Use underscores to separate words in filenames in webkitpy.

third_party/WebKit/Tools/Scripts/webkitpy/common/system/user.py

 # Copyright (c) 2009, Google Inc. All rights reserved.
 #
 # Redistribution and use in source and binary forms, with or without
 # modification, are permitted provided that the following conditions are
 # met:
 #
 #     * Redistributions of source code must retain the above copyright
 # notice, this list of conditions and the following disclaimer.
 #     * Redistributions in binary form must reproduce the above
 # copyright notice, this list of conditions and the following disclaimer
@@ skipping 20 matching lines @@
 import os
 import platform
 import re
 import shlex
 import subprocess
 import sys
 import webbrowser
 
 from webkitpy.common.system.executive import Executive
 from webkitpy.common.system.filesystem import FileSystem
-from webkitpy.common.system.platforminfo import PlatformInfo
+from webkitpy.common.system.platform_info import PlatformInfo
 
 
 _log = logging.getLogger(__name__)
 
 
 class User(object):
     DEFAULT_NO = 'n'
     DEFAULT_YES = 'y'
 
-    def __init__(self, platforminfo=None):
+    def __init__(self, platform_info=None):
         # We cannot get the PlatformInfo object from a SystemHost because
         # User is part of SystemHost itself.
-        self._platforminfo = platforminfo or PlatformInfo(sys, platform, FileSystem(), Executive())
+        self._platform_info = platform_info or PlatformInfo(sys, platform, FileSystem(), Executive())
 
     # FIXME: These are @classmethods because bugzilla.py doesn't have a Tool object (thus no User instance).
     @classmethod
     def prompt(cls, message, repeat=1, raw_input=raw_input):
         response = None
         while repeat and not response:
             repeat -= 1
             response = raw_input(message)
         return response
 
@@ skipping 79 matching lines @@
         try:
             webbrowser.get()
             return True
         except webbrowser.Error:
             return False
 
     def open_url(self, url):
         if not self.can_open_url():
             _log.warning("Failed to open %s", url)
         webbrowser.open(url)