Fix copyright header presubmit

PRESUBMIT.py

Index: PRESUBMIT.py
diff --git a/PRESUBMIT.py b/PRESUBMIT.py
index fce336da65048046a452911b8d9243f5eadbce7f..66aa5ea2e8312fb18b71a8c14e2d7f5797324ab6 100644
--- a/PRESUBMIT.py
+++ b/PRESUBMIT.py
@@ -1,6 +1,16 @@
-# Copyright 2015 The LUCI Authors. All rights reserved.
-# Use of this source code is governed under the Apache License, Version 2.0
-# that can be found in the LICENSE file.
+# Copyright 2017 The LUCI Authors.
+#
+# Licensed under the Apache License, Version 2.0 (the "License");
+# you may not use this file except in compliance with the License.
+# You may obtain a copy of the License at
+#
+#      http://www.apache.org/licenses/LICENSE-2.0
+#
+# Unless required by applicable law or agreed to in writing, software
+# distributed under the License is distributed on an "AS IS" BASIS,
+# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
+# See the License for the specific language governing permissions and
+# limitations under the License.
 
 """Top-level presubmit script.
 
@@ -9,6 +19,7 @@ details on the presubmit API built into depot_tools.
 """
 
 import os
+import re
 import sys
 
 
@@ -65,26 +76,38 @@ def WebChecks(input_api, output_api):
           'presubmit',
       ],
       kwargs={},
-      message=output_api.PresubmitError,
+      message=error_type,
   )])
   return output
 
 
+COPYRIGHT_TEMPLATE = """
+Copyright YEARPATTERN The LUCI Authors.
+
+Licensed under the Apache License, Version 2.0 (the "License");
+you may not use this file except in compliance with the License.
+You may obtain a copy of the License at
+
+     http://www.apache.org/licenses/LICENSE-2.0
+
+Unless required by applicable law or agreed to in writing, software
+distributed under the License is distributed on an "AS IS" BASIS,
+WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
+See the License for the specific language governing permissions and
+limitations under the License.
+""".strip()
+
 def header(input_api):
   """Returns the expected license header regexp for this project."""
   current_year = int(input_api.time.strftime('%Y'))
   allowed_years = (str(s) for s in reversed(xrange(2011, current_year + 1)))
   years_re = '(' + '|'.join(allowed_years) + ')'
-  license_header = (
-    r'.*? Copyright %(year)s The LUCI Authors\. '
-      r'All rights reserved\.\n'
-    r'.*? Use of this source code is governed under the Apache License, '
-      r'Version 2\.0\n'
-    r'.*? that can be found in the LICENSE file\.(?: \*/)?\n'
-  ) % {
-    'year': years_re,
-  }
-  return license_header
+  lines = [
+    ('.*? ' + re.escape(line)) if line else '.*?'
+    for line in COPYRIGHT_TEMPLATE.splitlines()
+  ]
+  lines[0] = lines[0].replace('YEARPATTERN', years_re)

[Ryan Tseng, 2017/07/15 01:08:23]

lol

+  return '\n'.join(lines) + '(?: \*/)?\n'
 
 
 def source_file_filter(input_api):