relax quadratic binary search test

src/pathops/SkDQuadIntersection.cpp

 // Another approach is to start with the implicit form of one curve and solve
 // (seek implicit coefficients in QuadraticParameter.cpp
 // by substituting in the parametric form of the other.
 // The downside of this approach is that early rejects are difficult to come by.
 // http://planetmath.org/encyclopedia/GaloisTheoreticDerivationOfTheQuarticFormula.html#step
 
 #include "SkDQuadImplicit.h"
 #include "SkIntersections.h"
 #include "SkPathOpsLine.h"
 #include "SkQuarticRoot.h"
@@ skipping 468 matching lines @@
     double roots2Copy[4];
     int r2Count = addValidRoots(roots2, rootCount2, roots2Copy);
     SkDPoint pts2[4];
     for (index = 0; index < r2Count; ++index) {
         pts2[index] = q2.ptAtT(roots2Copy[index]);
     }
     if (r1Count == r2Count && r1Count <= 1) {
         if (r1Count == 1 && used() == 0) {
             if (pts1[0].approximatelyEqual(pts2[0])) {
                 insert(roots1Copy[0], roots2Copy[0], pts1[0]);
-            } else if (pts1[0].moreRoughlyEqual(pts2[0])) {
-                // experiment: try to find intersection by chasing t
+            } else {
+                // find intersection by chasing t
                 if (binary_search(q1, q2, roots1Copy, roots2Copy, pts1)) {
                     insert(roots1Copy[0], roots2Copy[0], pts1[0]);
                 }
             }
         }
         return fUsed;
     }
     int closest[4];
     double dist[4];
     bool foundSomething = false;
@@ skipping 45 matching lines @@
         }
         if (lowestIndex < 0) {
             break;
         }
         insert(roots1Copy[lowestIndex], roots2Copy[closest[lowestIndex]],
                 pts1[lowestIndex]);
         closest[lowestIndex] = -1;
     } while (++used < r1Count);
     return fUsed;
 }