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1 // Copyright 2010 the V8 project authors. All rights reserved. | |
2 // Redistribution and use in source and binary forms, with or without | |
3 // modification, are permitted provided that the following conditions are | |
4 // met: | |
5 // | |
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7 // notice, this list of conditions and the following disclaimer. | |
8 // * Redistributions in binary form must reproduce the above | |
9 // copyright notice, this list of conditions and the following | |
10 // disclaimer in the documentation and/or other materials provided | |
11 // with the distribution. | |
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13 // contributors may be used to endorse or promote products derived | |
14 // from this software without specific prior written permission. | |
15 // | |
16 // THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS | |
17 // "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT | |
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26 // OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. | |
27 | |
28 #include "config.h" | |
29 | |
30 #include <math.h> | |
31 | |
32 #include "bignum-dtoa.h" | |
33 | |
34 #include "bignum.h" | |
35 #include "double.h" | |
36 | |
37 namespace WTF { | |
38 | |
39 namespace double_conversion { | |
40 | |
41 static int NormalizedExponent(uint64_t significand, int exponent) { | |
42 ASSERT(significand != 0); | |
43 while ((significand & Double::kHiddenBit) == 0) { | |
44 significand = significand << 1; | |
45 exponent = exponent - 1; | |
46 } | |
47 return exponent; | |
48 } | |
49 | |
50 | |
51 // Forward declarations: | |
52 // Returns an estimation of k such that 10^(k-1) <= v < 10^k. | |
53 static int EstimatePower(int exponent); | |
54 // Computes v / 10^estimated_power exactly, as a ratio of two bignums, numer
ator | |
55 // and denominator. | |
56 static void InitialScaledStartValues(double v, | |
57 int estimated_power, | |
58 bool need_boundary_deltas, | |
59 Bignum* numerator, | |
60 Bignum* denominator, | |
61 Bignum* delta_minus, | |
62 Bignum* delta_plus); | |
63 // Multiplies numerator/denominator so that its values lies in the range 1-1
0. | |
64 // Returns decimal_point s.t. | |
65 // v = numerator'/denominator' * 10^(decimal_point-1) | |
66 // where numerator' and denominator' are the values of numerator and | |
67 // denominator after the call to this function. | |
68 static void FixupMultiply10(int estimated_power, bool is_even, | |
69 int* decimal_point, | |
70 Bignum* numerator, Bignum* denominator, | |
71 Bignum* delta_minus, Bignum* delta_plus); | |
72 // Generates digits from the left to the right and stops when the generated | |
73 // digits yield the shortest decimal representation of v. | |
74 static void GenerateShortestDigits(Bignum* numerator, Bignum* denominator, | |
75 Bignum* delta_minus, Bignum* delta_plus, | |
76 bool is_even, | |
77 Vector<char> buffer, int* length); | |
78 // Generates 'requested_digits' after the decimal point. | |
79 static void BignumToFixed(int requested_digits, int* decimal_point, | |
80 Bignum* numerator, Bignum* denominator, | |
81 Vector<char>(buffer), int* length); | |
82 // Generates 'count' digits of numerator/denominator. | |
83 // Once 'count' digits have been produced rounds the result depending on the | |
84 // remainder (remainders of exactly .5 round upwards). Might update the | |
85 // decimal_point when rounding up (for example for 0.9999). | |
86 static void GenerateCountedDigits(int count, int* decimal_point, | |
87 Bignum* numerator, Bignum* denominator, | |
88 Vector<char>(buffer), int* length); | |
89 | |
90 | |
91 void BignumDtoa(double v, BignumDtoaMode mode, int requested_digits, | |
92 Vector<char> buffer, int* length, int* decimal_point) { | |
93 ASSERT(v > 0); | |
94 ASSERT(!Double(v).IsSpecial()); | |
95 uint64_t significand = Double(v).Significand(); | |
96 bool is_even = (significand & 1) == 0; | |
97 int exponent = Double(v).Exponent(); | |
98 int normalized_exponent = NormalizedExponent(significand, exponent); | |
99 // estimated_power might be too low by 1. | |
100 int estimated_power = EstimatePower(normalized_exponent); | |
101 | |
102 // Shortcut for Fixed. | |
103 // The requested digits correspond to the digits after the point. If the | |
104 // number is much too small, then there is no need in trying to get any | |
105 // digits. | |
106 if (mode == BIGNUM_DTOA_FIXED && -estimated_power - 1 > requested_digits
) { | |
107 buffer[0] = '\0'; | |
108 *length = 0; | |
109 // Set decimal-point to -requested_digits. This is what Gay does. | |
110 // Note that it should not have any effect anyways since the string
is | |
111 // empty. | |
112 *decimal_point = -requested_digits; | |
113 return; | |
114 } | |
115 | |
116 Bignum numerator; | |
117 Bignum denominator; | |
118 Bignum delta_minus; | |
119 Bignum delta_plus; | |
120 // Make sure the bignum can grow large enough. The smallest double equal
s | |
121 // 4e-324. In this case the denominator needs fewer than 324*4 binary di
gits. | |
122 // The maximum double is 1.7976931348623157e308 which needs fewer than | |
123 // 308*4 binary digits. | |
124 ASSERT(Bignum::kMaxSignificantBits >= 324*4); | |
125 bool need_boundary_deltas = (mode == BIGNUM_DTOA_SHORTEST); | |
126 InitialScaledStartValues(v, estimated_power, need_boundary_deltas, | |
127 &numerator, &denominator, | |
128 &delta_minus, &delta_plus); | |
129 // We now have v = (numerator / denominator) * 10^estimated_power. | |
130 FixupMultiply10(estimated_power, is_even, decimal_point, | |
131 &numerator, &denominator, | |
132 &delta_minus, &delta_plus); | |
133 // We now have v = (numerator / denominator) * 10^(decimal_point-1), and | |
134 // 1 <= (numerator + delta_plus) / denominator < 10 | |
135 switch (mode) { | |
136 case BIGNUM_DTOA_SHORTEST: | |
137 GenerateShortestDigits(&numerator, &denominator, | |
138 &delta_minus, &delta_plus, | |
139 is_even, buffer, length); | |
140 break; | |
141 case BIGNUM_DTOA_FIXED: | |
142 BignumToFixed(requested_digits, decimal_point, | |
143 &numerator, &denominator, | |
144 buffer, length); | |
145 break; | |
146 case BIGNUM_DTOA_PRECISION: | |
147 GenerateCountedDigits(requested_digits, decimal_point, | |
148 &numerator, &denominator, | |
149 buffer, length); | |
150 break; | |
151 default: | |
152 UNREACHABLE(); | |
153 } | |
154 buffer[*length] = '\0'; | |
155 } | |
156 | |
157 | |
158 // The procedure starts generating digits from the left to the right and sto
ps | |
159 // when the generated digits yield the shortest decimal representation of v.
A | |
160 // decimal representation of v is a number lying closer to v than to any oth
er | |
161 // double, so it converts to v when read. | |
162 // | |
163 // This is true if d, the decimal representation, is between m- and m+, the | |
164 // upper and lower boundaries. d must be strictly between them if !is_even. | |
165 // m- := (numerator - delta_minus) / denominator | |
166 // m+ := (numerator + delta_plus) / denominator | |
167 // | |
168 // Precondition: 0 <= (numerator+delta_plus) / denominator < 10. | |
169 // If 1 <= (numerator+delta_plus) / denominator < 10 then no leading 0 dig
it | |
170 // will be produced. This should be the standard precondition. | |
171 static void GenerateShortestDigits(Bignum* numerator, Bignum* denominator, | |
172 Bignum* delta_minus, Bignum* delta_plus, | |
173 bool is_even, | |
174 Vector<char> buffer, int* length) { | |
175 // Small optimization: if delta_minus and delta_plus are the same just r
euse | |
176 // one of the two bignums. | |
177 if (Bignum::Equal(*delta_minus, *delta_plus)) { | |
178 delta_plus = delta_minus; | |
179 } | |
180 *length = 0; | |
181 while (true) { | |
182 uint16_t digit; | |
183 digit = numerator->DivideModuloIntBignum(*denominator); | |
184 ASSERT(digit <= 9); // digit is a uint16_t and therefore always pos
itive. | |
185 // digit = numerator / denominator (integer division). | |
186 // numerator = numerator % denominator. | |
187 buffer[(*length)++] = digit + '0'; | |
188 | |
189 // Can we stop already? | |
190 // If the remainder of the division is less than the distance to the
lower | |
191 // boundary we can stop. In this case we simply round down (discardi
ng the | |
192 // remainder). | |
193 // Similarly we test if we can round up (using the upper boundary). | |
194 bool in_delta_room_minus; | |
195 bool in_delta_room_plus; | |
196 if (is_even) { | |
197 in_delta_room_minus = Bignum::LessEqual(*numerator, *delta_minus
); | |
198 } else { | |
199 in_delta_room_minus = Bignum::Less(*numerator, *delta_minus); | |
200 } | |
201 if (is_even) { | |
202 in_delta_room_plus = | |
203 Bignum::PlusCompare(*numerator, *delta_plus, *denominator) >= 0; | |
204 } else { | |
205 in_delta_room_plus = | |
206 Bignum::PlusCompare(*numerator, *delta_plus, *denominator) > 0; | |
207 } | |
208 if (!in_delta_room_minus && !in_delta_room_plus) { | |
209 // Prepare for next iteration. | |
210 numerator->Times10(); | |
211 delta_minus->Times10(); | |
212 // We optimized delta_plus to be equal to delta_minus (if they s
hare the | |
213 // same value). So don't multiply delta_plus if they point to th
e same | |
214 // object. | |
215 if (delta_minus != delta_plus) { | |
216 delta_plus->Times10(); | |
217 } | |
218 } else if (in_delta_room_minus && in_delta_room_plus) { | |
219 // Let's see if 2*numerator < denominator. | |
220 // If yes, then the next digit would be < 5 and we can round dow
n. | |
221 int compare = Bignum::PlusCompare(*numerator, *numerator, *denom
inator); | |
222 if (compare < 0) { | |
223 // Remaining digits are less than .5. -> Round down (== do n
othing). | |
224 } else if (compare > 0) { | |
225 // Remaining digits are more than .5 of denominator. -> Roun
d up. | |
226 // Note that the last digit could not be a '9' as otherwise
the whole | |
227 // loop would have stopped earlier. | |
228 // We still have an assert here in case the preconditions we
re not | |
229 // satisfied. | |
230 ASSERT(buffer[(*length) - 1] != '9'); | |
231 buffer[(*length) - 1]++; | |
232 } else { | |
233 // Halfway case. | |
234 // TODO(floitsch): need a way to solve half-way cases. | |
235 // For now let's round towards even (since this is what Ga
y seems to | |
236 // do). | |
237 | |
238 if ((buffer[(*length) - 1] - '0') % 2 == 0) { | |
239 // Round down => Do nothing. | |
240 } else { | |
241 ASSERT(buffer[(*length) - 1] != '9'); | |
242 buffer[(*length) - 1]++; | |
243 } | |
244 } | |
245 return; | |
246 } else if (in_delta_room_minus) { | |
247 // Round down (== do nothing). | |
248 return; | |
249 } else { // in_delta_room_plus | |
250 // Round up. | |
251 // Note again that the last digit could not be '9' since this wo
uld have | |
252 // stopped the loop earlier. | |
253 // We still have an ASSERT here, in case the preconditions were
not | |
254 // satisfied. | |
255 ASSERT(buffer[(*length) -1] != '9'); | |
256 buffer[(*length) - 1]++; | |
257 return; | |
258 } | |
259 } | |
260 } | |
261 | |
262 | |
263 // Let v = numerator / denominator < 10. | |
264 // Then we generate 'count' digits of d = x.xxxxx... (without the decimal po
int) | |
265 // from left to right. Once 'count' digits have been produced we decide weth
er | |
266 // to round up or down. Remainders of exactly .5 round upwards. Numbers such | |
267 // as 9.999999 propagate a carry all the way, and change the | |
268 // exponent (decimal_point), when rounding upwards. | |
269 static void GenerateCountedDigits(int count, int* decimal_point, | |
270 Bignum* numerator, Bignum* denominator, | |
271 Vector<char>(buffer), int* length) { | |
272 ASSERT(count >= 0); | |
273 for (int i = 0; i < count - 1; ++i) { | |
274 uint16_t digit; | |
275 digit = numerator->DivideModuloIntBignum(*denominator); | |
276 ASSERT(digit <= 9); // digit is a uint16_t and therefore always pos
itive. | |
277 // digit = numerator / denominator (integer division). | |
278 // numerator = numerator % denominator. | |
279 buffer[i] = digit + '0'; | |
280 // Prepare for next iteration. | |
281 numerator->Times10(); | |
282 } | |
283 // Generate the last digit. | |
284 uint16_t digit; | |
285 digit = numerator->DivideModuloIntBignum(*denominator); | |
286 if (Bignum::PlusCompare(*numerator, *numerator, *denominator) >= 0) { | |
287 digit++; | |
288 } | |
289 buffer[count - 1] = digit + '0'; | |
290 // Correct bad digits (in case we had a sequence of '9's). Propagate the | |
291 // carry until we hat a non-'9' or til we reach the first digit. | |
292 for (int i = count - 1; i > 0; --i) { | |
293 if (buffer[i] != '0' + 10) break; | |
294 buffer[i] = '0'; | |
295 buffer[i - 1]++; | |
296 } | |
297 if (buffer[0] == '0' + 10) { | |
298 // Propagate a carry past the top place. | |
299 buffer[0] = '1'; | |
300 (*decimal_point)++; | |
301 } | |
302 *length = count; | |
303 } | |
304 | |
305 | |
306 // Generates 'requested_digits' after the decimal point. It might omit | |
307 // trailing '0's. If the input number is too small then no digits at all are | |
308 // generated (ex.: 2 fixed digits for 0.00001). | |
309 // | |
310 // Input verifies: 1 <= (numerator + delta) / denominator < 10. | |
311 static void BignumToFixed(int requested_digits, int* decimal_point, | |
312 Bignum* numerator, Bignum* denominator, | |
313 Vector<char>(buffer), int* length) { | |
314 // Note that we have to look at more than just the requested_digits, sin
ce | |
315 // a number could be rounded up. Example: v=0.5 with requested_digits=0. | |
316 // Even though the power of v equals 0 we can't just stop here. | |
317 if (-(*decimal_point) > requested_digits) { | |
318 // The number is definitively too small. | |
319 // Ex: 0.001 with requested_digits == 1. | |
320 // Set decimal-point to -requested_digits. This is what Gay does. | |
321 // Note that it should not have any effect anyways since the string
is | |
322 // empty. | |
323 *decimal_point = -requested_digits; | |
324 *length = 0; | |
325 return; | |
326 } else if (-(*decimal_point) == requested_digits) { | |
327 // We only need to verify if the number rounds down or up. | |
328 // Ex: 0.04 and 0.06 with requested_digits == 1. | |
329 ASSERT(*decimal_point == -requested_digits); | |
330 // Initially the fraction lies in range (1, 10]. Multiply the denomi
nator | |
331 // by 10 so that we can compare more easily. | |
332 denominator->Times10(); | |
333 if (Bignum::PlusCompare(*numerator, *numerator, *denominator) >= 0)
{ | |
334 // If the fraction is >= 0.5 then we have to include the rounded | |
335 // digit. | |
336 buffer[0] = '1'; | |
337 *length = 1; | |
338 (*decimal_point)++; | |
339 } else { | |
340 // Note that we caught most of similar cases earlier. | |
341 *length = 0; | |
342 } | |
343 return; | |
344 } else { | |
345 // The requested digits correspond to the digits after the point. | |
346 // The variable 'needed_digits' includes the digits before the point
. | |
347 int needed_digits = (*decimal_point) + requested_digits; | |
348 GenerateCountedDigits(needed_digits, decimal_point, | |
349 numerator, denominator, | |
350 buffer, length); | |
351 } | |
352 } | |
353 | |
354 | |
355 // Returns an estimation of k such that 10^(k-1) <= v < 10^k where | |
356 // v = f * 2^exponent and 2^52 <= f < 2^53. | |
357 // v is hence a normalized double with the given exponent. The output is an | |
358 // approximation for the exponent of the decimal approimation .digits * 10^k
. | |
359 // | |
360 // The result might undershoot by 1 in which case 10^k <= v < 10^k+1. | |
361 // Note: this property holds for v's upper boundary m+ too. | |
362 // 10^k <= m+ < 10^k+1. | |
363 // (see explanation below). | |
364 // | |
365 // Examples: | |
366 // EstimatePower(0) => 16 | |
367 // EstimatePower(-52) => 0 | |
368 // | |
369 // Note: e >= 0 => EstimatedPower(e) > 0. No similar claim can be made for e
<0. | |
370 static int EstimatePower(int exponent) { | |
371 // This function estimates log10 of v where v = f*2^e (with e == exponen
t). | |
372 // Note that 10^floor(log10(v)) <= v, but v <= 10^ceil(log10(v)). | |
373 // Note that f is bounded by its container size. Let p = 53 (the double'
s | |
374 // significand size). Then 2^(p-1) <= f < 2^p. | |
375 // | |
376 // Given that log10(v) == log2(v)/log2(10) and e+(len(f)-1) is quite clo
se | |
377 // to log2(v) the function is simplified to (e+(len(f)-1)/log2(10)). | |
378 // The computed number undershoots by less than 0.631 (when we compute l
og3 | |
379 // and not log10). | |
380 // | |
381 // Optimization: since we only need an approximated result this computat
ion | |
382 // can be performed on 64 bit integers. On x86/x64 architecture the spee
dup is | |
383 // not really measurable, though. | |
384 // | |
385 // Since we want to avoid overshooting we decrement by 1e10 so that | |
386 // floating-point imprecisions don't affect us. | |
387 // | |
388 // Explanation for v's boundary m+: the computation takes advantage of | |
389 // the fact that 2^(p-1) <= f < 2^p. Boundaries still satisfy this requi
rement | |
390 // (even for denormals where the delta can be much more important). | |
391 | |
392 const double k1Log10 = 0.30102999566398114; // 1/lg(10) | |
393 | |
394 // For doubles len(f) == 53 (don't forget the hidden bit). | |
395 const int kSignificandSize = 53; | |
396 double estimate = ceil((exponent + kSignificandSize - 1) * k1Log10 - 1e-
10); | |
397 return static_cast<int>(estimate); | |
398 } | |
399 | |
400 | |
401 // See comments for InitialScaledStartValues. | |
402 static void InitialScaledStartValuesPositiveExponent( | |
403 double v, int estimated
_power, bool need_boundary_deltas, | |
404 Bignum* numerator, Bign
um* denominator, | |
405 Bignum* delta_minus, Bi
gnum* delta_plus) { | |
406 // A positive exponent implies a positive power. | |
407 ASSERT(estimated_power >= 0); | |
408 // Since the estimated_power is positive we simply multiply the denomina
tor | |
409 // by 10^estimated_power. | |
410 | |
411 // numerator = v. | |
412 numerator->AssignUInt64(Double(v).Significand()); | |
413 numerator->ShiftLeft(Double(v).Exponent()); | |
414 // denominator = 10^estimated_power. | |
415 denominator->AssignPowerUInt16(10, estimated_power); | |
416 | |
417 if (need_boundary_deltas) { | |
418 // Introduce a common denominator so that the deltas to the boundari
es are | |
419 // integers. | |
420 denominator->ShiftLeft(1); | |
421 numerator->ShiftLeft(1); | |
422 // Let v = f * 2^e, then m+ - v = 1/2 * 2^e; With the common | |
423 // denominator (of 2) delta_plus equals 2^e. | |
424 delta_plus->AssignUInt16(1); | |
425 delta_plus->ShiftLeft(Double(v).Exponent()); | |
426 // Same for delta_minus (with adjustments below if f == 2^p-1). | |
427 delta_minus->AssignUInt16(1); | |
428 delta_minus->ShiftLeft(Double(v).Exponent()); | |
429 | |
430 // If the significand (without the hidden bit) is 0, then the lower | |
431 // boundary is closer than just half a ulp (unit in the last place). | |
432 // There is only one exception: if the next lower number is a denorm
al then | |
433 // the distance is 1 ulp. This cannot be the case for exponent >= 0
(but we | |
434 // have to test it in the other function where exponent < 0). | |
435 uint64_t v_bits = Double(v).AsUint64(); | |
436 if ((v_bits & Double::kSignificandMask) == 0) { | |
437 // The lower boundary is closer at half the distance of "normal"
numbers. | |
438 // Increase the common denominator and adapt all but the delta_m
inus. | |
439 denominator->ShiftLeft(1); // *2 | |
440 numerator->ShiftLeft(1); // *2 | |
441 delta_plus->ShiftLeft(1); // *2 | |
442 } | |
443 } | |
444 } | |
445 | |
446 | |
447 // See comments for InitialScaledStartValues | |
448 static void InitialScaledStartValuesNegativeExponentPositivePower( | |
449 double v,
int estimated_power, bool need_boundary_deltas, | |
450 Bignum* nu
merator, Bignum* denominator, | |
451 Bignum* de
lta_minus, Bignum* delta_plus) { | |
452 uint64_t significand = Double(v).Significand(); | |
453 int exponent = Double(v).Exponent(); | |
454 // v = f * 2^e with e < 0, and with estimated_power >= 0. | |
455 // This means that e is close to 0 (have a look at how estimated_power i
s | |
456 // computed). | |
457 | |
458 // numerator = significand | |
459 // since v = significand * 2^exponent this is equivalent to | |
460 // numerator = v * / 2^-exponent | |
461 numerator->AssignUInt64(significand); | |
462 // denominator = 10^estimated_power * 2^-exponent (with exponent < 0) | |
463 denominator->AssignPowerUInt16(10, estimated_power); | |
464 denominator->ShiftLeft(-exponent); | |
465 | |
466 if (need_boundary_deltas) { | |
467 // Introduce a common denominator so that the deltas to the boundari
es are | |
468 // integers. | |
469 denominator->ShiftLeft(1); | |
470 numerator->ShiftLeft(1); | |
471 // Let v = f * 2^e, then m+ - v = 1/2 * 2^e; With the common | |
472 // denominator (of 2) delta_plus equals 2^e. | |
473 // Given that the denominator already includes v's exponent the dist
ance | |
474 // to the boundaries is simply 1. | |
475 delta_plus->AssignUInt16(1); | |
476 // Same for delta_minus (with adjustments below if f == 2^p-1). | |
477 delta_minus->AssignUInt16(1); | |
478 | |
479 // If the significand (without the hidden bit) is 0, then the lower | |
480 // boundary is closer than just one ulp (unit in the last place). | |
481 // There is only one exception: if the next lower number is a denorm
al | |
482 // then the distance is 1 ulp. Since the exponent is close to zero | |
483 // (otherwise estimated_power would have been negative) this cannot
happen | |
484 // here either. | |
485 uint64_t v_bits = Double(v).AsUint64(); | |
486 if ((v_bits & Double::kSignificandMask) == 0) { | |
487 // The lower boundary is closer at half the distance of "normal"
numbers. | |
488 // Increase the denominator and adapt all but the delta_minus. | |
489 denominator->ShiftLeft(1); // *2 | |
490 numerator->ShiftLeft(1); // *2 | |
491 delta_plus->ShiftLeft(1); // *2 | |
492 } | |
493 } | |
494 } | |
495 | |
496 | |
497 // See comments for InitialScaledStartValues | |
498 static void InitialScaledStartValuesNegativeExponentNegativePower( | |
499 double v,
int estimated_power, bool need_boundary_deltas, | |
500 Bignum* nu
merator, Bignum* denominator, | |
501 Bignum* de
lta_minus, Bignum* delta_plus) { | |
502 const uint64_t kMinimalNormalizedExponent = | |
503 UINT64_2PART_C(0x00100000, 00000000); | |
504 uint64_t significand = Double(v).Significand(); | |
505 int exponent = Double(v).Exponent(); | |
506 // Instead of multiplying the denominator with 10^estimated_power we | |
507 // multiply all values (numerator and deltas) by 10^-estimated_power. | |
508 | |
509 // Use numerator as temporary container for power_ten. | |
510 Bignum* power_ten = numerator; | |
511 power_ten->AssignPowerUInt16(10, -estimated_power); | |
512 | |
513 if (need_boundary_deltas) { | |
514 // Since power_ten == numerator we must make a copy of 10^estimated_
power | |
515 // before we complete the computation of the numerator. | |
516 // delta_plus = delta_minus = 10^estimated_power | |
517 delta_plus->AssignBignum(*power_ten); | |
518 delta_minus->AssignBignum(*power_ten); | |
519 } | |
520 | |
521 // numerator = significand * 2 * 10^-estimated_power | |
522 // since v = significand * 2^exponent this is equivalent to | |
523 // numerator = v * 10^-estimated_power * 2 * 2^-exponent. | |
524 // Remember: numerator has been abused as power_ten. So no need to assig
n it | |
525 // to itself. | |
526 ASSERT(numerator == power_ten); | |
527 numerator->MultiplyByUInt64(significand); | |
528 | |
529 // denominator = 2 * 2^-exponent with exponent < 0. | |
530 denominator->AssignUInt16(1); | |
531 denominator->ShiftLeft(-exponent); | |
532 | |
533 if (need_boundary_deltas) { | |
534 // Introduce a common denominator so that the deltas to the boundari
es are | |
535 // integers. | |
536 numerator->ShiftLeft(1); | |
537 denominator->ShiftLeft(1); | |
538 // With this shift the boundaries have their correct value, since | |
539 // delta_plus = 10^-estimated_power, and | |
540 // delta_minus = 10^-estimated_power. | |
541 // These assignments have been done earlier. | |
542 | |
543 // The special case where the lower boundary is twice as close. | |
544 // This time we have to look out for the exception too. | |
545 uint64_t v_bits = Double(v).AsUint64(); | |
546 if ((v_bits & Double::kSignificandMask) == 0 && | |
547 // The only exception where a significand == 0 has its boundarie
s at | |
548 // "normal" distances: | |
549 (v_bits & Double::kExponentMask) != kMinimalNormalizedExponent)
{ | |
550 numerator->ShiftLeft(1); // *2 | |
551 denominator->ShiftLeft(1); // *2 | |
552 delta_plus->ShiftLeft(1); // *2 | |
553 } | |
554 } | |
555 } | |
556 | |
557 | |
558 // Let v = significand * 2^exponent. | |
559 // Computes v / 10^estimated_power exactly, as a ratio of two bignums, numer
ator | |
560 // and denominator. The functions GenerateShortestDigits and | |
561 // GenerateCountedDigits will then convert this ratio to its decimal | |
562 // representation d, with the required accuracy. | |
563 // Then d * 10^estimated_power is the representation of v. | |
564 // (Note: the fraction and the estimated_power might get adjusted before | |
565 // generating the decimal representation.) | |
566 // | |
567 // The initial start values consist of: | |
568 // - a scaled numerator: s.t. numerator/denominator == v / 10^estimated_pow
er. | |
569 // - a scaled (common) denominator. | |
570 // optionally (used by GenerateShortestDigits to decide if it has the short
est | |
571 // decimal converting back to v): | |
572 // - v - m-: the distance to the lower boundary. | |
573 // - m+ - v: the distance to the upper boundary. | |
574 // | |
575 // v, m+, m-, and therefore v - m- and m+ - v all share the same denominator
. | |
576 // | |
577 // Let ep == estimated_power, then the returned values will satisfy: | |
578 // v / 10^ep = numerator / denominator. | |
579 // v's boundarys m- and m+: | |
580 // m- / 10^ep == v / 10^ep - delta_minus / denominator | |
581 // m+ / 10^ep == v / 10^ep + delta_plus / denominator | |
582 // Or in other words: | |
583 // m- == v - delta_minus * 10^ep / denominator; | |
584 // m+ == v + delta_plus * 10^ep / denominator; | |
585 // | |
586 // Since 10^(k-1) <= v < 10^k (with k == estimated_power) | |
587 // or 10^k <= v < 10^(k+1) | |
588 // we then have 0.1 <= numerator/denominator < 1 | |
589 // or 1 <= numerator/denominator < 10 | |
590 // | |
591 // It is then easy to kickstart the digit-generation routine. | |
592 // | |
593 // The boundary-deltas are only filled if need_boundary_deltas is set. | |
594 static void InitialScaledStartValues(double v, | |
595 int estimated_power, | |
596 bool need_boundary_deltas, | |
597 Bignum* numerator, | |
598 Bignum* denominator, | |
599 Bignum* delta_minus, | |
600 Bignum* delta_plus) { | |
601 if (Double(v).Exponent() >= 0) { | |
602 InitialScaledStartValuesPositiveExponent( | |
603 v, estimated_power, need_bo
undary_deltas, | |
604 numerator, denominator, del
ta_minus, delta_plus); | |
605 } else if (estimated_power >= 0) { | |
606 InitialScaledStartValuesNegativeExponentPositivePower( | |
607 v, estimated_p
ower, need_boundary_deltas, | |
608 numerator, den
ominator, delta_minus, delta_plus); | |
609 } else { | |
610 InitialScaledStartValuesNegativeExponentNegativePower( | |
611 v, estimated_p
ower, need_boundary_deltas, | |
612 numerator, den
ominator, delta_minus, delta_plus); | |
613 } | |
614 } | |
615 | |
616 | |
617 // This routine multiplies numerator/denominator so that its values lies in
the | |
618 // range 1-10. That is after a call to this function we have: | |
619 // 1 <= (numerator + delta_plus) /denominator < 10. | |
620 // Let numerator the input before modification and numerator' the argument | |
621 // after modification, then the output-parameter decimal_point is such that | |
622 // numerator / denominator * 10^estimated_power == | |
623 // numerator' / denominator' * 10^(decimal_point - 1) | |
624 // In some cases estimated_power was too low, and this is already the case.
We | |
625 // then simply adjust the power so that 10^(k-1) <= v < 10^k (with k == | |
626 // estimated_power) but do not touch the numerator or denominator. | |
627 // Otherwise the routine multiplies the numerator and the deltas by 10. | |
628 static void FixupMultiply10(int estimated_power, bool is_even, | |
629 int* decimal_point, | |
630 Bignum* numerator, Bignum* denominator, | |
631 Bignum* delta_minus, Bignum* delta_plus) { | |
632 bool in_range; | |
633 if (is_even) { | |
634 // For IEEE doubles half-way cases (in decimal system numbers ending
with 5) | |
635 // are rounded to the closest floating-point number with even signif
icand. | |
636 in_range = Bignum::PlusCompare(*numerator, *delta_plus, *denominator
) >= 0; | |
637 } else { | |
638 in_range = Bignum::PlusCompare(*numerator, *delta_plus, *denominator
) > 0; | |
639 } | |
640 if (in_range) { | |
641 // Since numerator + delta_plus >= denominator we already have | |
642 // 1 <= numerator/denominator < 10. Simply update the estimated_powe
r. | |
643 *decimal_point = estimated_power + 1; | |
644 } else { | |
645 *decimal_point = estimated_power; | |
646 numerator->Times10(); | |
647 if (Bignum::Equal(*delta_minus, *delta_plus)) { | |
648 delta_minus->Times10(); | |
649 delta_plus->AssignBignum(*delta_minus); | |
650 } else { | |
651 delta_minus->Times10(); | |
652 delta_plus->Times10(); | |
653 } | |
654 } | |
655 } | |
656 | |
657 } // namespace double_conversion | |
658 | |
659 } // namespace WTF | |
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