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1 # Copyright (c) 2012 The Chromium Authors. All rights reserved. | |
2 # Use of this source code is governed by a BSD-style license that can be | |
3 # found in the LICENSE file. | |
4 | |
5 """Gathers information about APKs.""" | |
6 | |
7 import logging | |
8 import os | |
9 import re | |
10 | |
11 # TODO(frankf): Move cmd_helper to utils. | |
12 from pylib import cmd_helper | |
13 | |
14 | |
15 def GetPackageNameForApk(apk_path): | |
16 """Returns the package name of this APK.""" | |
17 aapt_output = cmd_helper.GetCmdOutput( | |
18 ['aapt', 'dump', 'badging', apk_path]).split('\n') | |
19 package_name_re = re.compile(r'package: .*name=\'(\S*)\'') | |
20 for line in aapt_output: | |
21 m = package_name_re.match(line) | |
22 if m: | |
23 return m.group(1) | |
24 raise Exception('Failed to determine package name of %s' % apk_path) | |
25 | |
26 | |
27 class ApkInfo(object): | |
28 """Helper class for inspecting APKs.""" | |
29 | |
30 def __init__(self, apk_path): | |
31 if not os.path.exists(apk_path): | |
32 raise Exception('%s not found, please build it' % apk_path) | |
33 self._apk_path = apk_path | |
34 | |
35 def GetApkPath(self): | |
36 return self._apk_path | |
37 | |
38 def GetPackageName(self): | |
39 """Returns the package name of this APK.""" | |
40 return GetPackageNameForApk(self._apk_path) | |
41 | |
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