DevTools: explicitly reveal the stack frame location upon click.

third_party/WebKit/Source/devtools/front_end/sources/CallStackSidebarPane.js

 /*
  * Copyright (C) 2008 Apple Inc. All Rights Reserved.
  *
  * Redistribution and use in source and binary forms, with or without
  * modification, are permitted provided that the following conditions
  * are met:
  * 1. Redistributions of source code must retain the above copyright
  *    notice, this list of conditions and the following disclaimer.
  * 2. Redistributions in binary form must reproduce the above copyright
  *    notice, this list of conditions and the following disclaimer in the
@@ skipping 397 matching lines @@
 
         for (var i = 0; i < this.callFrames.length; ++i) {
             var callFrameItem = this.callFrames[i];
             callFrameItem.setSelected(callFrameItem === selectedCallFrame);
             if (callFrameItem.isSelected() && callFrameItem.isHidden())
                 this._revealHiddenCallFrames();
         }
 
         WebInspector.context.setFlavor(WebInspector.DebuggerModel.CallFrame, callFrame);
         callFrame.debuggerModel.setSelectedCallFrame(callFrame);
+        var uiLocation = WebInspector.debuggerWorkspaceBinding.rawLocationToUILocation(callFrame.location());

[kozy, 2016/10/13 22:56:54]

Can we reveal location only if current
flavor(WebInspector.DebuggerModel.CallFrame) == callFrame?

+        WebInspector.Revealer.reveal(uiLocation);
     },
 
     _copyStackTrace: function()
     {
         var text = "";
         var lastCallFrame = null;
         for (var i = 0; i < this.callFrames.length; ++i) {
             var callFrame = this.callFrames[i];
             if (callFrame.isHidden())
                 continue;
@@ skipping 61 matching lines @@
         var uiLocation = liveLocation.uiLocation();
         if (!uiLocation)
             return;
         var text = uiLocation.linkText();
         this.setSubtitle(text.trimMiddle(30));
         this.subtitleElement.title = text;
     },
 
     __proto__: WebInspector.UIList.Item.prototype
 }