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Side by Side Diff: chrome/test/data/third_party/kraken/tests/kraken-1.1/ai-astar.js

Issue 11348021: Automate Kraken benchmark with Chrome Remote Control. (Closed) Base URL: svn://svn.chromium.org/chrome/trunk/src
Patch Set: Created 8 years, 1 month ago
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1 Array.prototype.each = function(f) {
2 if(!f.apply) return;
3 for(var i=0;i<this.length;i++) {
4 f.apply(this[i], [i, this]);
5 }
6 }
7 Array.prototype.findGraphNode = function(obj) {
8 for(var i=0;i<this.length;i++) {
9 if(this[i].pos == obj.pos) { return this[i]; }
10 }
11 return false;
12 };
13 Array.prototype.removeGraphNode = function(obj) {
14 for(var i=0;i<this.length;i++) {
15 if(this[i].pos == obj.pos) { this.splice(i,1); }
16 }
17 return false;
18 };
19
20 function createGraphSet(gridSize, wallFrequency) {
21 var graphSet = [];
22 for(var x=0;x<gridSize;x++) {
23 var row = [];
24 for(var y=0;y<gridSize;y++) {
25 // maybe set this node to be wall
26 var rand = Math.floor(Math.random()*(1/wallFrequency));
27 row.push(new GraphNode(x,y,(rand == 0)));
28 }
29 graphSet.push(row);
30 }
31 return graphSet;
32 }
33
34 // astar.js
35 // Implements the astar search algorithm in javascript
36
37 var astar = {
38 init: function(grid) {
39 for(var x = 0; x < grid.length; x++) {
40 for(var y = 0; y < grid[x].length; y++) {
41 grid[x][y].f = 0;
42 grid[x][y].g = 0;
43 grid[x][y].h = 0;
44 grid[x][y].parent = null;
45 }
46 }
47 },
48 search: function(grid, start, end) {
49 astar.init(grid);
50
51 var openList = [];
52 var closedList = [];
53 openList.push(start);
54
55 while(openList.length > 0) {
56
57 // Grab the lowest f(x) to process next
58 var lowInd = 0;
59 for(var i=0; i<openList.length; i++) {
60 if(openList[i].f < openList[lowInd].f) { lowInd = i; }
61 }
62 var currentNode = openList[lowInd];
63
64 // End case -- result has been found, return the traced path
65 if(currentNode.pos == end.pos) {
66 var curr = currentNode;
67 var ret = [];
68 while(curr.parent) {
69 ret.push(curr);
70 curr = curr.parent;
71 }
72 return ret.reverse();
73 }
74
75 // Normal case -- move currentNode from open to closed, process each of its neighbors
76 openList.removeGraphNode(currentNode);
77 closedList.push(currentNode);
78 var neighbors = astar.neighbors(grid, currentNode);
79
80 for(var j=0; j<neighbors.length;j++) {
81 var neighbor = neighbors[j];
82 if(closedList.findGraphNode(neighbor) || neighbor.isWall()) {
83 // not a valid node to process, skip to next neighbor
84 continue;
85 }
86
87 // g score is the shortest distance from start to current node, we need to check if
88 // the path we have arrived at this neighbor is the shortest o ne we have seen yet
89 var gScore = currentNode.g + 1; // 1 is the distance from a node to it's neighbor
90 var gScoreIsBest = false;
91
92
93 if(!openList.findGraphNode(neighbor)) {
94 // This the the first time we have arrived at this node, it must be the best
95 // Also, we need to take the h (heuristic) score since we ha ven't done so yet
96
97 gScoreIsBest = true;
98 neighbor.h = astar.heuristic(neighbor.pos, end.pos);
99 openList.push(neighbor);
100 }
101 else if(gScore < neighbor.g) {
102 // We have already seen the node, but last time it had a wor se g (distance from start)
103 gScoreIsBest = true;
104 }
105
106 if(gScoreIsBest) {
107 // Found an optimal (so far) path to this node. Store info on how we got here and
108 // just how good it really is...
109 neighbor.parent = currentNode;
110 neighbor.g = gScore;
111 neighbor.f = neighbor.g + neighbor.h;
112 }
113 }
114 }
115
116 // No result was found -- empty array signifies failure to find path
117 return [];
118 },
119 heuristic: function(pos0, pos1) {
120 // This is the Manhattan distance
121 var d1 = Math.abs (pos1.x - pos0.x);
122 var d2 = Math.abs (pos1.y - pos0.y);
123 return d1 + d2;
124 },
125 neighbors: function(grid, node) {
126 var ret = [];
127 var x = node.pos.x;
128 var y = node.pos.y;
129
130 if(grid[x-1] && grid[x-1][y]) {
131 ret.push(grid[x-1][y]);
132 }
133 if(grid[x+1] && grid[x+1][y]) {
134 ret.push(grid[x+1][y]);
135 }
136 if(grid[x][y-1] && grid[x][y-1]) {
137 ret.push(grid[x][y-1]);
138 }
139 if(grid[x][y+1] && grid[x][y+1]) {
140 ret.push(grid[x][y+1]);
141 }
142 return ret;
143 }
144 };
145
146 function go() {
147 path = astar.search(g1, start, end);
148 };
149
150 go();
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