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Side by Side Diff: sdk/lib/collection/hash_map.dart

Issue 2754013002: Format all dart: library files (Closed)
Patch Set: Format all dart: library files Created 3 years, 9 months ago
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1 // Copyright (c) 2013, the Dart project authors. Please see the AUTHORS file 1 // Copyright (c) 2013, the Dart project authors. Please see the AUTHORS file
2 // for details. All rights reserved. Use of this source code is governed by a 2 // for details. All rights reserved. Use of this source code is governed by a
3 // BSD-style license that can be found in the LICENSE file. 3 // BSD-style license that can be found in the LICENSE file.
4 4
5 part of dart.collection; 5 part of dart.collection;
6 6
7 /** Default function for equality comparison in customized HashMaps */ 7 /** Default function for equality comparison in customized HashMaps */
8 bool _defaultEquals(a, b) => a == b; 8 bool _defaultEquals(a, b) => a == b;
9 /** Default function for hash-code computation in customized HashMaps */ 9 /** Default function for hash-code computation in customized HashMaps */
10 int _defaultHashCode(a) => a.hashCode; 10 int _defaultHashCode(a) => a.hashCode;
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76 * Such a map can be created directly using [HashMap.identity]. 76 * Such a map can be created directly using [HashMap.identity].
77 * 77 *
78 * The used `equals` and `hashCode` method should always be consistent, 78 * The used `equals` and `hashCode` method should always be consistent,
79 * so that if `equals(a, b)` then `hashCode(a) == hashCode(b)`. The hash 79 * so that if `equals(a, b)` then `hashCode(a) == hashCode(b)`. The hash
80 * of an object, or what it compares equal to, should not change while the 80 * of an object, or what it compares equal to, should not change while the
81 * object is a key in the map. If it does change, the result is unpredictable. 81 * object is a key in the map. If it does change, the result is unpredictable.
82 * 82 *
83 * If you supply one of [equals] and [hashCode], 83 * If you supply one of [equals] and [hashCode],
84 * you should generally also to supply the other. 84 * you should generally also to supply the other.
85 */ 85 */
86 external factory HashMap({bool equals(K key1, K key2), 86 external factory HashMap(
87 int hashCode(K key), 87 {bool equals(K key1, K key2),
88 bool isValidKey(potentialKey)}); 88 int hashCode(K key),
89 bool isValidKey(potentialKey)});
89 90
90 /** 91 /**
91 * Creates an unordered identity-based map. 92 * Creates an unordered identity-based map.
92 * 93 *
93 * Effectively a shorthand for: 94 * Effectively a shorthand for:
94 * 95 *
95 * new HashMap<K, V>(equals: identical, 96 * new HashMap<K, V>(equals: identical,
96 * hashCode: identityHashCode) 97 * hashCode: identityHashCode)
97 */ 98 */
98 external factory HashMap.identity(); 99 external factory HashMap.identity();
99 100
100 /** 101 /**
101 * Creates a [HashMap] that contains all key/value pairs of [other]. 102 * Creates a [HashMap] that contains all key/value pairs of [other].
102 */ 103 */
103 factory HashMap.from(Map other) { 104 factory HashMap.from(Map other) {
104 HashMap<K, V> result = new HashMap<K, V>(); 105 HashMap<K, V> result = new HashMap<K, V>();
105 other.forEach((k, v) { result[k as Object/*=K*/] = v as Object/*=V*/; }); 106 other.forEach((k, v) {
107 result[k as Object/*=K*/] = v as Object/*=V*/;
108 });
106 return result; 109 return result;
107 } 110 }
108 111
109 /** 112 /**
110 * Creates a [HashMap] where the keys and values are computed from the 113 * Creates a [HashMap] where the keys and values are computed from the
111 * [iterable]. 114 * [iterable].
112 * 115 *
113 * For each element of the [iterable] this constructor computes a key/value 116 * For each element of the [iterable] this constructor computes a key/value
114 * pair, by applying [key] and [value] respectively. 117 * pair, by applying [key] and [value] respectively.
115 * 118 *
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136 * overwrites the previous value. 139 * overwrites the previous value.
137 * 140 *
138 * It is an error if the two [Iterable]s don't have the same length. 141 * It is an error if the two [Iterable]s don't have the same length.
139 */ 142 */
140 factory HashMap.fromIterables(Iterable<K> keys, Iterable<V> values) { 143 factory HashMap.fromIterables(Iterable<K> keys, Iterable<V> values) {
141 HashMap<K, V> map = new HashMap<K, V>(); 144 HashMap<K, V> map = new HashMap<K, V>();
142 Maps._fillMapWithIterables(map, keys, values); 145 Maps._fillMapWithIterables(map, keys, values);
143 return map; 146 return map;
144 } 147 }
145 } 148 }
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