Added affiliation IDs for the new affiliation determination.

chrome/browser/chromeos/login/users/affiliation.h

Index: chrome/browser/chromeos/login/users/affiliation.h
diff --git a/chrome/browser/chromeos/login/users/affiliation.h b/chrome/browser/chromeos/login/users/affiliation.h
new file mode 100644
index 0000000000000000000000000000000000000000..61ee87994d63402402ad651991d34f771b543dad
--- /dev/null
+++ b/chrome/browser/chromeos/login/users/affiliation.h
@@ -0,0 +1,32 @@
+// Copyright 2015 The Chromium Authors. All rights reserved.
+// Use of this source code is governed by a BSD-style license that can be
+// found in the LICENSE file.
+
+#ifndef CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_
+#define CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_
+
+#include <set>
+#include <string>
+
+namespace chromeos {

[Mattias Nissler (ping if slow), 2015/07/30 17:04:17]

nit: newline

[peletskyi, 2015/07/30 17:13:34]

Done.

+typedef std::set<std::string> AffiliationIDSet;
+
+// Returns true if there is at least one common element in two sets.
+// Complexity: O(n + m), where n - size of the first set, m - size of
+// the second set.
+bool HaveCommonElement(const std::set<std::string>& set1,
+                       const std::set<std::string>& set2);
+
+// TODO(peletskyi): Remove email and enterprise domain after affiliation
+// based implementation will fully work. http://crbug.com/515476
+// The function makes a decision if user with |user_affiliation_ids| and
+// |email| is affiliated on the device with |device_affiliation_ids| and
+// |enterprise_domain|.
+bool IsUserAffiliated(const AffiliationIDSet& user_affiliation_ids,
+                      const AffiliationIDSet& device_affiliation_ids,
+                      const std::string& email,
+                      const std::string& enterprise_domain);
+
+}  // namespace chromeos
+
+#endif  // CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_