| Index: chrome/browser/chromeos/login/users/affiliation.h
|
| diff --git a/chrome/browser/chromeos/login/users/affiliation.h b/chrome/browser/chromeos/login/users/affiliation.h
|
| new file mode 100644
|
| index 0000000000000000000000000000000000000000..9d32440446c8c485fccf558b2635bc4be6506658
|
| --- /dev/null
|
| +++ b/chrome/browser/chromeos/login/users/affiliation.h
|
| @@ -0,0 +1,33 @@
|
| +// Copyright 2015 The Chromium Authors. All rights reserved.
|
| +// Use of this source code is governed by a BSD-style license that can be
|
| +// found in the LICENSE file.
|
| +
|
| +#ifndef CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_
|
| +#define CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_
|
| +
|
| +#include <set>
|
| +#include <string>
|
| +
|
| +namespace chromeos {
|
| +
|
| +typedef std::set<std::string> AffiliationIDSet;
|
| +
|
| +// Returns true if there is at least one common element in two sets.
|
| +// Complexity: O(n + m), where n - size of the first set, m - size of
|
| +// the second set.
|
| +bool HaveCommonElement(const std::set<std::string>& set1,
|
| + const std::set<std::string>& set2);
|
| +
|
| +// TODO(peletskyi): Remove email and enterprise domain after affiliation
|
| +// based implementation will fully work. http://crbug.com/515476
|
| +// The function makes a decision if user with |user_affiliation_ids| and
|
| +// |email| is affiliated on the device with |device_affiliation_ids| and
|
| +// |enterprise_domain|.
|
| +bool IsUserAffiliated(const AffiliationIDSet& user_affiliation_ids,
|
| + const AffiliationIDSet& device_affiliation_ids,
|
| + const std::string& email,
|
| + const std::string& enterprise_domain);
|
| +
|
| +} // namespace chromeos
|
| +
|
| +#endif // CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_
|
|
|