pathops version two

src/pathops/SkDQuadImplicit.cpp

Index: src/pathops/SkDQuadImplicit.cpp
diff --git a/src/pathops/SkDQuadImplicit.cpp b/src/pathops/SkDQuadImplicit.cpp
deleted file mode 100644
index f0f66d1a10a4f8f27d87c2d47705497248fcef25..0000000000000000000000000000000000000000
--- a/src/pathops/SkDQuadImplicit.cpp
+++ /dev/null
@@ -1,117 +0,0 @@
-/*
- * Copyright 2012 Google Inc.
- *
- * Use of this source code is governed by a BSD-style license that can be
- * found in the LICENSE file.
- */
-#include "SkDQuadImplicit.h"
-
-/* from http://tom.cs.byu.edu/~tom/papers/cvgip84.pdf 4.1
- *
- * This paper proves that Syvester's method can compute the implicit form of
- * the quadratic from the parameterized form.
- *
- * Given x = a*t*t + b*t + c  (the parameterized form)
- *       y = d*t*t + e*t + f
- *
- * we want to find an equation of the implicit form:
- *
- * A*x*x + B*x*y + C*y*y + D*x + E*y + F = 0
- *
- * The implicit form can be expressed as a 4x4 determinant, as shown.
- *
- * The resultant obtained by Syvester's method is
- *
- * |   a   b   (c - x)     0     |
- * |   0   a      b     (c - x)  |
- * |   d   e   (f - y)     0     |
- * |   0   d      e     (f - y)  |
- *
- * which expands to
- *
- * d*d*x*x + -2*a*d*x*y + a*a*y*y
- *         + (-2*c*d*d + b*e*d - a*e*e + 2*a*f*d)*x
- *         + (-2*f*a*a + e*b*a - d*b*b + 2*d*c*a)*y
- *         +
- * |   a   b   c   0   |
- * |   0   a   b   c   | == 0.
- * |   d   e   f   0   |
- * |   0   d   e   f   |
- *
- * Expanding the constant determinant results in
- *
- *   | a b c |     | b c 0 |
- * a*| e f 0 | + d*| a b c | ==
- *   | d e f |     | d e f |
- *
- * a*(a*f*f + c*e*e - c*f*d - b*e*f) + d*(b*b*f + c*c*d - c*a*f - c*e*b)
- *
- */
-
-// use the tricky arithmetic path, but leave the original to compare just in case
-static bool straight_forward = false;
-
-SkDQuadImplicit::SkDQuadImplicit(const SkDQuad& q) {
-    double a, b, c;
-    SkDQuad::SetABC(&q[0].fX, &a, &b, &c);
-    double d, e, f;
-    SkDQuad::SetABC(&q[0].fY, &d, &e, &f);
-    // compute the implicit coefficients
-    if (straight_forward) {  // 42 muls, 13 adds
-        fP[kXx_Coeff] = d * d;
-        fP[kXy_Coeff] = -2 * a * d;
-        fP[kYy_Coeff] = a * a;
-        fP[kX_Coeff] = -2*c*d*d + b*e*d - a*e*e + 2*a*f*d;
-        fP[kY_Coeff] = -2*f*a*a + e*b*a - d*b*b + 2*d*c*a;
-        fP[kC_Coeff] = a*(a*f*f + c*e*e - c*f*d - b*e*f)
-                   + d*(b*b*f + c*c*d - c*a*f - c*e*b);
-    } else {  // 26 muls, 11 adds
-        double aa = a * a;
-        double ad = a * d;
-        double dd = d * d;
-        fP[kXx_Coeff] = dd;
-        fP[kXy_Coeff] = -2 * ad;
-        fP[kYy_Coeff] = aa;
-        double be = b * e;
-        double bde = be * d;
-        double cdd = c * dd;
-        double ee = e * e;
-        fP[kX_Coeff] =  -2*cdd + bde - a*ee + 2*ad*f;
-        double aaf = aa * f;
-        double abe = a * be;
-        double ac = a * c;
-        double bb_2ac = b*b - 2*ac;
-        fP[kY_Coeff] = -2*aaf + abe - d*bb_2ac;
-        fP[kC_Coeff] = aaf*f + ac*ee + d*f*bb_2ac - abe*f + c*cdd - c*bde;
-    }
-}
-
- /* Given a pair of quadratics, determine their parametric coefficients.
-  * If the scaled coefficients are nearly equal, then the part of the quadratics
-  * may be coincident.
-  * OPTIMIZATION -- since comparison short-circuits on no match,
-  * lazily compute the coefficients, comparing the easiest to compute first.
-  * xx and yy first; then xy; and so on.
-  */
-bool SkDQuadImplicit::match(const SkDQuadImplicit& p2) const {
-    int first = 0;
-    for (int index = 0; index <= kC_Coeff; ++index) {
-        if (approximately_zero(fP[index]) && approximately_zero(p2.fP[index])) {
-            first += first == index;
-            continue;
-        }
-        if (first == index) {
-            continue;
-        }
-        if (!AlmostDequalUlps(fP[index] * p2.fP[first], fP[first] * p2.fP[index])) {
-            return false;
-        }
-    }
-    return true;
-}
-
-bool SkDQuadImplicit::Match(const SkDQuad& quad1, const SkDQuad& quad2) {
-    SkDQuadImplicit i1(quad1);  // a'xx , b'xy , c'yy , d'x , e'y , f
-    SkDQuadImplicit i2(quad2);
-    return i1.match(i2);
-}