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| 1 // Copyright 2015 The Chromium Authors. All rights reserved. |
| 2 // Use of this source code is governed by a BSD-style license that can be |
| 3 // found in the LICENSE file. |
| 4 |
| 5 #ifndef CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_ |
| 6 #define CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_ |
| 7 |
| 8 #include <set> |
| 9 #include <string> |
| 10 |
| 11 namespace chromeos { |
| 12 // Returns true if there is at least one common element in two sets. |
| 13 // Complexity: O(n + m), where n - size of the first set, m - size of |
| 14 // the second set. |
| 15 bool HaveCommonElement(const std::set<std::string>& set1, |
| 16 const std::set<std::string>& set2); |
| 17 |
| 18 // TODO(peletskyi): Remove email and enterprise domain after affiliation |
| 19 // based implementation will fully work. |
| 20 // The function makes a decision if user with |user_affiliation_ids| and |
| 21 // |email| is affiliated on the device with |device_affiliation_ids| and |
| 22 // |enterprise_domain|. |
| 23 bool IsUserAffiliated(const std::set<std::string>& user_affiliation_ids, |
| 24 const std::set<std::string>& device_affiliation_ids, |
| 25 const std::string& email, |
| 26 const std::string& enterprise_domain); |
| 27 |
| 28 } // namespace chromeos |
| 29 |
| 30 #endif // CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_ |
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