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Side by Side Diff: src/pathops/SkQuarticRoot.cpp

Issue 12880016: Add intersections for path ops (Closed) Base URL: http://skia.googlecode.com/svn/trunk/
Patch Set: Created 7 years, 8 months ago
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1 // from http://tog.acm.org/resources/GraphicsGems/gems/Roots3And4.c
2 /*
3 * Roots3And4.c
4 *
5 * Utility functions to find cubic and quartic roots,
6 * coefficients are passed like this:
7 *
8 * c[0] + c[1]*x + c[2]*x^2 + c[3]*x^3 + c[4]*x^4 = 0
9 *
10 * The functions return the number of non-complex roots and
11 * put the values into the s array.
12 *
13 * Author: Jochen Schwarze (schwarze@isa.de)
14 *
15 * Jan 26, 1990 Version for Graphics Gems
16 * Oct 11, 1990 Fixed sign problem for negative q's in SolveQuartic
17 * (reported by Mark Podlipec),
18 * Old-style function definitions,
19 * IsZero() as a macro
20 * Nov 23, 1990 Some systems do not declare acos() and cbrt() in
21 * <math.h>, though the functions exist in the library.
22 * If large coefficients are used, EQN_EPS should be
23 * reduced considerably (e.g. to 1E-30), results will be
24 * correct but multiple roots might be reported more
25 * than once.
26 */
27
28 #include "SkPathOpsCubic.h"
29 #include "SkPathOpsQuad.h"
30 #include "SkQuarticRoot.h"
31
32 int SkReducedQuarticRoots(const double t4, const double t3, const double t2, con st double t1,
33 const double t0, const bool oneHint, double roots[4]) {
34 #ifdef SK_DEBUG
35 // create a string mathematica understands
36 // GDB set print repe 15 # if repeated digits is a bother
37 // set print elements 400 # if line doesn't fit
38 char str[1024];
39 bzero(str, sizeof(str));
40 snprintf(str, sizeof(str),
41 "Solve[%1.19g x^4 + %1.19g x^3 + %1.19g x^2 + %1.19g x + %1.19g == 0 , x]",
42 t4, t3, t2, t1, t0);
43 mathematica_ize(str, sizeof(str));
44 #if ONE_OFF_DEBUG && ONE_OFF_DEBUG_MATHEMATICA
45 SkDebugf("%s\n", str);
46 #endif
47 #endif
48 if (approximately_zero_when_compared_to(t4, t0) // 0 is one root
49 && approximately_zero_when_compared_to(t4, t1)
50 && approximately_zero_when_compared_to(t4, t2)) {
51 if (approximately_zero_when_compared_to(t3, t0)
52 && approximately_zero_when_compared_to(t3, t1)
53 && approximately_zero_when_compared_to(t3, t2)) {
54 return SkDQuad::RootsReal(t2, t1, t0, roots);
55 }
56 if (approximately_zero_when_compared_to(t4, t3)) {
57 return SkDCubic::RootsReal(t3, t2, t1, t0, roots);
58 }
59 }
60 if ((approximately_zero_when_compared_to(t0, t1) || approximately_zero(t1)) // 0 is one root
61 // && approximately_zero_when_compared_to(t0, t2)
62 && approximately_zero_when_compared_to(t0, t3)
63 && approximately_zero_when_compared_to(t0, t4)) {
64 int num = SkDCubic::RootsReal(t4, t3, t2, t1, roots);
65 for (int i = 0; i < num; ++i) {
66 if (approximately_zero(roots[i])) {
67 return num;
68 }
69 }
70 roots[num++] = 0;
71 return num;
72 }
73 if (oneHint) {
74 SkASSERT(approximately_zero(t4 + t3 + t2 + t1 + t0)); // 1 is one root
75 // note that -C == A + B + D + E
76 int num = SkDCubic::RootsReal(t4, t4 + t3, -(t1 + t0), -t0, roots);
77 for (int i = 0; i < num; ++i) {
78 if (approximately_equal(roots[i], 1)) {
79 return num;
80 }
81 }
82 roots[num++] = 1;
83 return num;
84 }
85 return -1;
86 }
87
88 int SkQuarticRootsReal(int firstCubicRoot, const double A, const double B, const double C,
89 const double D, const double E, double s[4]) {
90 double u, v;
91 /* normal form: x^4 + Ax^3 + Bx^2 + Cx + D = 0 */
92 const double invA = 1 / A;
93 const double a = B * invA;
94 const double b = C * invA;
95 const double c = D * invA;
96 const double d = E * invA;
97 /* substitute x = y - a/4 to eliminate cubic term:
98 x^4 + px^2 + qx + r = 0 */
99 const double a2 = a * a;
100 const double p = -3 * a2 / 8 + b;
101 const double q = a2 * a / 8 - a * b / 2 + c;
102 const double r = -3 * a2 * a2 / 256 + a2 * b / 16 - a * c / 4 + d;
103 int num;
104 if (approximately_zero(r)) {
105 /* no absolute term: y(y^3 + py + q) = 0 */
106 num = SkDCubic::RootsReal(1, 0, p, q, s);
107 s[num++] = 0;
108 } else {
109 /* solve the resolvent cubic ... */
110 double cubicRoots[3];
111 int roots = SkDCubic::RootsReal(1, -p / 2, -r, r * p / 2 - q * q / 8, cu bicRoots);
112 int index;
113 /* ... and take one real solution ... */
114 double z;
115 num = 0;
116 int num2 = 0;
117 for (index = firstCubicRoot; index < roots; ++index) {
118 z = cubicRoots[index];
119 /* ... to build two quadric equations */
120 u = z * z - r;
121 v = 2 * z - p;
122 if (approximately_zero_squared(u)) {
123 u = 0;
124 } else if (u > 0) {
125 u = sqrt(u);
126 } else {
127 continue;
128 }
129 if (approximately_zero_squared(v)) {
130 v = 0;
131 } else if (v > 0) {
132 v = sqrt(v);
133 } else {
134 continue;
135 }
136 num = SkDQuad::RootsReal(1, q < 0 ? -v : v, z - u, s);
137 num2 = SkDQuad::RootsReal(1, q < 0 ? v : -v, z + u, s + num);
138 if (!((num | num2) & 1)) {
139 break; // prefer solutions without single quad roots
140 }
141 }
142 num += num2;
143 if (!num) {
144 return 0; // no valid cubic root
145 }
146 }
147 /* resubstitute */
148 const double sub = a / 4;
149 for (int i = 0; i < num; ++i) {
150 s[i] -= sub;
151 }
152 // eliminate duplicates
153 for (int i = 0; i < num - 1; ++i) {
154 for (int j = i + 1; j < num; ) {
155 if (AlmostEqualUlps(s[i], s[j])) {
156 if (j < --num) {
157 s[j] = s[num];
158 }
159 } else {
160 ++j;
161 }
162 }
163 }
164 return num;
165 }
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