`1..isPrototypeOf.call(null)` should return false, not throw TypeError.

test/mjsunit/regress/regress-3483.js

Index: test/mjsunit/regress/regress-3483.js
diff --git a/test/mjsunit/regress/regress-352059.js b/test/mjsunit/regress/regress-3483.js
similarity index 90%
copy from test/mjsunit/regress/regress-352059.js
copy to test/mjsunit/regress/regress-3483.js
index cd1a4c28f77f40e3932b4dd860c803915b25b375..dec95c48ffe53482af0cbd56103ef05cb8c84752 100644
--- a/test/mjsunit/regress/regress-352059.js
+++ b/test/mjsunit/regress/regress-3483.js
@@ -25,11 +25,6 @@
 // (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
 // OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
 
-var foo = false;
-
-function bar() {
-  foo = 2;
-  return 4 % foo;
-}
-
-bar();
+assertFalse(Object.prototype.isPrototypeOf.call());
+assertFalse(Object.prototype.isPrototypeOf.call(null, 1));
+assertFalse(Object.prototype.isPrototypeOf.call(undefined, 1));