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Side by Side Diff: src/gpu/gl/GrGLFragmentProcessor.cpp

Issue 1298233002: Added fNumTransformsExclChildren and fNumTexturesExclChildren; changed emitChild() to forward search (Closed) Base URL: https://skia.googlesource.com/skia@cs3_emitchild
Patch Set: Created 5 years, 4 months ago
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1 /* 1 /*
2 * Copyright 2015 Google Inc. 2 * Copyright 2015 Google Inc.
3 * 3 *
4 * Use of this source code is governed by a BSD-style license that can be 4 * Use of this source code is governed by a BSD-style license that can be
5 * found in the LICENSE file. 5 * found in the LICENSE file.
6 */ 6 */
7 7
8 #include "GrGLFragmentProcessor.h" 8 #include "GrGLFragmentProcessor.h"
9 #include "GrFragmentProcessor.h" 9 #include "GrFragmentProcessor.h"
10 #include "builders/GrGLFragmentShaderBuilder.h" 10 #include "builders/GrGLFragmentShaderBuilder.h"
(...skipping 14 matching lines...) Expand all
25 fb->onBeforeChildProcEmitCode(); // call first so mangleString is updated 25 fb->onBeforeChildProcEmitCode(); // call first so mangleString is updated
26 26
27 const GrFragmentProcessor& childProc = args.fFp.childProcessor(childIndex); 27 const GrFragmentProcessor& childProc = args.fFp.childProcessor(childIndex);
28 28
29 // Mangle the name of the outputColor 29 // Mangle the name of the outputColor
30 outputColor->set(args.fOutputColor); 30 outputColor->set(args.fOutputColor);
31 outputColor->append(fb->getMangleStringThisLevel()); 31 outputColor->append(fb->getMangleStringThisLevel());
32 32
33 /* 33 /*
34 * We now want to find the subset of coords and samplers that belong to the child and its 34 * We now want to find the subset of coords and samplers that belong to the child and its
35 * descendants and put that into childCoords and childSamplers. To do so, we must do a 35 * descendants and put that into childCoords and childSamplers. To do so, we 'll do a forwards
36 * backwards linear search on coords and samplers. 36 * linear search.
37 * 37 *
38 * Explanation: 38 * Explanation:
39 * Each GrFragmentProcessor has a copy of all the transforms and textures of itself and 39 * Each GrFragmentProcessor has a copy of all the transforms and textures of itself and
40 * all procs in its subtree. For example, suppose we have frag proc A, who h as two children B 40 * all procs in its subtree. For example, suppose we have frag proc A, who h as two children B
41 * and D. B has a child C, and D has two children E and F. Each frag proc's transforms array 41 * and D. B has a child C, and D has two children E and F. Each frag proc's transforms array
42 * contains its own transforms, followed by the transforms of all its descen dants (i.e. preorder 42 * contains its own transforms, followed by the transforms of all its descen dants (i.e. preorder
43 * traversal). Suppose procs A, B, C, D, E, F have 1, 2, 1, 1, 3, 2 transfor ms respectively. 43 * traversal). Suppose procs A, B, C, D, E, F have 1, 2, 1, 1, 3, 2 transfor ms respectively.
44 * 44 *
45 * (A) 45 * (A)
46 * [a1,b1,b2,c1,d1,e1,e2,e3,f1,f2] 46 * [a1,b1,b2,c1,d1,e1,e2,e3,f1,f2]
47 * / \ 47 * / \
48 * / \ 48 * / \
49 * (B) (D) 49 * (B) (D)
50 * [b1,b2,c1] [d1,e1,e2,e3,f1,f2] 50 * [b1,b2,c1] [d1,e1,e2,e3,f1,f2]
51 * / / \ 51 * / / \
52 * / / \ 52 * / / \
53 * (C) (E) (F) 53 * (C) (E) (F)
54 * [c1] [e1,e2,e3] [f1,f2] 54 * [c1] [e1,e2,e3] [f1,f2]
55 * 55 *
56 * So if we're inside proc A's emitCode, and A is about to call emitCode on proc B, we want the 56 * So if we're inside proc A's emitCode, and A is about to call emitCode on proc D, we want the
57 * EmitArgs that's passed onto B to only contain its and its descendants' co ords. The 57 * EmitArgs that's passed onto D to only contain its and its descendants' co ords. The
58 * EmitArgs given to A would contain the transforms [a1,b1,b2,c1,d1,e1,e2,e3 ,f1,f2], and we want 58 * EmitArgs given to A would contain the transforms [a1,b1,b2,c1,d1,e1,e2,e3 ,f1,f2], and we want
59 * to extract the subset [b1,b2,c1] to pass on to B. We can do this with a b ackwards linear 59 * to extract the subset [d1,e1,e2,e3,f1,f2] to pass on to D. We can do this with a linear
60 * search since we know that D's subtree has 6 transforms and B's subtree ha s 3 transforms (by 60 * search since we know that A has 1 transform (using A.numTransformsExclChi ldren()), and B's
61 * calling D.numTextures() and B.numTextures()), so we know the start of B's transforms is 9 61 * subtree has 3 transforms (using B.numTransforms()), so we know the start of D's transforms is
62 * from the end of A's transforms. We cannot do this with a forwards linear search since we 62 * 4 after the start of A's transforms.
63 * don't know how many transforms belong to A (A.numTextures() will return 1 0, not 1), so
64 * we wouldn't know how many transforms to initially skip in A's array if us ing a forward linear
65 * search.
66 * Textures work the same way as transforms. 63 * Textures work the same way as transforms.
67 */ 64 */
68 int firstCoordAt = args.fFp.numTransforms(); 65 int firstCoordAt = args.fFp.numTransformsExclChildren();
69 int firstSamplerAt = args.fFp.numTextures(); 66 int firstSamplerAt = args.fFp.numTexturesExclChildren();
70 for (int i = args.fFp.numChildProcessors() - 1; i >= childIndex; --i) { 67 for (int i = 0; i < childIndex; ++i) {
71 firstCoordAt -= args.fFp.childProcessor(i).numTransforms(); 68 firstCoordAt += args.fFp.childProcessor(i).numTransforms();
72 firstSamplerAt -= args.fFp.childProcessor(i).numTextures(); 69 firstSamplerAt += args.fFp.childProcessor(i).numTextures();
73 } 70 }
74 TransformedCoordsArray childCoords; 71 TransformedCoordsArray childCoords;
75 TextureSamplerArray childSamplers; 72 TextureSamplerArray childSamplers;
76 if (childProc.numTransforms() > 0) { 73 if (childProc.numTransforms() > 0) {
77 childCoords.push_back_n(childProc.numTransforms(), &args.fCoords[firstCo ordAt]); 74 childCoords.push_back_n(childProc.numTransforms(), &args.fCoords[firstCo ordAt]);
78 } 75 }
79 if (childProc.numTextures() > 0) { 76 if (childProc.numTextures() > 0) {
80 childSamplers.push_back_n(childProc.numTextures(), &args.fSamplers[first SamplerAt]); 77 childSamplers.push_back_n(childProc.numTextures(), &args.fSamplers[first SamplerAt]);
81 } 78 }
82 79
83 // emit the code for the child in its own scope 80 // emit the code for the child in its own scope
84 fb->codeAppendf("vec4 %s;\n", outputColor->c_str()); 81 fb->codeAppendf("vec4 %s;\n", outputColor->c_str());
85 fb->codeAppend("{\n"); 82 fb->codeAppend("{\n");
86 fb->codeAppendf("// Child Index %d (mangle: %s): %s\n", childIndex, 83 fb->codeAppendf("// Child Index %d (mangle: %s): %s\n", childIndex,
87 fb->getMangleString().c_str(), childProc.name()); 84 fb->getMangleString().c_str(), childProc.name());
88 EmitArgs childArgs(args.fBuilder, 85 EmitArgs childArgs(args.fBuilder,
89 childProc, 86 childProc,
90 outputColor->c_str(), 87 outputColor->c_str(),
91 inputColor, 88 inputColor,
92 childCoords, 89 childCoords,
93 childSamplers); 90 childSamplers);
94 this->childProcessor(childIndex)->emitCode(childArgs); 91 this->childProcessor(childIndex)->emitCode(childArgs);
95 fb->codeAppend("}\n"); 92 fb->codeAppend("}\n");
96 93
97 fb->onAfterChildProcEmitCode(); 94 fb->onAfterChildProcEmitCode();
98 } 95 }
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