Add name, package_repo_resource and resource support to recipe scripts.

recipe_engine/config_types.py

 # Copyright 2013 The LUCI Authors. All rights reserved.
 # Use of this source code is governed under the Apache License, Version 2.0
 # that can be found in the LICENSE file.
 
 import abc
 import os
 import re
 
 from collections import namedtuple
 
@@ skipping 98 matching lines @@
 
   def __repr__(self):
     prefix = '%s.' % RECIPE_MODULE_PREFIX
     assert self.module.__name__.startswith(prefix)
     name = self.module.__name__[len(prefix):]
     # We change python's module delimiter . to ::, since . is already used
     # by expect tests.
     return 'RECIPE_MODULE[%s]' % re.sub('\.', '::', name)
 
 
+class RecipeScriptBasePath(
+    BasePath, namedtuple('RecipeScriptBasePath', 'recipe_name script_path')):
+  def resolve(self, test_enabled):
+    if test_enabled:
+      return repr(self)
+    return os.path.dirname(self.script_path)  # pragma: no cover
+
+  def __repr__(self):
+    return 'RECIPE[%s].resources' % self.recipe_name

[nodir, 2016/11/18 22:42:25]

shouldn't this be RECIPE_RESOURCES[%s] ?
what is RECIPE[%s]? path to the recipe without extension?

[iannucci, 2016/11/19 00:00:57]

Discussed offline, don't see a better alternative :/

RECIPE_WITHOUT_EXTENSION[%s].resources just seems long :D

+
+
 class PackageRepoBasePath(
     BasePath, namedtuple('PackageRepoBasePath', 'package')):
   def resolve(self, test_enabled):
     if test_enabled:
       return repr(self)
     return self.package.repo_root  # pragma: no cover
 
   def __repr__(self):
     return 'RECIPE_PACKAGE_REPO[%s]' % self.package.name
 
@@ skipping 51 matching lines @@
     if len(self.pieces) >= len(child.pieces):
       return False
     return child.pieces[:len(self.pieces)] == self.pieces
 
   def __repr__(self):
     s = "Path(%r" % self.base
     if self.pieces:
       s += ", %s" % ",".join(repr(x) for x in self.pieces)
 
     return s + ")"