OLD | NEW |
| (Empty) |
1 /* crypto/bn/bn_sqrt.c */ | |
2 /* Written by Lenka Fibikova <fibikova@exp-math.uni-essen.de> | |
3 * and Bodo Moeller for the OpenSSL project. */ | |
4 /* ==================================================================== | |
5 * Copyright (c) 1998-2000 The OpenSSL Project. All rights reserved. | |
6 * | |
7 * Redistribution and use in source and binary forms, with or without | |
8 * modification, are permitted provided that the following conditions | |
9 * are met: | |
10 * | |
11 * 1. Redistributions of source code must retain the above copyright | |
12 * notice, this list of conditions and the following disclaimer. | |
13 * | |
14 * 2. Redistributions in binary form must reproduce the above copyright | |
15 * notice, this list of conditions and the following disclaimer in | |
16 * the documentation and/or other materials provided with the | |
17 * distribution. | |
18 * | |
19 * 3. All advertising materials mentioning features or use of this | |
20 * software must display the following acknowledgment: | |
21 * "This product includes software developed by the OpenSSL Project | |
22 * for use in the OpenSSL Toolkit. (http://www.openssl.org/)" | |
23 * | |
24 * 4. The names "OpenSSL Toolkit" and "OpenSSL Project" must not be used to | |
25 * endorse or promote products derived from this software without | |
26 * prior written permission. For written permission, please contact | |
27 * openssl-core@openssl.org. | |
28 * | |
29 * 5. Products derived from this software may not be called "OpenSSL" | |
30 * nor may "OpenSSL" appear in their names without prior written | |
31 * permission of the OpenSSL Project. | |
32 * | |
33 * 6. Redistributions of any form whatsoever must retain the following | |
34 * acknowledgment: | |
35 * "This product includes software developed by the OpenSSL Project | |
36 * for use in the OpenSSL Toolkit (http://www.openssl.org/)" | |
37 * | |
38 * THIS SOFTWARE IS PROVIDED BY THE OpenSSL PROJECT ``AS IS'' AND ANY | |
39 * EXPRESSED OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE | |
40 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR | |
41 * PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE OpenSSL PROJECT OR | |
42 * ITS CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, | |
43 * SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT | |
44 * NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; | |
45 * LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) | |
46 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, | |
47 * STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) | |
48 * ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED | |
49 * OF THE POSSIBILITY OF SUCH DAMAGE. | |
50 * ==================================================================== | |
51 * | |
52 * This product includes cryptographic software written by Eric Young | |
53 * (eay@cryptsoft.com). This product includes software written by Tim | |
54 * Hudson (tjh@cryptsoft.com). | |
55 * | |
56 */ | |
57 | |
58 #include "cryptlib.h" | |
59 #include "bn_lcl.h" | |
60 | |
61 | |
62 BIGNUM *BN_mod_sqrt(BIGNUM *in, const BIGNUM *a, const BIGNUM *p, BN_CTX *ctx) | |
63 /* Returns 'ret' such that | |
64 * ret^2 == a (mod p), | |
65 * using the Tonelli/Shanks algorithm (cf. Henri Cohen, "A Course | |
66 * in Algebraic Computational Number Theory", algorithm 1.5.1). | |
67 * 'p' must be prime! | |
68 */ | |
69 { | |
70 BIGNUM *ret = in; | |
71 int err = 1; | |
72 int r; | |
73 BIGNUM *A, *b, *q, *t, *x, *y; | |
74 int e, i, j; | |
75 | |
76 if (!BN_is_odd(p) || BN_abs_is_word(p, 1)) | |
77 { | |
78 if (BN_abs_is_word(p, 2)) | |
79 { | |
80 if (ret == NULL) | |
81 ret = BN_new(); | |
82 if (ret == NULL) | |
83 goto end; | |
84 if (!BN_set_word(ret, BN_is_bit_set(a, 0))) | |
85 { | |
86 if (ret != in) | |
87 BN_free(ret); | |
88 return NULL; | |
89 } | |
90 bn_check_top(ret); | |
91 return ret; | |
92 } | |
93 | |
94 BNerr(BN_F_BN_MOD_SQRT, BN_R_P_IS_NOT_PRIME); | |
95 return(NULL); | |
96 } | |
97 | |
98 if (BN_is_zero(a) || BN_is_one(a)) | |
99 { | |
100 if (ret == NULL) | |
101 ret = BN_new(); | |
102 if (ret == NULL) | |
103 goto end; | |
104 if (!BN_set_word(ret, BN_is_one(a))) | |
105 { | |
106 if (ret != in) | |
107 BN_free(ret); | |
108 return NULL; | |
109 } | |
110 bn_check_top(ret); | |
111 return ret; | |
112 } | |
113 | |
114 BN_CTX_start(ctx); | |
115 A = BN_CTX_get(ctx); | |
116 b = BN_CTX_get(ctx); | |
117 q = BN_CTX_get(ctx); | |
118 t = BN_CTX_get(ctx); | |
119 x = BN_CTX_get(ctx); | |
120 y = BN_CTX_get(ctx); | |
121 if (y == NULL) goto end; | |
122 | |
123 if (ret == NULL) | |
124 ret = BN_new(); | |
125 if (ret == NULL) goto end; | |
126 | |
127 /* A = a mod p */ | |
128 if (!BN_nnmod(A, a, p, ctx)) goto end; | |
129 | |
130 /* now write |p| - 1 as 2^e*q where q is odd */ | |
131 e = 1; | |
132 while (!BN_is_bit_set(p, e)) | |
133 e++; | |
134 /* we'll set q later (if needed) */ | |
135 | |
136 if (e == 1) | |
137 { | |
138 /* The easy case: (|p|-1)/2 is odd, so 2 has an inverse | |
139 * modulo (|p|-1)/2, and square roots can be computed | |
140 * directly by modular exponentiation. | |
141 * We have | |
142 * 2 * (|p|+1)/4 == 1 (mod (|p|-1)/2), | |
143 * so we can use exponent (|p|+1)/4, i.e. (|p|-3)/4 + 1. | |
144 */ | |
145 if (!BN_rshift(q, p, 2)) goto end; | |
146 q->neg = 0; | |
147 if (!BN_add_word(q, 1)) goto end; | |
148 if (!BN_mod_exp(ret, A, q, p, ctx)) goto end; | |
149 err = 0; | |
150 goto vrfy; | |
151 } | |
152 | |
153 if (e == 2) | |
154 { | |
155 /* |p| == 5 (mod 8) | |
156 * | |
157 * In this case 2 is always a non-square since | |
158 * Legendre(2,p) = (-1)^((p^2-1)/8) for any odd prime. | |
159 * So if a really is a square, then 2*a is a non-square. | |
160 * Thus for | |
161 * b := (2*a)^((|p|-5)/8), | |
162 * i := (2*a)*b^2 | |
163 * we have | |
164 * i^2 = (2*a)^((1 + (|p|-5)/4)*2) | |
165 * = (2*a)^((p-1)/2) | |
166 * = -1; | |
167 * so if we set | |
168 * x := a*b*(i-1), | |
169 * then | |
170 * x^2 = a^2 * b^2 * (i^2 - 2*i + 1) | |
171 * = a^2 * b^2 * (-2*i) | |
172 * = a*(-i)*(2*a*b^2) | |
173 * = a*(-i)*i | |
174 * = a. | |
175 * | |
176 * (This is due to A.O.L. Atkin, | |
177 * <URL: http://listserv.nodak.edu/scripts/wa.exe?A2=ind9211&L=n
mbrthry&O=T&P=562>, | |
178 * November 1992.) | |
179 */ | |
180 | |
181 /* t := 2*a */ | |
182 if (!BN_mod_lshift1_quick(t, A, p)) goto end; | |
183 | |
184 /* b := (2*a)^((|p|-5)/8) */ | |
185 if (!BN_rshift(q, p, 3)) goto end; | |
186 q->neg = 0; | |
187 if (!BN_mod_exp(b, t, q, p, ctx)) goto end; | |
188 | |
189 /* y := b^2 */ | |
190 if (!BN_mod_sqr(y, b, p, ctx)) goto end; | |
191 | |
192 /* t := (2*a)*b^2 - 1*/ | |
193 if (!BN_mod_mul(t, t, y, p, ctx)) goto end; | |
194 if (!BN_sub_word(t, 1)) goto end; | |
195 | |
196 /* x = a*b*t */ | |
197 if (!BN_mod_mul(x, A, b, p, ctx)) goto end; | |
198 if (!BN_mod_mul(x, x, t, p, ctx)) goto end; | |
199 | |
200 if (!BN_copy(ret, x)) goto end; | |
201 err = 0; | |
202 goto vrfy; | |
203 } | |
204 | |
205 /* e > 2, so we really have to use the Tonelli/Shanks algorithm. | |
206 * First, find some y that is not a square. */ | |
207 if (!BN_copy(q, p)) goto end; /* use 'q' as temp */ | |
208 q->neg = 0; | |
209 i = 2; | |
210 do | |
211 { | |
212 /* For efficiency, try small numbers first; | |
213 * if this fails, try random numbers. | |
214 */ | |
215 if (i < 22) | |
216 { | |
217 if (!BN_set_word(y, i)) goto end; | |
218 } | |
219 else | |
220 { | |
221 if (!BN_pseudo_rand(y, BN_num_bits(p), 0, 0)) goto end; | |
222 if (BN_ucmp(y, p) >= 0) | |
223 { | |
224 if (!(p->neg ? BN_add : BN_sub)(y, y, p)) goto e
nd; | |
225 } | |
226 /* now 0 <= y < |p| */ | |
227 if (BN_is_zero(y)) | |
228 if (!BN_set_word(y, i)) goto end; | |
229 } | |
230 | |
231 r = BN_kronecker(y, q, ctx); /* here 'q' is |p| */ | |
232 if (r < -1) goto end; | |
233 if (r == 0) | |
234 { | |
235 /* m divides p */ | |
236 BNerr(BN_F_BN_MOD_SQRT, BN_R_P_IS_NOT_PRIME); | |
237 goto end; | |
238 } | |
239 } | |
240 while (r == 1 && ++i < 82); | |
241 | |
242 if (r != -1) | |
243 { | |
244 /* Many rounds and still no non-square -- this is more likely | |
245 * a bug than just bad luck. | |
246 * Even if p is not prime, we should have found some y | |
247 * such that r == -1. | |
248 */ | |
249 BNerr(BN_F_BN_MOD_SQRT, BN_R_TOO_MANY_ITERATIONS); | |
250 goto end; | |
251 } | |
252 | |
253 /* Here's our actual 'q': */ | |
254 if (!BN_rshift(q, q, e)) goto end; | |
255 | |
256 /* Now that we have some non-square, we can find an element | |
257 * of order 2^e by computing its q'th power. */ | |
258 if (!BN_mod_exp(y, y, q, p, ctx)) goto end; | |
259 if (BN_is_one(y)) | |
260 { | |
261 BNerr(BN_F_BN_MOD_SQRT, BN_R_P_IS_NOT_PRIME); | |
262 goto end; | |
263 } | |
264 | |
265 /* Now we know that (if p is indeed prime) there is an integer | |
266 * k, 0 <= k < 2^e, such that | |
267 * | |
268 * a^q * y^k == 1 (mod p). | |
269 * | |
270 * As a^q is a square and y is not, k must be even. | |
271 * q+1 is even, too, so there is an element | |
272 * | |
273 * X := a^((q+1)/2) * y^(k/2), | |
274 * | |
275 * and it satisfies | |
276 * | |
277 * X^2 = a^q * a * y^k | |
278 * = a, | |
279 * | |
280 * so it is the square root that we are looking for. | |
281 */ | |
282 | |
283 /* t := (q-1)/2 (note that q is odd) */ | |
284 if (!BN_rshift1(t, q)) goto end; | |
285 | |
286 /* x := a^((q-1)/2) */ | |
287 if (BN_is_zero(t)) /* special case: p = 2^e + 1 */ | |
288 { | |
289 if (!BN_nnmod(t, A, p, ctx)) goto end; | |
290 if (BN_is_zero(t)) | |
291 { | |
292 /* special case: a == 0 (mod p) */ | |
293 BN_zero(ret); | |
294 err = 0; | |
295 goto end; | |
296 } | |
297 else | |
298 if (!BN_one(x)) goto end; | |
299 } | |
300 else | |
301 { | |
302 if (!BN_mod_exp(x, A, t, p, ctx)) goto end; | |
303 if (BN_is_zero(x)) | |
304 { | |
305 /* special case: a == 0 (mod p) */ | |
306 BN_zero(ret); | |
307 err = 0; | |
308 goto end; | |
309 } | |
310 } | |
311 | |
312 /* b := a*x^2 (= a^q) */ | |
313 if (!BN_mod_sqr(b, x, p, ctx)) goto end; | |
314 if (!BN_mod_mul(b, b, A, p, ctx)) goto end; | |
315 | |
316 /* x := a*x (= a^((q+1)/2)) */ | |
317 if (!BN_mod_mul(x, x, A, p, ctx)) goto end; | |
318 | |
319 while (1) | |
320 { | |
321 /* Now b is a^q * y^k for some even k (0 <= k < 2^E | |
322 * where E refers to the original value of e, which we | |
323 * don't keep in a variable), and x is a^((q+1)/2) * y^(k/2)
. | |
324 * | |
325 * We have a*b = x^2, | |
326 * y^2^(e-1) = -1, | |
327 * b^2^(e-1) = 1. | |
328 */ | |
329 | |
330 if (BN_is_one(b)) | |
331 { | |
332 if (!BN_copy(ret, x)) goto end; | |
333 err = 0; | |
334 goto vrfy; | |
335 } | |
336 | |
337 | |
338 /* find smallest i such that b^(2^i) = 1 */ | |
339 i = 1; | |
340 if (!BN_mod_sqr(t, b, p, ctx)) goto end; | |
341 while (!BN_is_one(t)) | |
342 { | |
343 i++; | |
344 if (i == e) | |
345 { | |
346 BNerr(BN_F_BN_MOD_SQRT, BN_R_NOT_A_SQUARE); | |
347 goto end; | |
348 } | |
349 if (!BN_mod_mul(t, t, t, p, ctx)) goto end; | |
350 } | |
351 | |
352 | |
353 /* t := y^2^(e - i - 1) */ | |
354 if (!BN_copy(t, y)) goto end; | |
355 for (j = e - i - 1; j > 0; j--) | |
356 { | |
357 if (!BN_mod_sqr(t, t, p, ctx)) goto end; | |
358 } | |
359 if (!BN_mod_mul(y, t, t, p, ctx)) goto end; | |
360 if (!BN_mod_mul(x, x, t, p, ctx)) goto end; | |
361 if (!BN_mod_mul(b, b, y, p, ctx)) goto end; | |
362 e = i; | |
363 } | |
364 | |
365 vrfy: | |
366 if (!err) | |
367 { | |
368 /* verify the result -- the input might have been not a square | |
369 * (test added in 0.9.8) */ | |
370 | |
371 if (!BN_mod_sqr(x, ret, p, ctx)) | |
372 err = 1; | |
373 | |
374 if (!err && 0 != BN_cmp(x, A)) | |
375 { | |
376 BNerr(BN_F_BN_MOD_SQRT, BN_R_NOT_A_SQUARE); | |
377 err = 1; | |
378 } | |
379 } | |
380 | |
381 end: | |
382 if (err) | |
383 { | |
384 if (ret != NULL && ret != in) | |
385 { | |
386 BN_clear_free(ret); | |
387 } | |
388 ret = NULL; | |
389 } | |
390 BN_CTX_end(ctx); | |
391 bn_check_top(ret); | |
392 return ret; | |
393 } | |
OLD | NEW |