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| 1 // Copyright 2015 The Chromium Authors. All rights reserved. | |
| 2 // Use of this source code is governed by a BSD-style license that can be | |
| 3 // found in the LICENSE file. | |
| 4 | |
| 5 #ifndef CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_ | |
| 6 #define CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_ | |
| 7 | |
| 8 #include <set> | |
| 9 #include <string> | |
| 10 | |
| 11 namespace chromeos { | |
| 12 // Returns true if there is at least one common element in two sets. | |
| 13 // Complexity: O(n + m), where n - size of the first set, m - size of | |
| 14 // the second set. | |
| 15 bool HaveCommonElement(const std::set<std::string>& set1, | |
| 16 const std::set<std::string>& set2); | |
| 17 | |
| 18 // TODO(peletskyi): Remove email and enterprise domain after affiliation | |
|
Mattias Nissler (ping if slow)
2015/07/30 12:10:57
nit: Please add a bug reference to the TODO
peletskyi
2015/07/30 14:10:57
Done.
| |
| 19 // based implementation will fully work. | |
| 20 // The function makes a decision if user with |user_affiliation_ids| and | |
| 21 // |email| is affiliated on the device with |device_affiliation_ids| and | |
| 22 // |enterprise_domain|. | |
| 23 bool IsUserAffiliated(const std::set<std::string>& user_affiliation_ids, | |
| 24 const std::set<std::string>& device_affiliation_ids, | |
| 25 const std::string& email, | |
| 26 const std::string& enterprise_domain); | |
| 27 | |
| 28 } // namespace chromeos | |
| 29 | |
| 30 #endif // CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_ | |
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