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Unified Diff: third_party/fdlibm/fdlibm.js

Issue 448633002: Revert "Implement trigonometric functions using a fdlibm port." (Closed) Base URL: https://v8.googlecode.com/svn/branches/bleeding_edge
Patch Set: Created 6 years, 4 months ago
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Index: third_party/fdlibm/fdlibm.js
diff --git a/third_party/fdlibm/fdlibm.js b/third_party/fdlibm/fdlibm.js
deleted file mode 100644
index d5dbb72990a5adecafd3697393ca86928ba31970..0000000000000000000000000000000000000000
--- a/third_party/fdlibm/fdlibm.js
+++ /dev/null
@@ -1,356 +0,0 @@
-// The following is adapted from fdlibm (http://www.netlib.org/fdlibm),
-//
-// ====================================================
-// Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
-//
-// Developed at SunSoft, a Sun Microsystems, Inc. business.
-// Permission to use, copy, modify, and distribute this
-// software is freely granted, provided that this notice
-// is preserved.
-// ====================================================
-//
-// The original source code covered by the above license above has been
-// modified significantly by Google Inc.
-// Copyright 2014 the V8 project authors. All rights reserved.
-//
-// The following is a straightforward translation of fdlibm routines for
-// sin, cos, and tan, by Raymond Toy (rtoy@google.com).
-
-
-var kTrig; // Initialized to a Float64Array during genesis and is not writable.
-
-const INVPIO2 = kTrig[0];
-const PIO2_1 = kTrig[1];
-const PIO2_1T = kTrig[2];
-const PIO2_2 = kTrig[3];
-const PIO2_2T = kTrig[4];
-const PIO2_3 = kTrig[5];
-const PIO2_3T = kTrig[6];
-const PIO4 = kTrig[32];
-const PIO4LO = kTrig[33];
-
-// Compute k and r such that x - k*pi/2 = r where |r| < pi/4. For
-// precision, r is returned as two values y0 and y1 such that r = y0 + y1
-// to more than double precision.
-macro REMPIO2(X)
- var n, y0, y1;
- var hx = %_DoubleHi(X);
- var ix = hx & 0x7fffffff;
-
- if (ix < 0x4002d97c) {
- // |X| ~< 3*pi/4, special case with n = +/- 1
- if (hx > 0) {
- var z = X - PIO2_1;
- if (ix != 0x3ff921fb) {
- // 33+53 bit pi is good enough
- y0 = z - PIO2_1T;
- y1 = (z - y0) - PIO2_1T;
- } else {
- // near pi/2, use 33+33+53 bit pi
- z -= PIO2_2;
- y0 = z - PIO2_2T;
- y1 = (z - y0) - PIO2_2T;
- }
- n = 1;
- } else {
- // Negative X
- var z = X + PIO2_1;
- if (ix != 0x3ff921fb) {
- // 33+53 bit pi is good enough
- y0 = z + PIO2_1T;
- y1 = (z - y0) + PIO2_1T;
- } else {
- // near pi/2, use 33+33+53 bit pi
- z += PIO2_2;
- y0 = z + PIO2_2T;
- y1 = (z - y0) + PIO2_2T;
- }
- n = -1;
- }
- } else if (ix <= 0x413921fb) {
- // |X| ~<= 2^19*(pi/2), medium size
- var t = MathAbs(X);
- n = (t * INVPIO2 + 0.5) | 0;
- var r = t - n * PIO2_1;
- var w = n * PIO2_1T;
- // First round good to 85 bit
- y0 = r - w;
- if (ix - (%_DoubleHi(y0) & 0x7ff00000) > 0x1000000) {
- // 2nd iteration needed, good to 118
- t = r;
- w = n * PIO2_2;
- r = t - w;
- w = n * PIO2_2T - ((t - r) - w);
- y0 = r - w;
- if (ix - (%_DoubleHi(y0) & 0x7ff00000) > 0x3100000) {
- // 3rd iteration needed. 151 bits accuracy
- t = r;
- w = n * PIO2_3;
- r = t - w;
- w = n * PIO2_3T - ((t - r) - w);
- y0 = r - w;
- }
- }
- y1 = (r - y0) - w;
- if (hx < 0) {
- n = -n;
- y0 = -y0;
- y1 = -y1;
- }
- } else {
- // Need to do full Payne-Hanek reduction here.
- var r = %RemPiO2(X);
- n = r[0];
- y0 = r[1];
- y1 = r[2];
- }
-endmacro
-
-
-// __kernel_sin(X, Y, IY)
-// kernel sin function on [-pi/4, pi/4], pi/4 ~ 0.7854
-// Input X is assumed to be bounded by ~pi/4 in magnitude.
-// Input Y is the tail of X so that x = X + Y.
-//
-// Algorithm
-// 1. Since ieee_sin(-x) = -ieee_sin(x), we need only to consider positive x.
-// 2. ieee_sin(x) is approximated by a polynomial of degree 13 on
-// [0,pi/4]
-// 3 13
-// sin(x) ~ x + S1*x + ... + S6*x
-// where
-//
-// |ieee_sin(x) 2 4 6 8 10 12 | -58
-// |----- - (1+S1*x +S2*x +S3*x +S4*x +S5*x +S6*x )| <= 2
-// | x |
-//
-// 3. ieee_sin(X+Y) = ieee_sin(X) + sin'(X')*Y
-// ~ ieee_sin(X) + (1-X*X/2)*Y
-// For better accuracy, let
-// 3 2 2 2 2
-// r = X *(S2+X *(S3+X *(S4+X *(S5+X *S6))))
-// then 3 2
-// sin(x) = X + (S1*X + (X *(r-Y/2)+Y))
-//
-macro KSIN(x)
-kTrig[7+x]
-endmacro
-
-macro RETURN_KERNELSIN(X, Y, SIGN)
- var z = X * X;
- var v = z * X;
- var r = KSIN(1) + z * (KSIN(2) + z * (KSIN(3) +
- z * (KSIN(4) + z * KSIN(5))));
- return (X - ((z * (0.5 * Y - v * r) - Y) - v * KSIN(0))) SIGN;
-endmacro
-
-// __kernel_cos(X, Y)
-// kernel cos function on [-pi/4, pi/4], pi/4 ~ 0.785398164
-// Input X is assumed to be bounded by ~pi/4 in magnitude.
-// Input Y is the tail of X so that x = X + Y.
-//
-// Algorithm
-// 1. Since ieee_cos(-x) = ieee_cos(x), we need only to consider positive x.
-// 2. ieee_cos(x) is approximated by a polynomial of degree 14 on
-// [0,pi/4]
-// 4 14
-// cos(x) ~ 1 - x*x/2 + C1*x + ... + C6*x
-// where the remez error is
-//
-// | 2 4 6 8 10 12 14 | -58
-// |ieee_cos(x)-(1-.5*x +C1*x +C2*x +C3*x +C4*x +C5*x +C6*x )| <= 2
-// | |
-//
-// 4 6 8 10 12 14
-// 3. let r = C1*x +C2*x +C3*x +C4*x +C5*x +C6*x , then
-// ieee_cos(x) = 1 - x*x/2 + r
-// since ieee_cos(X+Y) ~ ieee_cos(X) - ieee_sin(X)*Y
-// ~ ieee_cos(X) - X*Y,
-// a correction term is necessary in ieee_cos(x) and hence
-// cos(X+Y) = 1 - (X*X/2 - (r - X*Y))
-// For better accuracy when x > 0.3, let qx = |x|/4 with
-// the last 32 bits mask off, and if x > 0.78125, let qx = 0.28125.
-// Then
-// cos(X+Y) = (1-qx) - ((X*X/2-qx) - (r-X*Y)).
-// Note that 1-qx and (X*X/2-qx) is EXACT here, and the
-// magnitude of the latter is at least a quarter of X*X/2,
-// thus, reducing the rounding error in the subtraction.
-//
-macro KCOS(x)
-kTrig[13+x]
-endmacro
-
-macro RETURN_KERNELCOS(X, Y, SIGN)
- var ix = %_DoubleHi(X) & 0x7fffffff;
- var z = X * X;
- var r = z * (KCOS(0) + z * (KCOS(1) + z * (KCOS(2)+
- z * (KCOS(3) + z * (KCOS(4) + z * KCOS(5))))));
- if (ix < 0x3fd33333) { // |x| ~< 0.3
- return (1 - (0.5 * z - (z * r - X * Y))) SIGN;
- } else {
- var qx;
- if (ix > 0x3fe90000) { // |x| > 0.78125
- qx = 0.28125;
- } else {
- qx = %_ConstructDouble(%_DoubleHi(0.25 * X), 0);
- }
- var hz = 0.5 * z - qx;
- return (1 - qx - (hz - (z * r - X * Y))) SIGN;
- }
-endmacro
-
-// kernel tan function on [-pi/4, pi/4], pi/4 ~ 0.7854
-// Input x is assumed to be bounded by ~pi/4 in magnitude.
-// Input y is the tail of x.
-// Input k indicates whether ieee_tan (if k = 1) or -1/tan (if k = -1)
-// is returned.
-//
-// Algorithm
-// 1. Since ieee_tan(-x) = -ieee_tan(x), we need only to consider positive x.
-// 2. if x < 2^-28 (hx<0x3e300000 0), return x with inexact if x!=0.
-// 3. ieee_tan(x) is approximated by a odd polynomial of degree 27 on
-// [0,0.67434]
-// 3 27
-// tan(x) ~ x + T1*x + ... + T13*x
-// where
-//
-// |ieee_tan(x) 2 4 26 | -59.2
-// |----- - (1+T1*x +T2*x +.... +T13*x )| <= 2
-// | x |
-//
-// Note: ieee_tan(x+y) = ieee_tan(x) + tan'(x)*y
-// ~ ieee_tan(x) + (1+x*x)*y
-// Therefore, for better accuracy in computing ieee_tan(x+y), let
-// 3 2 2 2 2
-// r = x *(T2+x *(T3+x *(...+x *(T12+x *T13))))
-// then
-// 3 2
-// tan(x+y) = x + (T1*x + (x *(r+y)+y))
-//
-// 4. For x in [0.67434,pi/4], let y = pi/4 - x, then
-// tan(x) = ieee_tan(pi/4-y) = (1-ieee_tan(y))/(1+ieee_tan(y))
-// = 1 - 2*(ieee_tan(y) - (ieee_tan(y)^2)/(1+ieee_tan(y)))
-//
-// Set returnTan to 1 for tan; -1 for cot. Anything else is illegal
-// and will cause incorrect results.
-//
-macro KTAN(x)
-kTrig[19+x]
-endmacro
-
-function KernelTan(x, y, returnTan) {
- var z;
- var w;
- var hx = %_DoubleHi(x);
- var ix = hx & 0x7fffffff;
-
- if (ix < 0x3e300000) { // |x| < 2^-28
- if (((ix | %_DoubleLo(x)) | (returnTan + 1)) == 0) {
- // x == 0 && returnTan = -1
- return 1 / MathAbs(x);
- } else {
- if (returnTan == 1) {
- return x;
- } else {
- // Compute -1/(x + y) carefully
- var w = x + y;
- var z = %_ConstructDouble(%_DoubleHi(w), 0);
- var v = y - (z - x);
- var a = -1 / w;
- var t = %_ConstructDouble(%_DoubleHi(a), 0);
- var s = 1 + t * z;
- return t + a * (s + t * v);
- }
- }
- }
- if (ix >= 0x3fe59429) { // |x| > .6744
- if (x < 0) {
- x = -x;
- y = -y;
- }
- z = PIO4 - x;
- w = PIO4LO - y;
- x = z + w;
- y = 0;
- }
- z = x * x;
- w = z * z;
-
- // Break x^5 * (T1 + x^2*T2 + ...) into
- // x^5 * (T1 + x^4*T3 + ... + x^20*T11) +
- // x^5 * (x^2 * (T2 + x^4*T4 + ... + x^22*T12))
- var r = KTAN(1) + w * (KTAN(3) + w * (KTAN(5) +
- w * (KTAN(7) + w * (KTAN(9) + w * KTAN(11)))));
- var v = z * (KTAN(2) + w * (KTAN(4) + w * (KTAN(6) +
- w * (KTAN(8) + w * (KTAN(10) + w * KTAN(12))))));
- var s = z * x;
- r = y + z * (s * (r + v) + y);
- r = r + KTAN(0) * s;
- w = x + r;
- if (ix >= 0x3fe59428) {
- return (1 - ((hx >> 30) & 2)) *
- (returnTan - 2.0 * (x - (w * w / (w + returnTan) - r)));
- }
- if (returnTan == 1) {
- return w;
- } else {
- z = %_ConstructDouble(%_DoubleHi(w), 0);
- v = r - (z - x);
- var a = -1 / w;
- var t = %_ConstructDouble(%_DoubleHi(a), 0);
- s = 1 + t * z;
- return t + a * (s + t * v);
- }
-}
-
-function MathSinSlow(x) {
- REMPIO2(x);
- var sign = 1 - (n & 2);
- if (n & 1) {
- RETURN_KERNELCOS(y0, y1, * sign);
- } else {
- RETURN_KERNELSIN(y0, y1, * sign);
- }
-}
-
-function MathCosSlow(x) {
- REMPIO2(x);
- if (n & 1) {
- var sign = (n & 2) - 1;
- RETURN_KERNELSIN(y0, y1, * sign);
- } else {
- var sign = 1 - (n & 2);
- RETURN_KERNELCOS(y0, y1, * sign);
- }
-}
-
-// ECMA 262 - 15.8.2.16
-function MathSin(x) {
- x = x * 1; // Convert to number.
- if ((%_DoubleHi(x) & 0x7fffffff) <= 0x3fe921fb) {
- // |x| < pi/4, approximately. No reduction needed.
- RETURN_KERNELSIN(x, 0, /* empty */);
- }
- return MathSinSlow(x);
-}
-
-// ECMA 262 - 15.8.2.7
-function MathCos(x) {
- x = x * 1; // Convert to number.
- if ((%_DoubleHi(x) & 0x7fffffff) <= 0x3fe921fb) {
- // |x| < pi/4, approximately. No reduction needed.
- RETURN_KERNELCOS(x, 0, /* empty */);
- }
- return MathCosSlow(x);
-}
-
-// ECMA 262 - 15.8.2.18
-function MathTan(x) {
- x = x * 1; // Convert to number.
- if ((%_DoubleHi(x) & 0x7fffffff) <= 0x3fe921fb) {
- // |x| < pi/4, approximately. No reduction needed.
- return KernelTan(x, 0, 1);
- }
- REMPIO2(x);
- return KernelTan(y0, y1, (n & 1) ? -1 : 1);
-}
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