third_party/WebKit/PerformanceTests/DOM/remove_child_with_selection.html - Issue 2212293002: Use LayoutObject::selectionState() to check whether selection contains node or not

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Issue 2212293002: Use LayoutObject::selectionState() to check whether selection contains node or not (Closed) Base URL: https://chromium.googlesource.com/chromium/src.git@master

Patch Set: 2016-08-08T11:10:01 Created 4 years, 4 months ago

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	1 <!doctype html>

	2 <script src="../resources/runner.js"></script>

	3 <div id="target">target</div>

	4 <div id="sample" style="display: none"></div>

	5 <script>

	6 var selection = window.getSelection();

	7 selection.selectAllChildren(document.getElementById('target'));

	8 var sample = document.getElementById('sample');

	9 for (var index = 0; index < 1000; ++index) {

	10 var span = document.createElement('span');

	11 span.textContent = `item ${index}\n`;

	12 sample.appendChild(span);

	13 }

	14 PerfTestRunner.measureTime({

	15 description: 'Measures performance of removeChild() with selection.',

	16

	17 run: function() {

	18 var copy = sample.cloneNode(true);

	19 while (sample.firstChild)

	20 sample.removeChild(sample.firstChild);

	21 while (copy.firstChild)

	22 sample.appendChild(copy.firstChild);

	23 },

	24 });

	25 </script>

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