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pkg/dev_compiler/tool/input_sdk/lib/core/iterable.dart

Index: pkg/dev_compiler/tool/input_sdk/lib/core/iterable.dart
diff --git a/pkg/dev_compiler/tool/input_sdk/lib/core/iterable.dart b/pkg/dev_compiler/tool/input_sdk/lib/core/iterable.dart
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-// Copyright (c) 2011, the Dart project authors.  Please see the AUTHORS file
-// for details. All rights reserved. Use of this source code is governed by a
-// BSD-style license that can be found in the LICENSE file.
-
-part of dart.core;
-
-/**
- * A collection of values, or "elements", that can be accessed sequentially.
- *
- * The elements of the iterable are accessed by getting an [Iterator]
- * using the [iterator] getter, and using it to step through the values.
- * Stepping with the iterator is done by calling [Iterator.moveNext],
- * and if the call returns `true`,
- * the iterator has now moved to the next element,
- * which is then available as [Iterator.current].
- * If the call returns `false`, there are no more elements,
- * and `iterator.currrent` returns `null`.
- *
- * You can create more than one iterator from the same `Iterable`.
- * Each time `iterator` is read, it returns a new iterator,
- * and different iterators can be stepped through independently,
- * each giving access to all the elements of the iterable.
- * The iterators of the same iterable *should* provide the same values
- * in the same order (unless the underlying collection is modified between
- * the iterations, which some collections allow).
- *
- * You can also iterate over the elements of an `Iterable`
- * using the for-in loop construct, which uses the `iterator` getter behind the
- * scenes.
- * For example, you can iterate over all of the keys of a [Map],
- * because `Map` keys are iterable.
- *
- *     Map kidsBooks = {'Matilda': 'Roald Dahl',
- *                      'Green Eggs and Ham': 'Dr Seuss',
- *                      'Where the Wild Things Are': 'Maurice Sendak'};
- *     for (var book in kidsBooks.keys) {
- *       print('$book was written by ${kidsBooks[book]}');
- *     }
- *
- * The [List] and [Set] classes are both `Iterable`,
- * as are most classes in the [dart:collection](#dart-collection) library.
- *
- * Some [Iterable] collections can be modified.
- * Adding an element to a `List` or `Set` will change which elements it
- * contains, and adding a new key to a `Map` changes the elements of [Map.keys].
- * Iterators created after the change will provide the new elements, and may
- * or may not preserve the order of existing elements
- * (for example, a [HashSet] may completely change its order when a single
- * element is added).
- *
- * Changing a collection *while* it is being iterated
- * is generally *not* allowed.
- * Doing so will break the iteration, which is typically signalled
- * by throwing a [ConcurrentModificationError]
- * the next time [Iterator.moveNext] is called.
- * The current value of [Iterator.current] getter
- * should not be affected by the change in the collection,
- * the `current` value was set by the previous call to [Iterator.moveNext].
- *
- * Some iterables compute their elements dynamically every time they are
- * iterated, like the one returned by [Iterable.generate] or the iterable
- * returned by a `sync*` generator function. If the computation doesn't depend
- * on other objects that may change, then the generated sequence should be
- * the same one every time it's iterated.
- *
- * The members of `Iterable`, other than `iterator` itself,
- * work by looking at the elements of the iterable.
- * This can be implemented by running through the [iterator], but some classes
- * may have more efficient ways of finding the result
- * (like [last] or [length] on a [List], or [contains] on a [Set]).
- *
- * The methods that return another `Iterable` (like [map] and [where])
- * are all *lazy* - they will iterate the original (as necessary)
- * every time the returned iterable is iterated, and not before.
- *
- * Since an iterable may be iterated more than once, it's not recommended to
- * have detectable side-effects in the iterator.
- * For methods like [map] and [while], the returned iterable will execute the
- * argument function on every iteration, so those functions should also not
- * have side effects.
- */
-abstract class Iterable<E> {
-  const Iterable();
-
-  /**
-   * Creates an `Iterable` that generates its elements dynamically.
-   *
-   * An `Iterator` created by [iterator] will count from
-   * zero to [:count - 1:], and call [generator]
-   * with each index in turn to create the next value.
-   *
-   * If [generator] is omitted, it defaults to an identity function
-   * on integers `(int x) => x`, so it should only be omitted if the type
-   * parameter allows integer values.
-   *
-   * As an `Iterable`, `new Iterable.generate(n, generator))` is equivalent to
-   * `const [0, ..., n - 1].map(generator)`.
-   */
-  factory Iterable.generate(int count, [E generator(int index)]) {
-    if (count <= 0) return new EmptyIterable<E>();
-    return new _GeneratorIterable<E>(count, generator);
-  }
-
-  /**
-   * Creates an empty iterable.
-   *
-   * The empty iterable has no elements, and iterating it always stops
-   * immediately.
-   */
-  const factory Iterable.empty() = EmptyIterable<E>;
-
-  /**
-   * Returns a new `Iterator` that allows iterating the elements of this
-   * `Iterable`.
-   *
-   * Iterable classes may specify the iteration order of their elements
-   * (for example [List] always iterate in index order),
-   * or they may leave it unspecified (for example a hash-based [Set]
-   * may iterate in any order).
-   *
-   * Each time `iterator` is read, it returns a new iterator,
-   * which can be used to iterate through all the elements again.
-   * The iterators of the same iterable can be stepped through independently,
-   * but should return the same elements in the same order,
-   * as long as the underlying collection isn't changed.
-   *
-   * Modifying the collection may cause new iterators to produce
-   * different elements, and may change the order of existing elements.
-   * A [List] specifies its iteration order precisely,
-   * so modifying the list changes the iteration order predictably.
-   * A hash-based [Set] may change its iteration order completely
-   * when adding a new element to the set.
-   *
-   * Modifying the underlying collection after creating the new iterator
-   * may cause an error the next time [Iterator.moveNext] is called
-   * on that iterator.
-   * Any *modifiable* iterable class should specify which operations will
-   * break iteration.
-   */
-  Iterator<E> get iterator;
-
-  /**
-   * Returns a new lazy [Iterable] with elements that are created by
-   * calling `f` on each element of this `Iterable` in iteration order.
-   *
-   * This method returns a view of the mapped elements. As long as the
-   * returned [Iterable] is not iterated over, the supplied function [f] will
-   * not be invoked. The transformed elements will not be cached. Iterating
-   * multiple times over the returned [Iterable] will invoke the supplied
-   * function [f] multiple times on the same element.
-   *
-   * Methods on the returned iterable are allowed to omit calling `f`
-   * on any element where the result isn't needed.
-   * For example, [elementAt] may call `f` only once.
-   */
-  Iterable/*<T>*/ map/*<T>*/(/*=T*/ f(E e)) =>
-      new MappedIterable<E, dynamic/*=T*/>(this, f);
-
-  /**
-   * Returns a new lazy [Iterable] with all elements that satisfy the
-   * predicate [test].
-   *
-   * The matching elements have the same order in the returned iterable
-   * as they have in [iterator].
-   *
-   * This method returns a view of the mapped elements. As long as the
-   * returned [Iterable] is not iterated over, the supplied function [test] will
-   * not be invoked. Iterating will not cache results, and thus iterating
-   * multiple times over the returned [Iterable] will invoke the supplied
-   * function [test] multiple times on the same element.
-   */
-  Iterable<E> where(bool test(E element)) =>
-      new WhereIterable<E>(this, test);
-
-  /**
-   * Expands each element of this [Iterable] into zero or more elements.
-   *
-   * The resulting Iterable runs through the elements returned
-   * by [f] for each element of this, in iteration order.
-   *
-   * The returned [Iterable] is lazy, and calls [f] for each element
-   * of this every time it's iterated.
-   */
-  Iterable/*<T>*/ expand/*<T>*/(Iterable/*<T>*/ f(E element)) =>
-      new ExpandIterable<E, dynamic/*=T*/>(this, f);
-
-  /**
-   * Returns true if the collection contains an element equal to [element].
-   *
-   * This operation will check each element in order for being equal to
-   * [element], unless it has a more efficient way to find an element
-   * equal to [element].
-   *
-   * The equality used to determine whether [element] is equal to an element of
-   * the iterable defaults to the [Object.operator==] of the element.
-   *
-   * Some types of iterable may have a different equality used for its elements.
-   * For example, a [Set] may have a custom equality
-   * (see [Set.identical]) that its `contains` uses.
-   * Likewise the `Iterable` returned by a [Map.keys] call
-   * should use the same equality that the `Map` uses for keys.
-   */
-  bool contains(Object element) {
-    for (E e in this) {
-      if (e == element) return true;
-    }
-    return false;
-  }
-
-
-  /**
-   * Applies the function [f] to each element of this collection in iteration
-   * order.
-   */
-  void forEach(void f(E element)) {
-    for (E element in this) f(element);
-  }
-
-  /**
-   * Reduces a collection to a single value by iteratively combining elements
-   * of the collection using the provided function.
-   *
-   * The iterable must have at least one element.
-   * If it has only one element, that element is returned.
-   *
-   * Otherwise this method starts with the first element from the iterator,
-   * and then combines it with the remaining elements in iteration order,
-   * as if by:
-   *
-   *     E value = iterable.first;
-   *     iterable.skip(1).forEach((element) {
-   *       value = combine(value, element);
-   *     });
-   *     return value;
-   *
-   * Example of calculating the sum of an iterable:
-   *
-   *     iterable.reduce((value, element) => value + element);
-   *
-   */
-  E reduce(E combine(E value, E element)) {
-    Iterator<E> iterator = this.iterator;
-    if (!iterator.moveNext()) {
-      throw IterableElementError.noElement();
-    }
-    E value = iterator.current;
-    while (iterator.moveNext()) {
-      value = combine(value, iterator.current);
-    }
-    return value;
-  }
-
-  /**
-   * Reduces a collection to a single value by iteratively combining each
-   * element of the collection with an existing value
-   *
-   * Uses [initialValue] as the initial value,
-   * then iterates through the elements and updates the value with
-   * each element using the [combine] function, as if by:
-   *
-   *     var value = initialValue;
-   *     for (E element in this) {
-   *       value = combine(value, element);
-   *     }
-   *     return value;
-   *
-   * Example of calculating the sum of an iterable:
-   *
-   *     iterable.fold(0, (prev, element) => prev + element);
-   *
-   */
-  dynamic/*=T*/ fold/*<T>*/(var/*=T*/ initialValue,
-               dynamic/*=T*/ combine(var/*=T*/ previousValue, E element)) {
-    var value = initialValue;
-    for (E element in this) value = combine(value, element);
-    return value;
-  }
-
-  /**
-   * Checks whether every element of this iterable satisfies [test].
-   *
-   * Checks every element in iteration order, and returns `false` if
-   * any of them make [test] return `false`, otherwise returns `true`.
-   */
-  bool every(bool f(E element)) {
-    for (E element in this) {
-      if (!f(element)) return false;
-    }
-    return true;
-  }
-
-  /**
-   * Converts each element to a [String] and concatenates the strings.
-   *
-   * Iterates through elements of this iterable,
-   * converts each one to a [String] by calling [Object.toString],
-   * and then concatenates the strings, with the
-   * [separator] string interleaved between the elements.
-   */
-  String join([String separator = ""]) {
-    Iterator<E> iterator = this.iterator;
-    if (!iterator.moveNext()) return "";
-    StringBuffer buffer = new StringBuffer();
-    if (separator == null || separator == "") {
-      do {
-        buffer.write("${iterator.current}");
-      } while (iterator.moveNext());
-    } else {
-      buffer.write("${iterator.current}");
-      while (iterator.moveNext()) {
-        buffer.write(separator);
-        buffer.write("${iterator.current}");
-      }
-    }
-    return buffer.toString();
-  }
-
-
-  /**
-   * Checks whether any element of this iterable satisfies [test].
-   *
-   * Checks every element in iteration order, and returns `true` if
-   * any of them make [test] return `true`, otherwise returns false.
-   */
-  bool any(bool f(E element)) {
-    for (E element in this) {
-      if (f(element)) return true;
-    }
-    return false;
-  }
-
-  /**
-   * Creates a [List] containing the elements of this [Iterable].
-   *
-   * The elements are in iteration order.
-   * The list is fixed-length if [growable] is false.
-   */
-  List<E> toList({ bool growable: true }) =>
-      new List<E>.from(this, growable: growable);
-
-  /**
-   * Creates a [Set] containing the same elements as this iterable.
-   *
-   * The set may contain fewer elements than the iterable,
-   * if the iterable contains an element more than once,
-   * or it contains one or more elements that are equal.
-   * The order of the elements in the set is not guaranteed to be the same
-   * as for the iterable.
-   */
-  Set<E> toSet() => new Set<E>.from(this);
-
-  /**
-   * Returns the number of elements in [this].
-   *
-   * Counting all elements may involve iterating through all elements and can
-   * therefore be slow.
-   * Some iterables have a more efficient way to find the number of elements.
-   */
-  int get length {
-    assert(this is! EfficientLength);
-    int count = 0;
-    Iterator it = iterator;
-    while (it.moveNext()) {
-      count++;
-    }
-    return count;
-  }
-
-  /**
-   * Returns `true` if there are no elements in this collection.
-   *
-   * May be computed by checking if `iterator.moveNext()` returns `false`.
-   */
-  bool get isEmpty => !iterator.moveNext();
-
-  /**
-   * Returns true if there is at least one element in this collection.
-   *
-   * May be computed by checking if `iterator.moveNext()` returns `true`.
-   */
-  bool get isNotEmpty => !isEmpty;
-
-   /**
-   * Returns a lazy iterable of the [count] first elements of this iterable.
-   *
-   * The returned `Iterable` may contain fewer than `count` elements, if `this`
-   * contains fewer than `count` elements.
-   *
-   * The elements can be computed by stepping through [iterator] until [count]
-   * elements have been seen.
-   *
-   * The `count` must not be negative.
-   */
-  Iterable<E> take(int count) {
-    return new TakeIterable<E>(this, count);
-  }
-
-  /**
-   * Returns a lazy iterable of the leading elements satisfying [test].
-   *
-   * The filtering happens lazily. Every new iterator of the returned
-   * iterable starts iterating over the elements of `this`.
-   *
-   * The elements can be computed by stepping through [iterator] until an
-   * element is found where `test(element)` is false. At that point,
-   * the returned iterable stops (its `moveNext()` returns false).
-   */
-  Iterable<E> takeWhile(bool test(E value)) {
-    return new TakeWhileIterable<E>(this, test);
-  }
-
-  /**
-   * Returns an Iterable that provides all but the first [count] elements.
-   *
-   * When the returned iterable is iterated, it starts iterating over `this`,
-   * first skipping past the initial [count] elements.
-   * If `this` has fewer than `count` elements, then the resulting Iterable is
-   * empty.
-   * After that, the remaining elements are iterated in the same order as
-   * in this iterable.
-   *
-   * The `count` must not be negative.
-   */
-  Iterable<E> skip(int count) {
-    return new SkipIterable<E>(this, count);
-  }
-
-  /**
-   * Returns an Iterable that skips leading elements while [test] is satisfied.
-   *
-   * The filtering happens lazily. Every new Iterator of the returned
-   * Iterable iterates over all elements of `this`.
-   *
-   * The returned iterable provides elements by iterating this iterable,
-   * but skipping over all initial elements where `test(element)` returns
-   * true. If all elements satisfy `test` the resulting iterable is empty,
-   * otherwise it iterates the remaining elements in their original order,
-   * starting with the first element for which `test(element)` returns false.
-   */
-  Iterable<E> skipWhile(bool test(E value)) {
-    return new SkipWhileIterable<E>(this, test);
-  }
-
-  /**
-   * Returns the first element.
-   *
-   * Throws a [StateError] if `this` is empty.
-   * Otherwise returns the first element in the iteration order,
-   * equivalent to `this.elementAt(0)`.
-   */
-  E get first {
-    Iterator<E> it = iterator;
-    if (!it.moveNext()) {
-      throw IterableElementError.noElement();
-    }
-    return it.current;
-  }
-
-  /**
-   * Returns the last element.
-   *
-   * Throws a [StateError] if `this` is empty.
-   * Otherwise may iterate through the elements and returns the last one
-   * seen.
-   * Some iterables may have more efficient ways to find the last element
-   * (for example a list can directly access the last element,
-   * without iterating through the previous ones).
-   */
-  E get last {
-    Iterator<E> it = iterator;
-    if (!it.moveNext()) {
-      throw IterableElementError.noElement();
-    }
-    E result;
-    do {
-      result = it.current;
-    } while(it.moveNext());
-    return result;
-  }
-
-  /**
-   * Checks that this iterable has only one element, and returns that element.
-   *
-   * Throws a [StateError] if `this` is empty or has more than one element.
-   */
-  E get single {
-    Iterator<E> it = iterator;
-    if (!it.moveNext()) throw IterableElementError.noElement();
-    E result = it.current;
-    if (it.moveNext()) throw IterableElementError.tooMany();
-    return result;
-  }
-
-  /**
-   * Returns the first element that satisfies the given predicate [test].
-   *
-   * Iterates through elements and returns the first to satsify [test].
-   *
-   * If no element satisfies [test], the result of invoking the [orElse]
-   * function is returned.
-   * If [orElse] is omitted, it defaults to throwing a [StateError].
-   */
-  E firstWhere(bool test(E element), { E orElse() }) {
-    for (E element in this) {
-      if (test(element)) return element;
-    }
-    if (orElse != null) return orElse();
-    throw IterableElementError.noElement();
-  }
-
-  /**
-   * Returns the last element that satisfies the given predicate [test].
-   *
-   * An iterable that can access its elements directly may check its
-   * elements in any order (for example a list starts by checking the
-   * last element and then moves towards the start of the list).
-   * The default implementation iterates elements in iteration order,
-   * checks `test(element)` for each,
-   * and finally returns that last one that matched.
-   *
-   * If no element satsfies [test], the result of invoking the [orElse]
-   * function is returned.
-   * If [orElse] is omitted, it defaults to throwing a [StateError].
-   */
-  E lastWhere(bool test(E element), {E orElse()}) {
-    E result = null;
-    bool foundMatching = false;
-    for (E element in this) {
-      if (test(element)) {
-        result = element;
-        foundMatching = true;
-      }
-    }
-    if (foundMatching) return result;
-    if (orElse != null) return orElse();
-    throw IterableElementError.noElement();
-  }
-
-  /**
-   * Returns the single element that satisfies [test].
-   *
-   * Checks all elements to see if `test(element)` returns true.
-   * If exactly one element satisfies [test], that element is returned.
-   * Otherwise, if there are no matching elements, or if there is more than
-   * one matching element, a [StateError] is thrown.
-   */
-  E singleWhere(bool test(E element)) {
-    E result = null;
-    bool foundMatching = false;
-    for (E element in this) {
-      if (test(element)) {
-        if (foundMatching) {
-          throw IterableElementError.tooMany();
-        }
-        result = element;
-        foundMatching = true;
-      }
-    }
-    if (foundMatching) return result;
-    throw IterableElementError.noElement();
-  }
-
-  /**
-   * Returns the [index]th element.
-   *
-   * The [index] must be non-negative and less than [length].
-   * Index zero represents the first element (so `iterable.elementAt(0)` is
-   * equivalent to `iterable.first`).
-   *
-   * May iterate through the elements in iteration order, skipping the
-   * first `index` elements and returning the next.
-   * Some iterable may have more efficient ways to find the element.
-   */
-  E elementAt(int index) {
-    if (index is! int) throw new ArgumentError.notNull("index");
-    RangeError.checkNotNegative(index, "index");
-    int elementIndex = 0;
-    for (E element in this) {
-      if (index == elementIndex) return element;
-      elementIndex++;
-    }
-    throw new RangeError.index(index, this, "index", null, elementIndex);
-  }
-
-  /**
-   * Returns a string representation of (some of) the elements of `this`.
-   *
-   * Elements are represented by their own `toString` results.
-   *
-   * The default representation always contains the first three elements.
-   * If there are less than a hundred elements in the iterable, it also
-   * contains the last two elements.
-   *
-   * If the resulting string isn't above 80 characters, more elements are
-   * included from the start of the iterable.
-   *
-   * The conversion may omit calling `toString` on some elements if they
-   * are known to not occur in the output, and it may stop iterating after
-   * a hundred elements.
-   */
-  String toString() => IterableBase.iterableToShortString(this, '(', ')');
-}
-
-typedef E _Generator<E>(int index);
-
-class _GeneratorIterable<E> extends Iterable<E>
-                            implements EfficientLength {
-  final int _start;
-  final int _end;
-  final _Generator<E> _generator;
-
-  /// Creates an iterable that builds the elements from a generator function.
-  ///
-  /// The [generator] may be null, in which case the default generator
-  /// enumerating the integer positions is used. This means that [int] must
-  /// be assignable to [E] when no generator is provided. In practice this means
-  /// that the generator can only be emitted when [E] is equal to `dynamic`,
-  /// `int`, or `num`. The constructor will check that the types match.
-  _GeneratorIterable(this._end, E generator(int n))
-      : _start = 0,
-        // The `as` below is used as check to make sure that `int` is assignable
-        // to [E].
-        _generator = (generator != null) ? generator : _id as _Generator<E>;
-
-  _GeneratorIterable.slice(this._start, this._end, this._generator);
-
-  Iterator<E> get iterator =>
-      new _GeneratorIterator<E>(_start, _end, _generator);
-  int get length => _end - _start;
-
-  Iterable<E> skip(int count) {
-    RangeError.checkNotNegative(count, "count");
-    if (count == 0) return this;
-    int newStart = _start + count;
-    if (newStart >= _end) return new EmptyIterable<E>();
-    return new _GeneratorIterable<E>.slice(newStart, _end, _generator);
-  }
-
-  Iterable<E> take(int count) {
-    RangeError.checkNotNegative(count, "count");
-    if (count == 0) return new EmptyIterable<E>();
-    int newEnd = _start + count;
-    if (newEnd >= _end) return this;
-    return new _GeneratorIterable<E>.slice(_start, newEnd, _generator);
-  }
-
-  static int _id(int n) => n;
-}
-
-class _GeneratorIterator<E> implements Iterator<E> {
-  final int _end;
-  final _Generator<E> _generator;
-  int _index;
-  E _current;
-
-  _GeneratorIterator(this._index, this._end, this._generator);
-
-  bool moveNext() {
-    if (_index < _end) {
-      _current = _generator(_index);
-      _index++;
-      return true;
-    } else {
-      _current = null;
-      return false;
-    }
-  }
-
-  E get current => _current;
-}
-
-/**
- * An Iterator that allows moving backwards as well as forwards.
- */
-abstract class BidirectionalIterator<E> implements Iterator<E> {
-  /**
-   * Move back to the previous element.
-   *
-   * Returns true and updates [current] if successful. Returns false
-   * and sets [current] to null if there is no previous element.
-   */
-  bool movePrevious();
-}