AX presentation role should be inherited to its required owned elements.

Source/modules/accessibility/AXListBoxOption.cpp

 /*
  * Copyright (C) 2008 Apple Inc. All rights reserved.
  *
  * Redistribution and use in source and binary forms, with or without
  * modification, are permitted provided that the following conditions
  * are met:
  *
  * 1.  Redistributions of source code must retain the above copyright
  *     notice, this list of conditions and the following disclaimer.
  * 2.  Redistributions in binary form must reproduce the above copyright
@@ skipping 40 matching lines @@
 PassRefPtr<AXListBoxOption> AXListBoxOption::create(LayoutObject* layoutObject, AXObjectCacheImpl* axObjectCache)
 {
     return adoptRef(new AXListBoxOption(layoutObject, axObjectCache));
 }
 
 AccessibilityRole AXListBoxOption::roleValue() const
 {
     AccessibilityRole ariaRole = ariaRoleAttribute();
     if (ariaRole != UnknownRole)
         return ariaRole;
+
+    // Generally, the presentation role is handled in computeAccessibilityIsIgnored().
+    // In case of ListBoxOption, if it just marked as ignored in computeAccessibilityIsIgnored(),
+    // we can't see listboxoption on tree without any text.
+    // http://www.w3.org/TR/wai-aria/complete#presentation
+    // ARIA spec says that the presentation role causes a given element to be treated
+    // as having no role or to be removed from the accessibility tree, but does not cause the
+    // content contained within the element to be removed from the accessibility tree.
+    if (isParentPresentationRole())
+        return StaticTextRole;
+
     return ListBoxOptionRole;
 }
 
+bool AXListBoxOption::isParentPresentationRole() const
+{
+    AXObject* parent = parentObject();
+    if (!parent)
+        return false;
+
+    // The parent should be a listbox in order to be Required Owned Elements and
+    // have a presentation role.
+    Node* parentNode = parent->node();
+    if (isHTMLSelectElement(parentNode)) {
+        HTMLSelectElement& selectElement = toHTMLSelectElement(*parentNode);
+        if (selectElement.multiple() && isPresentationRole(parent))

[dmazzoni, 2015/03/31 16:35:23]

selectElement.multiple() isn't the same as a select element being a listbox vs a
menulist, because <select size=5> also looks like a listbox.

Also note that on some platforms the logic may be different - for example on
Android a select element is always a menu list.

The best check is to get the layoutObject and check layoutObject->isListBox()

[je_julie(Not used), 2015/04/01 12:51:28]

I updated it with layoutObject->isListBox().

+            return true;
+    }
+    return false;
+}
+
 bool AXListBoxOption::isEnabled() const
 {
     if (!node())
         return false;
 
     if (equalIgnoringCase(getAttribute(aria_disabledAttr), "true"))
         return false;
 
     if (toElement(node())->hasAttribute(disabledAttr))
         return false;
@@ skipping 95 matching lines @@
     unsigned length = listItems.size();
     for (unsigned i = 0; i < length; i++) {
         if (listItems[i] == node())
             return i;
     }
 
     return -1;
 }
 
 } // namespace blink