Update SCons to latest checkpoint release, 1.2.0.d20090113....

third_party/scons/scons-local/SCons/Tool/JavaCommon.py

 """SCons.Tool.JavaCommon
 
 Stuff for processing Java.
 
 """
 
 #
-# Copyright (c) 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008 The SCons Foundation
+# Copyright (c) 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008, 2009 The SCons Foundation
 #
 # Permission is hereby granted, free of charge, to any person obtaining
 # a copy of this software and associated documentation files (the
 # "Software"), to deal in the Software without restriction, including
 # without limitation the rights to use, copy, modify, merge, publish,
 # distribute, sublicense, and/or sell copies of the Software, and to
 # permit persons to whom the Software is furnished to do so, subject to
 # the following conditions:
 #
 # The above copyright notice and this permission notice shall be included
 # in all copies or substantial portions of the Software.
 #
 # THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY
 # KIND, EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE
 # WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
 # NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE
 # LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION
 # OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION
 # WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
 #
 
-__revision__ = "src/engine/SCons/Tool/JavaCommon.py 3842 2008/12/20 22:59:52 scons"
+__revision__ = "src/engine/SCons/Tool/JavaCommon.py 3897 2009/01/13 06:45:54 scons"
 
 import os
 import os.path
 import re
 import string
 
 java_parsing = 1
 
 default_java_version = '1.4'
 
@@ skipping 267 matching lines @@
     # to how long the Java compiler itself seems to take...).
 
     def parse_java_file(fn):
         """ "Parse" a .java file.
 
         This actually just splits the file name, so the assumption here
         is that the file name matches the public class name, and that
         the path to the file is the same as the package name.
         """
         return os.path.split(file)