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Side by Side Diff: include/core/SkGeometry.h

Issue 18258005: Add implicit hairline conic rendering to GPU (Closed) Base URL: https://skia.googlecode.com/svn/trunk
Patch Set: Created 7 years, 5 months ago
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1 1
2 /* 2 /*
3 * Copyright 2006 The Android Open Source Project 3 * Copyright 2006 The Android Open Source Project
4 * 4 *
5 * Use of this source code is governed by a BSD-style license that can be 5 * Use of this source code is governed by a BSD-style license that can be
6 * found in the LICENSE file. 6 * found in the LICENSE file.
7 */ 7 */
8 8
9 9
10 #ifndef SkGeometry_DEFINED 10 #ifndef SkGeometry_DEFINED
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65 65
66 /** Given 3 points on a quadratic bezier, chop it into 1, 2 beziers such that 66 /** Given 3 points on a quadratic bezier, chop it into 1, 2 beziers such that
67 the resulting beziers are monotonic in Y. This is called by the scan convert er. 67 the resulting beziers are monotonic in Y. This is called by the scan convert er.
68 Depending on what is returned, dst[] is treated as follows 68 Depending on what is returned, dst[] is treated as follows
69 0 dst[0..2] is the original quad 69 0 dst[0..2] is the original quad
70 1 dst[0..2] and dst[2..4] are the two new quads 70 1 dst[0..2] and dst[2..4] are the two new quads
71 */ 71 */
72 int SkChopQuadAtYExtrema(const SkPoint src[3], SkPoint dst[5]); 72 int SkChopQuadAtYExtrema(const SkPoint src[3], SkPoint dst[5]);
73 int SkChopQuadAtXExtrema(const SkPoint src[3], SkPoint dst[5]); 73 int SkChopQuadAtXExtrema(const SkPoint src[3], SkPoint dst[5]);
74 74
75 /** Given 3 points on a quadratic bezier, if the point of maximum
76 curvature exists on the segment, returns the t value for this
77 point along the curve. Otherwise it will return a value of 0.
78 */
79 float SkFindQuadMaxCurvature(const SkPoint src[3]);
80
75 /** Given 3 points on a quadratic bezier, divide it into 2 quadratics 81 /** Given 3 points on a quadratic bezier, divide it into 2 quadratics
76 if the point of maximum curvature exists on the quad segment. 82 if the point of maximum curvature exists on the quad segment.
77 Depending on what is returned, dst[] is treated as follows 83 Depending on what is returned, dst[] is treated as follows
78 1 dst[0..2] is the original quad 84 1 dst[0..2] is the original quad
79 2 dst[0..2] and dst[2..4] are the two new quads 85 2 dst[0..2] and dst[2..4] are the two new quads
80 If dst == null, it is ignored and only the count is returned. 86 If dst == null, it is ignored and only the count is returned.
81 */ 87 */
82 int SkChopQuadAtMaxCurvature(const SkPoint src[3], SkPoint dst[5]); 88 int SkChopQuadAtMaxCurvature(const SkPoint src[3], SkPoint dst[5]);
83 89
84 /** Given 3 points on a quadratic bezier, use degree elevation to 90 /** Given 3 points on a quadratic bezier, use degree elevation to
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292 private: 298 private:
293 enum { 299 enum {
294 kQuadCount = 8, // should handle most conics 300 kQuadCount = 8, // should handle most conics
295 kPointCount = 1 + 2 * kQuadCount, 301 kPointCount = 1 + 2 * kQuadCount,
296 }; 302 };
297 SkAutoSTMalloc<kPointCount, SkPoint> fStorage; 303 SkAutoSTMalloc<kPointCount, SkPoint> fStorage;
298 int fQuadCount; // #quads for current usage 304 int fQuadCount; // #quads for current usage
299 }; 305 };
300 306
301 #endif 307 #endif
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