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Side by Side Diff: sdk/lib/core/double.dart

Issue 15333006: Rewrite double.parse. (Closed) Base URL: https://dart.googlecode.com/svn/branches/bleeding_edge/dart
Patch Set: Add parenthesis. Created 7 years, 7 months ago
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1 // Copyright (c) 2012, the Dart project authors. Please see the AUTHORS file 1 // Copyright (c) 2012, the Dart project authors. Please see the AUTHORS file
2 // for details. All rights reserved. Use of this source code is governed by a 2 // for details. All rights reserved. Use of this source code is governed by a
3 // BSD-style license that can be found in the LICENSE file. 3 // BSD-style license that can be found in the LICENSE file.
4 4
5 part of dart.core; 5 part of dart.core;
6 6
7 // TODO: Convert this abstract class into a concrete class double 7 // TODO: Convert this abstract class into a concrete class double
8 // that uses the patch class functionality to account for the 8 // that uses the patch class functionality to account for the
9 // different platform implementations. 9 // different platform implementations.
10 10
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126 * Returns "-0.0" for negative zero. 126 * Returns "-0.0" for negative zero.
127 * 127 *
128 * It should always be the case that if [:d:] is a [double], then 128 * It should always be the case that if [:d:] is a [double], then
129 * [:d == double.parse(d.toString()):]. 129 * [:d == double.parse(d.toString()):].
130 */ 130 */
131 String toString(); 131 String toString();
132 132
133 /** 133 /**
134 * Parse [source] as an double literal and return its value. 134 * Parse [source] as an double literal and return its value.
135 * 135 *
136 * Accepts the same format as double literals: 136 * Accepts the following format:
137 * [: ['+'|'-'] [digit* '.'] digit+ [('e'|'E') ['+'|'-'] digit+] :] 137 * `/^\s*[+-]?(?:Infinity|NaN|(?:\.\d+|\d+(?:\.\d*)?)(?:[eE][+-]?\d+)?)\s*$`.
Lasse Reichstein Nielsen 2013/05/21 06:12:09 Don't use RegExp as specification. It's unreadable
floitsch 2013/05/21 14:39:31 Removed the regexp. As discussed keeping the new b
138 * 138 *
139 * Also recognizes "NaN", "Infinity" and "-Infinity" as inputs and 139 * In English this equals an optional sign followed by either, "Infinity",
140 * returns the corresponding double value. 140 * "NaN" or a double number. A double number is composed of the mantissa and
Lasse Reichstein Nielsen 2013/05/21 06:12:09 This accepts -NaN, which is meaningless. Please av
floitsch 2013/05/21 14:39:31 As discussed. keeping.
141 * and optional exponent part. The mantissa is either a dot followed by a
142 * sequence of digits, or a sequence of digits optionally followed by a dot
143 * and more digits. The (optional) exponent part consists of the character
144 * "e" or "E", an optional sign, and the exponent digits.
141 * 145 *
142 * If the [soure] is not a valid double literal, the [handleError] 146 * The whole double may be surrounded by whitespace.
147 *
148 * If the [source] is not a valid double literal, the [handleError]
143 * is called with the [source] as argument, and its return value is 149 * is called with the [source] as argument, and its return value is
144 * used instead. If no handleError is provided, a [FormatException] 150 * used instead. If no handleError is provided, a [FormatException]
145 * is thrown. 151 * is thrown.
152 *
153 * Examples of accepted strings:
154 *
155 * "3.14"
156 * " 3.14 \xA0"
157 * "0."
158 * ".0"
159 * "-1.e3"
160 * "1234E+7"
161 * "+.12e-9"
162 * "-NaN"
146 */ 163 */
147 external static double parse(String source, 164 external static double parse(String source,
148 [double handleError(String source)]); 165 [double handleError(String source)]);
149 } 166 }
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