| Index: Source/core/accessibility/AXNodeObject.cpp
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| diff --git a/Source/core/accessibility/AXNodeObject.cpp b/Source/core/accessibility/AXNodeObject.cpp
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| index 6410e9cafdbb12241ee581154b6f6e2862e2affa..819c702d81823ee08a7150e3cceaa0a6474a51b0 100644
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| --- a/Source/core/accessibility/AXNodeObject.cpp
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| +++ b/Source/core/accessibility/AXNodeObject.cpp
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| @@ -1247,8 +1247,28 @@ LayoutRect AXNodeObject::elementRect() const
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|      if (!m_explicitElementRect.isEmpty())
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|          return m_explicitElementRect;
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|  
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| -    // AXNodeObjects have no mechanism yet to return a size or position.
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| -    // For now, let's return the position of the ancestor that does have a position,
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| +    // FIXME: If there are a lot of elements in the canvas, it will be inefficient.
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| +    // We can avoid the inefficient calculations by using AXComputedObjectAttributeCache.
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| +    if (node()->parentElement()->isInCanvasSubtree()) {
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| +        LayoutRect rect;
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| +
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| +        for (Node* child = node()->firstChild(); child; child = child->nextSibling()) {
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| +            if (child->isHTMLElement()) {
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| +                if (AXObject* obj = axObjectCache()->get(child)) {
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| +                    if (rect.isEmpty())
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| +                        rect = obj->elementRect();
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| +                    else
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| +                        rect.unite(obj->elementRect());
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| +                }
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| +            }
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| +        }
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| +
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| +        if (!rect.isEmpty())
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| +            return rect;
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| +    }
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| +
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| +    // If this object doesn't have an explicit element rect or computable from its children,
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| +    // for now, let's return the position of the ancestor that does have a position,
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|      // and make it the width of that parent, and about the height of a line of text, so that it's clear the object is a child of the parent.
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|  
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|      LayoutRect boundingBox;
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| 
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