resources/GraphicsGems/gems/Roots3And4.c
2 /* 2 /*
3 * Roots3And4.c 3 * Roots3And4.c
4 * 4 *
5 * Utility functions to find cubic and quartic roots, 5 * Utility functions to find cubic and quartic roots,
6 * coefficients are passed like this: 6 * coefficients are passed like this:
7 * 7 *
8 * c[0] + c[1]*x + c[2]*x^2 + c[3]*x^3 + c[4]*x^4 = 0 8 * c[0] + c[1]*x + c[2]*x^2 + c[3]*x^3 + c[4]*x^4 = 0
9 * 9 *
10 * The functions return the number of non-complex roots and 10 * The functions return the number of non-complex roots and
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64 int num = SkDCubic::RootsReal(t4, t3, t2, t1, roots); 64 int num = SkDCubic::RootsReal(t4, t3, t2, t1, roots);
65 for (int i = 0; i < num; ++i) { 65 for (int i = 0; i < num; ++i) {
66 if (approximately_zero(roots[i])) { 66 if (approximately_zero(roots[i])) {
67 return num; 67 return num;
68 } 68 }
69 } 69 }
70 roots[num++] = 0; 70 roots[num++] = 0;
71 return num; 71 return num;
72 } 72 }
73 if (oneHint) { 73 if (oneHint) {
74 SkASSERT(approximately_zero(t4 + t3 + t2 + t1 + t0)); // 1 is one root 74 SkASSERT(approximately_zero_double(t4 + t3 + t2 + t1 + t0)); // 1 is on e root
75 // note that -C == A + B + D + E 75 // note that -C == A + B + D + E
76 int num = SkDCubic::RootsReal(t4, t4 + t3, -(t1 + t0), -t0, roots); 76 int num = SkDCubic::RootsReal(t4, t4 + t3, -(t1 + t0), -t0, roots);
77 for (int i = 0; i < num; ++i) { 77 for (int i = 0; i < num; ++i) {
78 if (approximately_equal(roots[i], 1)) { 78 if (approximately_equal(roots[i], 1)) {
79 return num; 79 return num;
80 } 80 }
81 } 81 }
82 roots[num++] = 1; 82 roots[num++] = 1;
83 return num; 83 return num;
84 } 84 }
(...skipping 71 matching lines...) Expand 10 before | Expand all | Expand 10 after
156 if (j < --num) { 156 if (j < --num) {
157 s[j] = s[num]; 157 s[j] = s[num];
158 } 158 }
159 } else { 159 } else {
160 ++j; 160 ++j;
161 } 161 }
162 } 162 }
163 } 163 }
164 return num; 164 return num;
165 } 165 }
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