Chromium Code Reviews| Index: ui/compositor/transform_animation_curve_adapter_unittest.cc |
| diff --git a/ui/compositor/transform_animation_curve_adapter_unittest.cc b/ui/compositor/transform_animation_curve_adapter_unittest.cc |
| new file mode 100644 |
| index 0000000000000000000000000000000000000000..613cf4af8c6684f6b4a2d0220b62b44a49a47067 |
| --- /dev/null |
| +++ b/ui/compositor/transform_animation_curve_adapter_unittest.cc |
| @@ -0,0 +1,59 @@ |
| +// Copyright (c) 2013 The Chromium Authors. All rights reserved. |
| +// Use of this source code is governed by a BSD-style license that can be |
| +// found in the LICENSE file. |
| + |
| +#include "ui/compositor/transform_animation_curve_adapter.h" |
| + |
| +#include <sstream> |
| + |
| +#include "base/time/time.h" |
| +#include "testing/gtest/include/gtest/gtest.h" |
| +#include "ui/compositor/test/test_utils.h" |
| + |
| +namespace ui { |
| + |
| +namespace { |
| + |
| +// Check that the inverse transform curve gives the gives a transform that when |
| +// applied on top of the parent transform gives the original transform |
| +TEST(InverseTransformCurveAdapterTest, InversesTransform) { |
| + gfx::Transform parent_start, parent_target; |
| + parent_start.Scale(0.5, 3.0); |
| + parent_start.Translate(-20.0, 30.0); |
| + parent_target.Translate(0, 100); |
| + |
| + gfx::Transform child_transform; |
| + child_transform.Rotate(-30.0); |
| + |
| + base::TimeDelta duration = base::TimeDelta::FromSeconds(1); |
| + |
| + const gfx::Transform effective_child_transform = |
| + parent_start * child_transform; |
| + |
| + TransformAnimationCurveAdapter parent_curve(Tween::LINEAR, |
| + parent_start, |
| + parent_target, |
| + duration); |
| + |
| + InverseTransformCurveAdapter child_curve(parent_curve, |
| + child_transform, |
| + duration); |
| + static const int kSteps = 1000; |
| + double step = 1.0 / kSteps; |
| + for (int i = 0; i != kSteps + 1; ++i) { |
|
danakj
2013/09/04 15:29:09
nit: i < kSteps + 1 ?
avallee
2013/09/04 15:36:53
I want to exit the loop having done 1001 steps in
danakj
2013/09/04 15:47:40
I'm not sure how < and != differ in this case. The
danakj
2013/09/04 15:48:26
(i <= kSteps) would also work if you preferred.
avallee
2013/09/04 15:50:34
Done.
|
| + std::ostringstream message; |
| + message << "Step " << i << " of " << kSteps; |
| + SCOPED_TRACE(message.str()); |
| + gfx::Transform progress_parent_transform = |
| + parent_curve.GetValue(i*step); |
| + gfx::Transform progress_child_transform = |
| + child_curve.GetValue(i*step); |
| + CheckApproximatelyEqual(effective_child_transform, |
| + progress_parent_transform * |
| + progress_child_transform); |
| + } |
| +} |
| + |
| +} // namespace |
| + |
| +} // namespace ui |