Fix an error in cron_servlet.py

chrome/common/extensions/docs/server2/cron_servlet.py

 # Copyright 2013 The Chromium Authors. All rights reserved.
 # Use of this source code is governed by a BSD-style license that can be
 # found in the LICENSE file.
 
 import logging
 import time
 import traceback
 
 from app_yaml_helper import AppYamlHelper
 from appengine_wrappers import (
@@ skipping 47 matching lines @@
   try:
     for i, item in enumerate(items):
       def error_message(detail):
         return '%s: error rendering %s (%s of %s): %s' % (
             title, item, i + 1, len(items), detail)
       try:
         response = request_callback(item)
         if response.status == 200:
           success_count += 1
         else:
-          _cronlog.error(error_message('response status %s', response.status))
+          _cronlog.error(error_message('response status %s' % response.status))
           failure_count += 1
       except Exception as e:
         _cronlog.error(error_message(traceback.format_exc()))
         failure_count += 1
         if IsDeadlineExceededError(e): raise
   finally:
     elapsed_seconds = time.time() - start_time
     _cronlog.info('%s: rendered %s of %s with %s failures in %s seconds',
         title, success_count, len(items), failure_count, elapsed_seconds);
   return success_count == len(items)
@@ skipping 171 matching lines @@
     compiled_host_fs_factory = CompiledFileSystem.Factory(
         host_file_system,
         object_store_creator)
     return ServerInstance(object_store_creator,
                           host_file_system,
                           app_samples_file_system,
                           '',
                           compiled_host_fs_factory,
                           branch_utility,
                           host_file_system_creator)