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pkg/dev_compiler/tool/input_sdk/lib/core/set.dart

Index: pkg/dev_compiler/tool/input_sdk/lib/core/set.dart
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-// Copyright (c) 2011, the Dart project authors.  Please see the AUTHORS file
-// for details. All rights reserved. Use of this source code is governed by a
-// BSD-style license that can be found in the LICENSE file.
-
-part of dart.core;
-
-/**
- * A collection of objects in which each object can occur only once.
- *
- * That is, for each object of the element type, the object is either considered
- * to be in the set, or to _not_ be in the set.
- *
- * Set implementations may consider some elements indistinguishable. These
- * elements are treated as being the same for any operation on the set.
- *
- * The default [Set] implementation, [LinkedHashSet], considers objects
- * indistinguishable if they are equal with regard to
- * operator [Object.==].
- *
- * Iterating over elements of a set may be either unordered
- * or ordered in some way. Examples:
- *
- * * A [HashSet] is unordered, which means that its iteration order is
- *   uspecified,
- * * [LinkedHashSet] iterates in the insertion order of its elements, and
- * * a sorted set like [SplayTreeSet] iterates the elements in sorted order.
- *
- * It is generally not allowed to modify the set (add or remove elements) while
- * an operation on the set is being performed, for example during a call to
- * [forEach] or [containsAll]. Nor is it allowed to modify the set while
- * iterating either the set itself or any [Iterable] that is backed by the set,
- * such as the ones returned by methods like [where] and [map].
- */
-abstract class Set<E> extends Iterable<E> implements EfficientLength {
-  /**
-   * Creates an empty [Set].
-   *
-   * The created [Set] is a plain [LinkedHashSet].
-   * As such, it considers elements that are equal (using [==]) to be
-   * indistinguishable, and requires them to have a compatible
-   * [Object.hashCode] implementation.
-   *
-   * The set is equivalent to one created by `new LinkedHashSet<E>()`.
-   */
-  factory Set() = LinkedHashSet<E>;
-
-  /**
-   * Creates an empty identity [Set].
-   *
-   * The created [Set] is a [LinkedHashSet] that uses identity as equality
-   * relation.
-   *
-   * The set is equivalent to one created by `new LinkedHashSet<E>.identity()`.
-   */
-  factory Set.identity() = LinkedHashSet<E>.identity;
-
-  /**
-   * Creates a [Set] that contains all [elements].
-   *
-   * All the [elements] should be assignable to [E].
-   * The `elements` iterable itself can have any type,
-   * so this constructor can be used to down-cast a `Set`, for example as:
-   *
-   *     Set<SuperType> superSet = ...;
-   *     Set<SubType> subSet =
-   *         new Set<SubType>.from(superSet.where((e) => e is SubType));
-   *
-   * The created [Set] is a [LinkedHashSet]. As such, it considers elements that
-   * are equal (using [==]) to be indistinguishable, and requires them to
-   * have a compatible [Object.hashCode] implementation.
-   *
-   * The set is equivalent to one created by
-   * `new LinkedHashSet<E>.from(elements)`.
-   */
-  factory Set.from(Iterable<E> elements) = LinkedHashSet<E>.from;
-
-  /**
-   * Provides an iterator that iterates over the elements of this set.
-   *
-   * The order of iteration is defined by the individual `Set` implementation,
-   * but must be consistent between changes to the set.
-   */
-  Iterator<E> get iterator;
-
-  /**
-   * Returns true if [value] is in the set.
-   */
-  bool contains(Object value);
-
-  /**
-   * Adds [value] to the set.
-   *
-   * Returns `true` if [value] (or an equal value) was not yet in the set.
-   * Otherwise returns `false` and the set is not changed.
-   *
-   * Example:
-   *
-   *     var set = new Set();
-   *     var time1 = new DateTime.fromMillisecondsSinceEpoch(0);
-   *     var time2 = new DateTime.fromMillisecondsSinceEpoch(0);
-   *     // time1 and time2 are equal, but not identical.
-   *     Expect.isTrue(time1 == time2);
-   *     Expect.isFalse(identical(time1, time2));
-   *     set.add(time1);  // => true.
-   *     // A value equal to time2 exists already in the set, and the call to
-   *     // add doesn't change the set.
-   *     set.add(time2);  // => false.
-   *     Expect.isTrue(set.length == 1);
-   *     Expect.isTrue(identical(time1, set.first));
-   */
-  bool add(E value);
-
-  /**
-   * Adds all [elements] to this Set.
-   *
-   * Equivalent to adding each element in [elements] using [add],
-   * but some collections may be able to optimize it.
-   */
-  void addAll(Iterable<E> elements);
-
-  /**
-   * Removes [value] from the set. Returns true if [value] was
-   * in the set. Returns false otherwise. The method has no effect
-   * if [value] value was not in the set.
-   */
-  bool remove(Object value);
-
-  /**
-   * If an object equal to [object] is in the set, return it.
-   *
-   * Checks if there is an object in the set that is equal to [object].
-   * If so, that object is returned, otherwise returns null.
-   */
-  E lookup(Object object);
-
-  /**
-   * Removes each element of [elements] from this set.
-   */
-  void removeAll(Iterable<Object> elements);
-
-  /**
-   * Removes all elements of this set that are not elements in [elements].
-   *
-   * Checks for each element of [elements] whether there is an element in this
-   * set that is equal to it (according to `this.contains`), and if so, the
-   * equal element in this set is retained, and elements that are not equal
-   * to any element in `elements` are removed.
-   */
-  void retainAll(Iterable<Object> elements);
-
-  /**
-   * Removes all elements of this set that satisfy [test].
-   */
-  void removeWhere(bool test(E element));
-
-  /**
-   * Removes all elements of this set that fail to satisfy [test].
-   */
-  void retainWhere(bool test(E element));
-
-  /**
-   * Returns whether this Set contains all the elements of [other].
-   */
-  bool containsAll(Iterable<Object> other);
-
-  /**
-   * Returns a new set which is the intersection between this set and [other].
-   *
-   * That is, the returned set contains all the elements of this [Set] that
-   * are also elements of [other] according to `other.contains`.
-   */
-  Set<E> intersection(Set<Object> other);
-
-  /**
-   * Returns a new set which contains all the elements of this set and [other].
-   *
-   * That is, the returned set contains all the elements of this [Set] and
-   * all the elements of [other].
-   */
-  Set<E> union(Set<E> other);
-
-  /**
-   * Returns a new set with the elements of this that are not in [other].
-   *
-   * That is, the returned set contains all the elements of this [Set] that
-   * are not elements of [other] according to `other.contains`.
-   */
-  Set<E> difference(Set<Object> other);
-
-  /**
-   * Removes all elements in the set.
-   */
-  void clear();
-
-  /* Creates a [Set] with the same elements and behavior as this `Set`.
-   *
-   * The returned set behaves the same as this set
-   * with regard to adding and removing elements.
-   * It initially contains the same elements.
-   * If this set specifies an ordering of the elements,
-   * the returned set will have the same order.
-   */
-  Set<E> toSet();
-}