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| 1 # Copyright (c) 2013 The Chromium Authors. All rights reserved. |
| 2 # Use of this source code is governed by a BSD-style license that can be |
| 3 # found in the LICENSE file. |
| 4 |
| 5 """Class representing instrumentation test apk and jar.""" |
| 6 |
| 7 import os |
| 8 |
| 9 from pylib.instrumentation import test_jar |
| 10 from pylib.utils import apk_helper |
| 11 |
| 12 |
| 13 class TestPackage(test_jar.TestJar): |
| 14 def __init__(self, apk_path, jar_path, test_support_apk_path): |
| 15 test_jar.TestJar.__init__(self, jar_path) |
| 16 |
| 17 if not os.path.exists(apk_path): |
| 18 raise Exception('%s not found, please build it' % apk_path) |
| 19 if test_support_apk_path and not os.path.exists(test_support_apk_path): |
| 20 raise Exception('%s not found, please build it' % test_support_apk_path) |
| 21 self._apk_path = apk_path |
| 22 self._apk_name = os.path.splitext(os.path.basename(apk_path))[0] |
| 23 self._package_name = apk_helper.GetPackageName(self._apk_path) |
| 24 self._test_support_apk_path = test_support_apk_path |
| 25 |
| 26 def GetApkPath(self): |
| 27 """Returns the absolute path to the APK.""" |
| 28 return self._apk_path |
| 29 |
| 30 def GetApkName(self): |
| 31 """Returns the name of the apk without the suffix.""" |
| 32 return self._apk_name |
| 33 |
| 34 def GetPackageName(self): |
| 35 """Returns the package name of this APK.""" |
| 36 return self._package_name |
| 37 |
| 38 # Override. |
| 39 def Install(self, device): |
| 40 device.Install(self.GetApkPath()) |
| 41 if (self._test_support_apk_path and |
| 42 os.path.exists(self._test_support_apk_path)): |
| 43 device.Install(self._test_support_apk_path) |
| 44 |
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