Fixed position elements should layout relative to transformed container

Source/core/rendering/RenderLayer.cpp

 /*
  * Copyright (C) 2006, 2007, 2008, 2009, 2010, 2011, 2012 Apple Inc. All rights reserved.
  *
  * Portions are Copyright (C) 1998 Netscape Communications Corporation.
  *
  * Other contributors:
  *   Robert O'Callahan <roc+@cs.cmu.edu>
  *   David Baron <dbaron@fas.harvard.edu>
  *   Christian Biesinger <cbiesinger@web.de>
  *   Randall Jesup <rjesup@wgate.com>
@@ skipping 1864 matching lines @@
         ASSERT(fixedPositionContainerLayer); // We should have hit the RenderView's layer at least.
 
         if (fixedPositionContainerLayer != ancestorLayer) {
             LayoutPoint fixedContainerCoords;
             layer->convertToLayerCoords(fixedPositionContainerLayer, fixedContainerCoords);
 
             LayoutPoint ancestorCoords;
             ancestorLayer->convertToLayerCoords(fixedPositionContainerLayer, ancestorCoords);
 
             location += (fixedContainerCoords - ancestorCoords);
-            return ancestorLayer;
+        } else {
+            location += toSize(layer->location());
         }
+        return ancestorLayer;
     }
     
     RenderLayer* parentLayer;
     if (position == AbsolutePosition || position == FixedPosition) {
         // Do what enclosingPositionedAncestor() does, but check for ancestorLayer along the way.
         parentLayer = layer->parent();
         bool foundAncestorFirst = false;
         while (parentLayer) {
             // RenderFlowThread is a positioned container, child of RenderView, positioned at (0,0).
             // This implies that, for out-of-flow positioned elements inside a RenderFlowThread,
@@ skipping 4509 matching lines @@
     }
 }
 
 void showLayerTree(const WebCore::RenderObject* renderer)
 {
     if (!renderer)
         return;
     showLayerTree(renderer->enclosingLayer());
 }
 #endif