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Side by Side Diff: openssl/crypto/bn/bn_recp.c

Issue 2072073002: Delete bundled copy of OpenSSL and replace with README. (Closed) Base URL: https://chromium.googlesource.com/chromium/deps/openssl@master
Patch Set: Delete bundled copy of OpenSSL and replace with README. Created 4 years, 6 months ago
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1 /* crypto/bn/bn_recp.c */
2 /* Copyright (C) 1995-1998 Eric Young (eay@cryptsoft.com)
3 * All rights reserved.
4 *
5 * This package is an SSL implementation written
6 * by Eric Young (eay@cryptsoft.com).
7 * The implementation was written so as to conform with Netscapes SSL.
8 *
9 * This library is free for commercial and non-commercial use as long as
10 * the following conditions are aheared to. The following conditions
11 * apply to all code found in this distribution, be it the RC4, RSA,
12 * lhash, DES, etc., code; not just the SSL code. The SSL documentation
13 * included with this distribution is covered by the same copyright terms
14 * except that the holder is Tim Hudson (tjh@cryptsoft.com).
15 *
16 * Copyright remains Eric Young's, and as such any Copyright notices in
17 * the code are not to be removed.
18 * If this package is used in a product, Eric Young should be given attribution
19 * as the author of the parts of the library used.
20 * This can be in the form of a textual message at program startup or
21 * in documentation (online or textual) provided with the package.
22 *
23 * Redistribution and use in source and binary forms, with or without
24 * modification, are permitted provided that the following conditions
25 * are met:
26 * 1. Redistributions of source code must retain the copyright
27 * notice, this list of conditions and the following disclaimer.
28 * 2. Redistributions in binary form must reproduce the above copyright
29 * notice, this list of conditions and the following disclaimer in the
30 * documentation and/or other materials provided with the distribution.
31 * 3. All advertising materials mentioning features or use of this software
32 * must display the following acknowledgement:
33 * "This product includes cryptographic software written by
34 * Eric Young (eay@cryptsoft.com)"
35 * The word 'cryptographic' can be left out if the rouines from the library
36 * being used are not cryptographic related :-).
37 * 4. If you include any Windows specific code (or a derivative thereof) from
38 * the apps directory (application code) you must include an acknowledgement:
39 * "This product includes software written by Tim Hudson (tjh@cryptsoft.com)"
40 *
41 * THIS SOFTWARE IS PROVIDED BY ERIC YOUNG ``AS IS'' AND
42 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
43 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
44 * ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
45 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
46 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
47 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
48 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
49 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
50 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
51 * SUCH DAMAGE.
52 *
53 * The licence and distribution terms for any publically available version or
54 * derivative of this code cannot be changed. i.e. this code cannot simply be
55 * copied and put under another distribution licence
56 * [including the GNU Public Licence.]
57 */
58
59 #include <stdio.h>
60 #include "cryptlib.h"
61 #include "bn_lcl.h"
62
63 void BN_RECP_CTX_init(BN_RECP_CTX *recp)
64 {
65 BN_init(&(recp->N));
66 BN_init(&(recp->Nr));
67 recp->num_bits=0;
68 recp->flags=0;
69 }
70
71 BN_RECP_CTX *BN_RECP_CTX_new(void)
72 {
73 BN_RECP_CTX *ret;
74
75 if ((ret=(BN_RECP_CTX *)OPENSSL_malloc(sizeof(BN_RECP_CTX))) == NULL)
76 return(NULL);
77
78 BN_RECP_CTX_init(ret);
79 ret->flags=BN_FLG_MALLOCED;
80 return(ret);
81 }
82
83 void BN_RECP_CTX_free(BN_RECP_CTX *recp)
84 {
85 if(recp == NULL)
86 return;
87
88 BN_free(&(recp->N));
89 BN_free(&(recp->Nr));
90 if (recp->flags & BN_FLG_MALLOCED)
91 OPENSSL_free(recp);
92 }
93
94 int BN_RECP_CTX_set(BN_RECP_CTX *recp, const BIGNUM *d, BN_CTX *ctx)
95 {
96 if (!BN_copy(&(recp->N),d)) return 0;
97 BN_zero(&(recp->Nr));
98 recp->num_bits=BN_num_bits(d);
99 recp->shift=0;
100 return(1);
101 }
102
103 int BN_mod_mul_reciprocal(BIGNUM *r, const BIGNUM *x, const BIGNUM *y,
104 BN_RECP_CTX *recp, BN_CTX *ctx)
105 {
106 int ret=0;
107 BIGNUM *a;
108 const BIGNUM *ca;
109
110 BN_CTX_start(ctx);
111 if ((a = BN_CTX_get(ctx)) == NULL) goto err;
112 if (y != NULL)
113 {
114 if (x == y)
115 { if (!BN_sqr(a,x,ctx)) goto err; }
116 else
117 { if (!BN_mul(a,x,y,ctx)) goto err; }
118 ca = a;
119 }
120 else
121 ca=x; /* Just do the mod */
122
123 ret = BN_div_recp(NULL,r,ca,recp,ctx);
124 err:
125 BN_CTX_end(ctx);
126 bn_check_top(r);
127 return(ret);
128 }
129
130 int BN_div_recp(BIGNUM *dv, BIGNUM *rem, const BIGNUM *m,
131 BN_RECP_CTX *recp, BN_CTX *ctx)
132 {
133 int i,j,ret=0;
134 BIGNUM *a,*b,*d,*r;
135
136 BN_CTX_start(ctx);
137 a=BN_CTX_get(ctx);
138 b=BN_CTX_get(ctx);
139 if (dv != NULL)
140 d=dv;
141 else
142 d=BN_CTX_get(ctx);
143 if (rem != NULL)
144 r=rem;
145 else
146 r=BN_CTX_get(ctx);
147 if (a == NULL || b == NULL || d == NULL || r == NULL) goto err;
148
149 if (BN_ucmp(m,&(recp->N)) < 0)
150 {
151 BN_zero(d);
152 if (!BN_copy(r,m)) return 0;
153 BN_CTX_end(ctx);
154 return(1);
155 }
156
157 /* We want the remainder
158 * Given input of ABCDEF / ab
159 * we need multiply ABCDEF by 3 digests of the reciprocal of ab
160 *
161 */
162
163 /* i := max(BN_num_bits(m), 2*BN_num_bits(N)) */
164 i=BN_num_bits(m);
165 j=recp->num_bits<<1;
166 if (j>i) i=j;
167
168 /* Nr := round(2^i / N) */
169 if (i != recp->shift)
170 recp->shift=BN_reciprocal(&(recp->Nr),&(recp->N),
171 i,ctx); /* BN_reciprocal returns i, or -1 for an error * /
172 if (recp->shift == -1) goto err;
173
174 /* d := |round(round(m / 2^BN_num_bits(N)) * recp->Nr / 2^(i - BN_num_bi ts(N)))|
175 * = |round(round(m / 2^BN_num_bits(N)) * round(2^i / N) / 2^(i - BN_ num_bits(N)))|
176 * <= |(m / 2^BN_num_bits(N)) * (2^i / N) * (2^BN_num_bits(N) / 2^i)|
177 * = |m/N|
178 */
179 if (!BN_rshift(a,m,recp->num_bits)) goto err;
180 if (!BN_mul(b,a,&(recp->Nr),ctx)) goto err;
181 if (!BN_rshift(d,b,i-recp->num_bits)) goto err;
182 d->neg=0;
183
184 if (!BN_mul(b,&(recp->N),d,ctx)) goto err;
185 if (!BN_usub(r,m,b)) goto err;
186 r->neg=0;
187
188 #if 1
189 j=0;
190 while (BN_ucmp(r,&(recp->N)) >= 0)
191 {
192 if (j++ > 2)
193 {
194 BNerr(BN_F_BN_DIV_RECP,BN_R_BAD_RECIPROCAL);
195 goto err;
196 }
197 if (!BN_usub(r,r,&(recp->N))) goto err;
198 if (!BN_add_word(d,1)) goto err;
199 }
200 #endif
201
202 r->neg=BN_is_zero(r)?0:m->neg;
203 d->neg=m->neg^recp->N.neg;
204 ret=1;
205 err:
206 BN_CTX_end(ctx);
207 bn_check_top(dv);
208 bn_check_top(rem);
209 return(ret);
210 }
211
212 /* len is the expected size of the result
213 * We actually calculate with an extra word of precision, so
214 * we can do faster division if the remainder is not required.
215 */
216 /* r := 2^len / m */
217 int BN_reciprocal(BIGNUM *r, const BIGNUM *m, int len, BN_CTX *ctx)
218 {
219 int ret= -1;
220 BIGNUM *t;
221
222 BN_CTX_start(ctx);
223 if((t = BN_CTX_get(ctx)) == NULL) goto err;
224
225 if (!BN_set_bit(t,len)) goto err;
226
227 if (!BN_div(r,NULL,t,m,ctx)) goto err;
228
229 ret=len;
230 err:
231 bn_check_top(r);
232 BN_CTX_end(ctx);
233 return(ret);
234 }
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