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1 # Copyright (c) 2013 The Chromium Authors. All rights reserved. | |
2 # Use of this source code is governed by a BSD-style license that can be | |
3 # found in the LICENSE file. | |
4 | |
5 """Class representing instrumentation test apk and jar.""" | |
6 | |
7 import os | |
8 | |
9 from pylib.instrumentation import test_jar | |
10 from pylib.utils import apk_helper | |
11 | |
12 | |
13 class TestPackage(test_jar.TestJar): | |
14 def __init__(self, apk_path, jar_path, test_support_apk_path): | |
15 test_jar.TestJar.__init__(self, jar_path) | |
16 | |
17 if not os.path.exists(apk_path): | |
18 raise Exception('%s not found, please build it' % apk_path) | |
19 if test_support_apk_path and not os.path.exists(test_support_apk_path): | |
20 raise Exception('%s not found, please build it' % test_support_apk_path) | |
21 self._apk_path = apk_path | |
22 self._apk_name = os.path.splitext(os.path.basename(apk_path))[0] | |
23 self._package_name = apk_helper.GetPackageName(self._apk_path) | |
24 self._test_support_apk_path = test_support_apk_path | |
25 | |
26 def GetApkPath(self): | |
27 """Returns the absolute path to the APK.""" | |
28 return self._apk_path | |
29 | |
30 def GetApkName(self): | |
31 """Returns the name of the apk without the suffix.""" | |
32 return self._apk_name | |
33 | |
34 def GetPackageName(self): | |
35 """Returns the package name of this APK.""" | |
36 return self._package_name | |
37 | |
38 # Override. | |
39 def Install(self, device): | |
40 device.Install(self.GetApkPath()) | |
41 if (self._test_support_apk_path and | |
42 os.path.exists(self._test_support_apk_path)): | |
43 device.Install(self._test_support_apk_path) | |
44 | |
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