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| 1 #!/usr/bin/env python | |
| 2 # Copyright (c) 2012 The Chromium Authors. All rights reserved. | |
| 3 # Use of this source code is governed by a BSD-style license that can be | |
| 4 # found in the LICENSE file. | |
| 5 | |
| 6 '''Stuff to prevent conflicting shortcuts. | |
| 7 ''' | |
| 8 | |
| 9 from grit import lazy_re | |
| 10 | |
| 11 | |
| 12 class ShortcutGroup(object): | |
| 13 '''Manages a list of cliques that belong together in a single shortcut | |
| 14 group. Knows how to detect conflicting shortcut keys. | |
| 15 ''' | |
| 16 | |
| 17 # Matches shortcut keys, e.g. &J | |
| 18 SHORTCUT_RE = lazy_re.compile('([^&]|^)(&[A-Za-z])') | |
| 19 | |
| 20 def __init__(self, name): | |
| 21 self.name = name | |
| 22 # Map of language codes to shortcut keys used (which is a map of | |
| 23 # shortcut keys to counts). | |
| 24 self.keys_by_lang = {} | |
| 25 # List of cliques in this group | |
| 26 self.cliques = [] | |
| 27 | |
| 28 def AddClique(self, c): | |
| 29 for existing_clique in self.cliques: | |
| 30 if existing_clique.GetId() == c.GetId(): | |
| 31 # This happens e.g. when we have e.g. | |
| 32 # <if expr1><structure 1></if> <if expr2><structure 2></if> | |
| 33 # where only one will really be included in the output. | |
| 34 return | |
| 35 | |
| 36 self.cliques.append(c) | |
| 37 for (lang, msg) in c.clique.items(): | |
| 38 if lang not in self.keys_by_lang: | |
| 39 self.keys_by_lang[lang] = {} | |
| 40 keymap = self.keys_by_lang[lang] | |
| 41 | |
| 42 content = msg.GetRealContent() | |
| 43 keys = [groups[1] for groups in self.SHORTCUT_RE.findall(content)] | |
| 44 for key in keys: | |
| 45 key = key.upper() | |
| 46 if key in keymap: | |
| 47 keymap[key] += 1 | |
| 48 else: | |
| 49 keymap[key] = 1 | |
| 50 | |
| 51 def GenerateWarnings(self, tc_project): | |
| 52 # For any language that has more than one occurrence of any shortcut, | |
| 53 # make a list of the conflicting shortcuts. | |
| 54 problem_langs = {} | |
| 55 for (lang, keys) in self.keys_by_lang.items(): | |
| 56 for (key, count) in keys.items(): | |
| 57 if count > 1: | |
| 58 if lang not in problem_langs: | |
| 59 problem_langs[lang] = [] | |
| 60 problem_langs[lang].append(key) | |
| 61 | |
| 62 warnings = [] | |
| 63 if len(problem_langs): | |
| 64 warnings.append("WARNING - duplicate keys exist in shortcut group %s" % | |
| 65 self.name) | |
| 66 for (lang,keys) in problem_langs.items(): | |
| 67 warnings.append(" %6s duplicates: %s" % (lang, ', '.join(keys))) | |
| 68 return warnings | |
| 69 | |
| 70 | |
| 71 def GenerateDuplicateShortcutsWarnings(uberclique, tc_project): | |
| 72 '''Given an UberClique and a project name, will print out helpful warnings | |
| 73 if there are conflicting shortcuts within shortcut groups in the provided | |
| 74 UberClique. | |
| 75 | |
| 76 Args: | |
| 77 uberclique: clique.UberClique() | |
| 78 tc_project: 'MyProjectNameInTheTranslationConsole' | |
| 79 | |
| 80 Returns: | |
| 81 ['warning line 1', 'warning line 2', ...] | |
| 82 ''' | |
| 83 warnings = [] | |
| 84 groups = {} | |
| 85 for c in uberclique.AllCliques(): | |
| 86 for group in c.shortcut_groups: | |
| 87 if group not in groups: | |
| 88 groups[group] = ShortcutGroup(group) | |
| 89 groups[group].AddClique(c) | |
| 90 for group in groups.values(): | |
| 91 warnings += group.GenerateWarnings(tc_project) | |
| 92 return warnings | |
| 93 | |
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