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1 // Copyright 2015 The Chromium Authors. All rights reserved. | |
2 // Use of this source code is governed by a BSD-style license that can be | |
3 // found in the LICENSE file. | |
4 | |
5 #ifndef CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_ | |
6 #define CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_ | |
7 | |
8 #include <set> | |
9 #include <string> | |
10 | |
11 namespace chromeos { | |
12 | |
13 typedef std::set<std::string> AffiliationIDSet; | |
14 | |
15 // Returns true if there is at least one common element in two sets. | |
16 // Complexity: O(n + m), where n - size of the first set, m - size of | |
17 // the second set. | |
18 bool HaveCommonElement(const std::set<std::string>& set1, | |
19 const std::set<std::string>& set2); | |
20 | |
21 // TODO(peletskyi): Remove email and enterprise domain after affiliation | |
22 // based implementation will fully work. http://crbug.com/515476 | |
23 // The function makes a decision if user with |user_affiliation_ids| and | |
24 // |email| is affiliated on the device with |device_affiliation_ids| and | |
25 // |enterprise_domain|. | |
26 bool IsUserAffiliated(const AffiliationIDSet& user_affiliation_ids, | |
27 const AffiliationIDSet& device_affiliation_ids, | |
28 const std::string& email, | |
29 const std::string& enterprise_domain); | |
30 | |
31 } // namespace chromeos | |
32 | |
33 #endif // CHROME_BROWSER_CHROMEOS_LOGIN_USERS_AFFILIATION_H_ | |
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